Hello All,
I am trying to create a system and would like your views.
The idea is to bet every number until a repeat numbers shows up.
Below is test of ten million trials to see when a repeat occurs
on a double zero roulette table using a rand number generator.
Spin: Repeat occurred
1 : 0
2 : 263280
3 : 512608
4 : 729706
5 : 893503
6 : 1000672
7 : 1041586
8 : 1023667
9 : 955786
10 : 848365
11 : 718483
12 : 583348
13 : 450958
14 : 334641
15 : 237568
16 : 160392
17 : 103437
18 : 63660
19 : 37204
20 : 20665
21 : 10767
22 : 5381
23 : 2531
24 : 1067
25 : 444
26 : 173
27 : 78
28 : 26
29 : 3
30 : 0
31 : 0
32 : 0
33 : 0
34 : 0
35 : 0
36 : 0
37 : 0
38 : 0
39 : 0
40 : 0
41 : 0
42 : 0
43 : 0
44 : 0
45 : 0
46 : 0
47 : 0
48 : 0
49 : 0
So a repeat happens mostly between 6 and 8 spins.
Below is progression for 16 spins that shows how much to bet on each spin.
Place - Numbers - Profit - Bankroll Needed
$5 1 175 5
$3 2 97 11
$2 3 55 17
$2 4 47 25
$2 5 37 35
$2 6 25 47
$2 7 11 61
$3 8 23 85
$4 9 23 121
$6 10 35 181
$8 11 19 269
$12 12 19 413
$19 13 24 660
$32 14 44 1108
$56 15 68 1948
$103 16 112 3596
The above progression is based on a minimum inside bet of $5 and a max per number
bet of $200. The last bet in the progression places $103 on 16 numbers.
_______________________________________________________________
Which do you think would be better?
1. Wait until 15 numbers come up without a repeat,
then run the 16 spin progression and virtually guarantee a win by spin 31.
Or
2. Wait maybe 5 spins and start betting where you can win most of the time?
Consider that the progression can be reduced to 8 spins costing less than $100.
Do you have a better solution?
I look forward to reading your opinion!
Thank you,
FreeRoulette
Progression calculations from
nolinks://nolinks.loothog.com/Systems/followthewin.html (nolinks://nolinks.loothog.com/Systems/followthewin.html)
I like the simulation and the high peaks around 678.
The previous five numbers with no repeat would have the highest probability with one attack window of three attempts.