Two Hookers on a Street Method (roulette)

[Mr J]

Here we go, the rules >>> Every number will be tracked/recorded. I am looking for the furthest back unhit street BUT this street must be at least 27 spins back. If its not yet 27, we wait until it is. If that street hits before the 27, locate next street and wait again. Lets say its the 7 8 9 street. One of those numbers will hit. We'll say its the 8. We will be betting on the 7 and 9 with progression.

We again WAIT 7 more spins before betting, hoping a 7 or 9 does not hit. (the 8 hitting is ok) If a 7 or 9 does hit, start over. After any win, start over. This is a two number progression, 1-57 spins, $3,310 on a loss. The NET wins are VERY nice, only a few wins needed and you could go home for the day. In the last TWO years, I have very good results (actual play) using this but some portions of the waiting (and BR) are not for everyone. Ken

[Mr J]

If anyone has a shorter version of my progression, feel free to post it. This one is mine >>>

Remember, each bet is x2, we are betting 2 numbers every spin.

1-12 $5
13-21 $10
22-27 $15
28-31 $20
32-35 $25
36-38 $30
39-40 $35
41-42 $40
43-44 $45
45-46 $50
47-48 $55
49 $60
50 $65
51-52 $70
53 $75
54 $80
55 $85
56 $90
57 $100.....$3,310 total. Ken

[John Gold]

For anybody who wants a bit of harmless fun, I have converted Mr J's $3,310  57 step progression into a low roller 10p version which only requires 66.20 and still allows you to play all 57 steps. It could be good fun for someone who wants to play the live online casinos where low stakes are allowed.
Here are the steps.

spins 1-12. 10p x 2 = 20p x 12 = 2.40.
spins 13-21. 20p x 2 = 40p x 9 = 3.60.
spins 22-27. 30p x 2 = 60p x 6 = 3.60.
spins 28-31. 40p x 2 = 80p x 4 = 3.20.
spins 32-35. 50p x 2 = 1.00 x 4 = 4.00.
spins 36-38. 60p x 2 = 1.20 x 3 = 3.60.
spins 39-40. 70p x 2 = 1.40 x 2 = 2.80.
spins 41-42. 80p x 2 = 1.60 x 2 = 3.20.
spins 43-44. 90p x 2 = 1.80 x 2 = 3.60.
spins 45-46. 1.00 x 2 = 2.00 x 2 = 4.00.
spins 47-48. 1.10 x 2 = 2.20 x 2 = 4.40.
spin 49. 1.20 x 2 = 2.40 x 1 = 2.40.
spin 50. 1.30 x 2 = 2.60 x 1 = 2.60.
spins 51-52. 1.40 x 2 = 2.80 x 2 = 5.60.
spin 53. 1.50 x 2 = 3.00 x 1 = 3.00.
spin 54. 1.60 x 2 = 3.20 x 1 = 3.20.
spin 55. 1.70 x 2 = 3.40 x 1 = 3.40.
spin 56. 1.80 x 2 = 3.60 x 1 = 3.60.
spin 57. 2.00 x 2 = 4.00 x 1 = 4.00.
TOTAL BANKROLL = 66.20.

[Colin]

John again i like your 10p idea in your opinion whish is a good honest online casino allowing small bets.Thanks John Keep'er Lit Colin

[Mr J]

....but will your time be worth the smaller NET wins?  Ken

[John Gold]

Thanks Colin. Try 'prestige casino' They allow low stakes on roulette.

Mr J, According to my reckoning, your method has a 96% chance of success on any game. Using the low roller version gives a net win of 2.65 per game. So it would be possible to build up a healthy balance if the variance is on our side.

[RouletteFanatic]

Two numbers not hitting for 200 spins can occur. Likewise, your progession is up to 92 spins if im not wrong. therefore between 34 to 92 spins one of these two number has to hit.

Its a long progression, and there will be substantial short term gains but the losses outweights the wins as with all progressions.

[John Gold]

That's not always the case. For example a street could not hit for 60 spins and then you get a hit. So you wait the extra 7 spins and then start the 57 step progrssion. So here you are looking at 124 spins.
The only thing really cast in stone is the 57 steps. What happens before then could be a long or short wait.

[Mr J]

  You are correct JG, we are FIRST waiting for the street to hit. The other rule I hope everyone follows. In the BEGINNING for a street to even 'qualify'.....it must not of hit for 27 spins (furthest back)....THEN waiting for it to hit......then 7 skips on the other 2 numbers.....then a 57 step progression.  Ken

[Mr J]

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