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The Three winning systems I use

Started by roberge, December 08, 2009, 10:10:42 PM

0 Members and 1 Guest are viewing this topic.

roberge

Hello everyone, nice community u got here.     

Well I wanted to share some of the systems I use, since I didn't find them on ur website.     
First one:
(u all know it) the cubic Martingale 1,3,9,STOP  that I play on two dozens.     

Second one :  
I play 3 units on the low half (1-18) and 2 units on the high dozen (25-36)
If I lose I play 18 units on (1-18) and 12 units on (25-36)
If I lose again I play 108 units on (1-18) and 72 units on (25-36)
That way I have a 81% of wining  each streak, and 0.     677% of losing all 215 units.      (99.     323% chance of winning one of the three streaks).       

I like both of the above methods; they both work for daily petit cash (unless it's just one of those bad days).      But The problem is that when u lose it is very annoying to get ur chips back one by one.      So Im fed up with playing 'piquemouche' roulette methods .      I'm lately enjoying the success of the 3rd method.     

3rd method:
Well unlike the first method,  the mise is only on one dozen  using the 1,2,2,3,5,7,11,16,24,36,55,82 Fibonacci inspired serie, or another safer and way less boring exponential serie 1,2,4,6,9,STOP.       U get 3 units if u win ur first streak, 5 units if u win any of the following and risk only 22 units.     
Try also 1,2,4,6,STOP.       80% chance of winnings, 13 units risked.     
I played the 3rd methods three separate occasions, it never failed to impress me.     

hermes

Hi roberge, I never heard about the 3rd system (piquemouche) for one dozen/column? Could you be so kind end explain it a little in detail, especially what is the trigger to bet. We have here very good progressions for one D/C from cps10.
I can imagine if you lose 2 dozens progression it hurts a lot that's why I like the one dozen bets more.
Long time ago I played the second system a lot but I alternated to play the last 2 dozens + the corresponding double street, so it change to flexible system. If one D sleeps for 20 spins you are king of the game. The 19-24 #s come very often, those are Gamlet's numbers to bet! I saw one double street come 5 times in row! Or what about wait for one miss and then apply the 3 step progression? Then you lose only on Santa Clause days.
Thank you for 3rd system explanation and wish you creative touch.
Hermes

VLSroulette

Quote from: roberge on December 08, 2009, 10:10:42 PM
Hello everyone, nice community u got here.

Welcome Roberge, have a nice time around here.

Quote from: hermes on December 09, 2009, 12:45:25 AM
Hi roberge, I never heard about the 3rd system (piquemouche) for one dozen/column?

nolinks://vlsroulette.com/money-management/piquemouche-method/

:)

elmo

Maybe I am asking for trouble BUT..............
I looked over a weeks casino numbers and I would have won a fortune and never lost a game playing method 2 if I waited for a zero or 19/24 to appear and then use the three step progression.
I suppose for extra safety, I could wait for the zero or 19/24 to come out twice in a row but then I don't really think it would matter that much. If you are looking for the dinner money, this could be a nice relaxing way to play for an hour and gain some easy units.

thank you roberge

roberge

Hihihi, u completely misread my post.  It's the first method u have been using, read again, the 2nd method it is between the LOW HALF and the 3rd dozen (or alteration HIGH HALF  and 1st dozen)
low half: 1->18
High half: 19->36

The third method is not called piquemouche , I said the term piquemouche to make fun of boring methods.

try playing 1,2,2,3,5,7,11,16,24,36,55,82 on one dozen or collumn (but u r gonna  risk 244 units to get 1 or 2. .  the chance of loosing is 0. 67% but I've seen it happens a couple of time. )

A wiser way would be to  play 1,2,3,6,STOP on a alternate dozen or column (doesn't matter if it is fixed or alternate) and accept a loss every 5 or 6 play which is only of 13 units.

elmo

Another way to do it would be to leave out the street that has just appeared and also leave out the 34,35,36 street.

example. number 17 comes in.

you leave out the 16,17,18 street and also the 34,35,36 street leaving you betting streets 1,2,3,4,5,7,8,9,10,11.

I think this would work well most of the time.  As a safety measure I would wait for the same street to repeat twice and then bet on the next spin using the 3 step progression.

Don't ask me why  :-X

elmo

A few things to take into account using my modification.

1) If the 34,35,36 street appears, then you can not play after that hits twice because you will be left with 11 streets to play instead of 10.
2) If you start the 3 step progression and you hit a 34,35,36 street. QUIT THE PROGRESSION AND START OVER.

example.

12
12

so now you are playing streets 1,2,3,5,6,7,8,9,10,11.

36  QUIT PROGRESSION AND RESTART.


roberge

Interesting, it's true it is the same concept, But I do prefer mine cuz u risk less chips

Low Half.        .       .       .       .       .       .       .       .       .      3rd Dozen
.       .       .       .      3.       .       .       .       .       .       .       .       .       .   2.       .       .       .       
.       .       .       .      18.       .       .       .       .       .       .       .       .       18.       .       .       .       
.       .       .       .      108.       .       .       .       .       .       .       .       .     72.       .       .       
total unit risked = 215

urs start with a minimum of 10 1$ chips :S (however u do win TWO chips)
can u play ur method with a maximum bet of 100$? what is the serie of the 3 step progression?

elmo

Hello Roberge,

I can see that your way is using less bankroll.

My 3 step progression would be as follows.

1) 10 streets x 1 = 10.  profit by 2 or lose 10.
2) 10 streets x 6 = 60. profit by 2 or lose 70.
3) 10 streets x 36 = 360. profit by 2 or lose 430.

Of course I have a few safety measures built in where you would maybe have to quit the progression at times on either the first or second attempt and swallow the loss and restart. If you lost all three steps, 430 is a lot of units to lose compared to 107. However with my modification you are winning 2 units every time you win. It is just a twist and I think it would be interesting to compare results on the 2 different methods over a long spin sample.

iboba

Why progress when it will evenly zig-zag and inevitebly balance itself
throughout 400 night spins,and you can end the play after any of these balanced situations
in plus..............................Iboba 8) 8)

elmo

I just went through a day of results from the spielbank casino (yesterday the 9th december) and my twist to Roberge's method had 14 bets which all won for a profit of +28. About half of them got to the second stage in the progression. Would I play this for real money? NO, there are too many streets to bet and to get the 28 profit took 200 spins. If I had to stop on part 2 of the progression where the 34,35,36 street came up and take a 70 unit loss on the chin, then it would take ages to recoup.
It is a bit like what somebody said somewhere else about running across the road in heavy traffic, sure you will get across many times but one day SPLAT! :skull:

I am not knocking Roberge's method because his way uses less bankroll and you bet more often and have no stoppages in the 3 step progression but I did notice in the same spin sample that it would have suffered a few losses. if you take a hit, you can't get the money back quickly and another quick loss would be a real blow to the bankroll.

elmo

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