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ROULETTE

Started by RyanBuff, February 16, 2009, 09:11:01 PM

0 Members and 2 Guests are viewing this topic.

The Spiders Kiss

I am also only too willing to donate if the bet is found.We all know,i guess,someone touched by this awful disease.
My best wishes go to you Ryanbuff
The Spiders Kiss

f-rl-player

I;m sorry to hear about your health problem.
Good luck

sniper

Hello RyanBuff,

Sorry to hear about your case.I will pray for your health.
I am willing to take up your challenge and donate 20% of my winning towards your cause.
I will play full time if need arise.

Regards

sniper

Lanky

Hi Ryan.

Yes Mate sorry to hear of Your illness.
My Wife & I will pray for You.

I will try & explain what I see here in Your System Mate.
I am an old guy so take it easy on Me if I don't explain it right or I have the Bull by the Balls.

Mate from what I can see of Your System its an off shoot of what we call The LD = Last two dozens that came...... with a twist to it after WW comes You bet the furthest back Dozen for a win We would class that as an L.

I won't go through the A B C things as You know them already ....LOL

So if WW< > you bet the furthest back dozen to win .

So this pattern would be good for you then...

WW L<< in our terms>> would mean you have just won the last 3 bets.(nolinks) your way.
1x1 W+1
1x1 W+1
1 on the L to hit=+2+2 from the W's= +{4} profit.

So doing it My way it would be  wwL=+4 because you won the 3 bets.(nolinks) Your way
nolinksL=+2 because you won 3 out of 4 bets.(wwLw) your way
nolinkswL=Even because you won 3 out of 5 bets (wwLLw) your way.

So the problem would Come for you in these next examples.

ww (nolinks)  My way<< you won the 1st 2 bets & lost the next 3 (wwLLL) your way

So it would look like this My way with the Lw notations as I do.
w-1x1=+1
w-1x1=+2
w-bet 1 lose +1
w-bet 1 lose Even
w-bet 1 lose –1

It would look like this doing it Your way Mate ww(LLL)

So the wLw Lw Lw Lw LwLwL  pattern would really Kill you (My way)

Because the W would be the trigger for you to start betting and the L would lose on You....so In fact You would be losing 1x1 each time You bet on the Ls because Your betting for the L to be a W for You.

Your Friend .

Lanky.

Ps We have a group of a few people called

"For a Good Cause"

We are searching for the Consistent Bet so we too can support Charity from the Winnings.

Werdna

Hi Ryan

could you verify win3millions page 19 for us

regards

Werdna

WARRIOR


Marven

I just want to clarify something:

Ryan08 is NOT RyanBuff.

I don't know why Charles mentioned him, because Ryan08 has nothing to with all this.

With that said, and considering the silly mind-game that this is becoming, and the strange time-wasting acts of certain individuals, I am not going to make any more public posts regarding CEH-related topics.

All the best to everyone still wanting to discuss this.

Your friend, :)
Marven

WARRIOR

im with marven this this is gotten out of contoll all the  best TINO ps this is all begin to sound like the enymista saga where 2 italian guys started a rumor and snowball from there   mr ryan buff if this is all true be a man and come forward with it.

TwoCatSam

Is this it:

Once you get two differing dozens, you bet on both of them.  If you get a sleeping dozen for four spins, you bet on it.

Sam

ozshabs

Hi RyanBuff

Here is a sample of spin results from a live casino.


Dozen
A,A,B,B,C,C,B,C,C,C,C,C,C,B,B,B,C,A,A,C,C,A,B,B

How would you bet on the above sequence of dozens?

Cheers

alarian

If this claim would be true. Sorry if I'm a sceptic, I want to believe. It would also work with randomly generated numbers.

I'm going to bed now... This post will be 30+ pages tomorrow

dennisbelle

Ryanbluff,  In your original post why did you not bet for a change (C) on 13 because you had 4 decisions in the previous column
[smiley=3D-Smil/28_1_16.gif] 

RoulettePlayer

Dennisbelle,

Yes, bet the change there (@13). 

See posts 12 & 24.

RP

Lohnro

Quote from: RyanBuff on February 17, 2009, 08:11:48 PMexample-a,b,c,b,b,c,a,b,a,a,c,c,a,c,b  Notice this would be all wins=+11 once that c hit, we trapped c and b then since there would be four numbers (c,b,b,c) we would then bet and trap a until it hits or we go down three units (if we go down 3 units, we just wait for a and another dozen to hit again) I will keep giving you examples if it's helping. Keep up the good work.

[table=,]
1,,2,,3,,4,,5,
a,,c,,a,+2,c,+2,b,+2,
b,,b,,b,,c,,
,,b,+1,a,+1,a,+1,,
,,c,+1,a,+1,c,+1,[/table]

Hi Ryan,

Is this how the bets would be won? This comes to +12 so I must be doing something wrong?

RoulettePlayer

Lonhro,
I'm not answering for Ryan, but just repling with my 2 cents as I begin to understand this system.

1      2      3      4      5     
a      c      a +2  c +2 b +2 
b      b      b      c   
       b +1  a +1 a +1    
       c +1  a +1  c +1

In column 4, there would not be a bet in the third position (it's bold and blue) because only one group (c) has been established thus far, I think.

After the (a) appears, the next bet is correct in position #4 -
and then the change/switch to the top of column 5.    RP

RoulettePlayer

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