Preface: A buddy of mine and I were trying to come up with ideas for 24 numbers. The research gave me the idea that wheel-order connectiveness may be in the linking of two certain dozens. (European Wheel)
Procedure: Consider 1st and 3rd, 2nd and 3rd dozens. When 1st dozen hits twice, play 2nd dozen & 3rd dozen. When 2nd dozen hits twice, play 1st dozen and 3rd dozen. Progression: 1,2--retrack or end session.
Test #1: Dublinbet Wheel #1: Unit size $10
...18,11,9
1st Dozen has hit twice, bet 2nd & 3rd Dozens: 30(win)+10
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...36,0,32,22,18
2nd Dozen has hit twice, bet 1st & 3rd Dozens: 4(win)+10
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End session
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Test #2: *BetVoyager RNG*: Unit size $10
...30,22,32,5,11
1st Dozen has hit twice, bet 2nd & 3rd Dozens: 27(win)+10
...32,35,18,18
2nd Dozen has hit twice, bet 1st & 3rd Dozens: 30(win)+10
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End session
Talking about European wheel-order connectivity with dozens, in my opinion have to play like this:
-when two 2nd doz. , bet 1 and 3 (same like proof), two prog. steeps 1/1, 2/2
- when two 3rd doz. , bet 1 and 2 , two prog. steeps 1/1, 2/2
- when two 1st doz. , bet - first steep(1/1) on 1 and 2 doz.
-second steep (2/2) on 1 and 3 doz.
Looking at eu. wheel will see:
A.
Clockwise
-from 29 . . . . to. . . . . 32 , only 3rd doz. + 1st doz. (and 0)
-from 25. . . . . to. . . . . . 30, 3rd doz. +1st doz. + only two nbrs. 2nd doz. (13,17)
So most 3rd +1st doz.
B.
Clockwise
-from 8. . . . . to. . . . 18 , 2nd doz. +1st doz. + only two nmbrs. 3rd doz. (33,31)
-from 15. . . to. . . 2 , only 2nd doz. + 1st doz.
So most 2nd doz. +1st dozen
1st doz. is common for A and B.
Maybe this will help us find a solution, an advantage.