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Two unhit, side by side

Started by Mr J, August 26, 2009, 01:39:44 AM

0 Members and 1 Guest are viewing this topic.

Mr J

Sorry for another sidenote >> Of the 4 times I have played this, 3 of them I started at 7am, done at 3-4pm. I do not recommend playing at a busy table. The boredom of betting 33% of the spins will most likely over take you. I'm only being honest. Happy trails.  Ken

GTPfan

Mr J
   Can you tell me where to find the progression you use on this, I know i seen it somewhere but cant seem to find it now.

DOC

Hi Mr J

I would like to programme this and before I do would need to make sure I understand everything correctly.

1.  Arrive at the table and see the last number hit was 9.
2.  I wait 2 turns.  (No's hit are 0 and 28
3.  I now bet
4.  I choose any two numbers to bet, as long as they are side by side, and have not been hit already (so, 9, 0, 28 are out)
5.  I choose 18, 29
6.  I Lose.
7.  Wait 2 turns and do process 3-5 again except choosing a new set of numbers (or keep the same)
8.  What happens if after a number of losses the only numbers left to bet have adjacent numbers next to them that have already been hit? What is the decision then.

Look forward to doing this

DOC

Another quick question.
Please explain why you do this -[NOTE: An example, lets say the 24 and 13 are crossed off.  You must ALSO cross off the 36. ]

Mr J

The example I was giving was for a 00 wheel. I'll give you an example from a 0 wheel >>> Lets say the 19 and 21 are crossed off (hit), you can cross off the 4 if YOU WANT TO. You cant bet on the 4, I would cross it off just for the heck of it.





1.  Arrive at the table and see the last number hit was 9. >> I start right away, picking any two like 27, 13. You dont need to see a number before starting. 


2.  I wait 2 turns.  (No's hit are 0 and 28) >> hit AND cross them off.


3.  I now bet >> Correct


4.  I choose any two numbers to bet, as long as they are side by side, and have not been hit already (so, 9, 0, 28 are out) >> Correct but maybe not the 9 if you started right off.


5.  I choose 18, 29


6.  I Lose. >> cross off whatever hit EVEN on your betting spins!!


7.  Wait 2 turns and do process 3-5 again except choosing a new set of numbers (or keep the same) >> I would not choose the same, pick two others.


8.  What happens if after a number of losses the only numbers left to bet have adjacent numbers next to them that have already been hit? What is the decision then. >> Give me an example, I dont understand the question. NOTE: If you do get down to the LAST two unhit, no more skipping spins, stick to the same bet. Also, 3 is the same as 2 (like I already explained). Lets say the 20 14 31 are the only ones left unhit. NO MORE skipping spins. You alternate betting between the 14 20 and 14 31, back and fourth. HOPE a 14 hits!! Ken

Mr J

GTPfan >>> Here is the progression I use, it may be a bit steep for you but if anything, you can use different size units. 2 numbers, 1-56 $2,780 on a loss.  Remember, each bet I post, multiply by TWO (2 numbers). Ken

1- 14 $5, 15-23 $10, 24-29 $15, 30-33 $20, 34-37 $25, 38-40 $30, 41-42 $35,
43-44 $40, 45-46 $45, 47-48 $50, 49-50 $55, 51 $60, 52 $65, 53-54 $70,
55 $75, 56 $80.   

bernie

According to Turbo's website, the longest no show for a split is 249 times.  Okay, 2 numbers side by side on the wheel do not constitute a split however, I'm sure the outcome is somewhat similar.  I personally have seen a split not show for well over 100 spins. 

If I am right Mr J, you are only allowing for a 56 step progression? I cannot see how this could be sufficient given the above figures.  Am I missing something here?

Cheers


Mr J

"Am I missing something here?" >>> Yes, you didn't read it all.  AND was the split you are talking about, PRE-CHOSEN? In other words, when you sat down, you said the 19/20 split (whatever it was) will NOT show for over 100 spins and you were correct?  Ken

DOC

Quote from: DOC link=topic=11594. msg75288#msg75288 date=1251729337
Another quick question. 
Please explain why you do this -[NOTE: An example, lets say the 24 and 13 are crossed off.   You must ALSO cross off the 36.  ]


Please can you clarrify this point you made (using the single 0 wheel).  Or are you saying this because on the 00 wheel the 36 is between the 24 & 13 ?

Mr J

The example I was giving was for a 00 wheel. I'll give you an example from a 0 wheel >>> Lets say the 19 and 21 are crossed off (hit), you can cross off the 4 if YOU WANT TO. You cant bet on the 4, I would cross it off just for the heck of it. Ken

bernie

Mr J,

The point I was making was that your progression wouldn't work if data produced says that a split can go for 249 spins without hitting.  Please enlighten me.

I did try this method as your explaination and at the second attempt I was left with the numbers 14 and 31.  They could have remained dormamt for maybe another 200 spins.  Correct?

Cheers

Mr J

Can you answer this >>> was the split you are talking about, PRE-CHOSEN?   "They could have remained dormamt for maybe another 200 spins.  Correct?" >>> They might not hit for the next 942 spins. "I did try this method as your explaination and at the second attempt I was left with the numbers 14 and 31." >>> Just curious, what point were you at in YOUR progression when you were left with these 2 numbers? Ken

bernie

No, the split wasn't pre-chosen.  It came about by a process of elimination as per your instructions.



I honestly can't recall how far into the progression.  Maybe 20-30 spins at most.  It doesn't take long to to reach the final two side by side numbers if there aren't a lot of repeats and you are only betting every second spin.  I was crossing off numbers as you explained and ended up with numbers 14 and 31.  I wasn't lucky enough to hit any unhit numbers prior to ending up with the 14 and 31.



Cheers


DOC

How often do you double up.  I have had instances when the hit was after 7 bets, and then again after 50.  So is the betting progressive ie.  lose, then double, lose then double again etc. .


Mr J

Its not doubling up. Here is the progression I use, it may be a bit steep for you but if anything, you can use different size units. 2 numbers, 1-56 $2,780 on a loss.  Remember, each bet I post, multiply by TWO (2 numbers). Ken

1-14 $5, 15-23 $10, 24-29 $15, 30-33 $20, 34-37 $25, 38-40 $30, 41-42 $35,
43-44 $40, 45-46 $45, 47-48 $50, 49-50 $55, 51 $60, 52 $65, 53-54 $70,
55 $75, 56 $80.

Mr J

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