A statistics question Ive been wondering

[Rebirtha]

So I am having a little troubule figuring out some statistics, should have paid more attention in school I guess. 

How do I go about testing the statistical probability of 37 numbers coming out without a repeater. .  What is the statistical probability that after 10 numbers of no repeats a repeating number will hit within the next 10.  If somebody could just show me the basic maths behind this I would be very grateful. 

[bombus]

Have a read through this for starters...

nolinks://vlsroulette.com/reference-area/roulette-probability-made-easier-t2193/

[Pactole]

Rebirtha,

I think this chart is
what you are looking for.

I hope it helps.

[Rebirtha]

what am I looking at? Why is 7 the max?

[Kelly]

You should find the calculation in the link above. 

What you are looking at is the highest probability for the first repeat to happen. The fist coloumn is the independent probability for a repeat in a certain spin and the second coloumn is the acumulated probability. Obviously when you get to spin 38 the probability for a repeat will then be 100%.

The table is from a math system designed be Pierre Basieux and is covered in his book "Die Zâhmung der Schwankungen"  the system is called "Die zufâllige Plein Wiederholung" (The random single number repeat). In his tests over 98.000 spins it was slightly positive but he emphasizes in the book that it probably will go into negative sooner or later, which i think later tests confimed. The system basicly operates in a window of 6 spins, where you are going for a repeat on the 7th spin if there also is a correlation of repeats and sleepers in the dozens in the same 6 spins. Can`t remember the exact rules for that but the dozens is in the measures to avoid betting all 6 non repeated numbers after 6 spins with no repeats. Sort of a filter, could also be the coloumns.

[Kelly]

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