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A TwoCat test of enrique's "Winning Edge"...........

Started by TwoCatSam, November 24, 2008, 03:55:08 AM

0 Members and 2 Guests are viewing this topic.

TwoCatSam


Worm

Wow sam you sure are the nr1 tester here on this forum!  ;)

sniper


TwoCatSam


enrique malou

Hello Sam. I was just looking at the video you made. There is some good news and bad news.  :)
The good news is the early spins that I was watching seemed to be working well however that is not the way I would play it.
Allow me to show you how I would have played.

36=6
--------

23=4   4   4   (1,2,3,5,6)

Because the 6 double street is missing and that is the one that seems to go missing for the longest time in all my tests and live play, then that is the one that I will play.

looking at the betting chart as follows

no 6 on a 1. bet 2,3,4 and 5
no 6 on a 2. bet 1,3,4 and 5
no 6 on a 3. bet 1,2,4 and 5
no 6 on a 4. bet 1,2,3 and 5
no 6 on a 5. bet 1,2,3 and 4

So my first bet because there is no 6 on a 4 would be to bet on 1,2,3 and 5.

06=1   1   3   (2,4,5,6)

So my second bet because there is no 6 on a 1 would be to bet on 2,3,4 and 5.

23=4   5   3   (1,2,6)

so my third bet because there is no 6 on a 4 would be to bet on 1,2,3 and 5.

06=1   1   3   (2,4,5,6)

So my fourth bet because there is no 6 on a 1 would be 2,3,4, and 5.

11=2   2   1   (3,4,5,6)

so my fifth bet because there is no 6 on a 2 would be 1,3,4 and 5. So far I have won 4 consecutive bets and I am winning 8 chips.

22=4   3   2   (1,5,6)

So my sixth bet because there is no 6 on a 4 would be 1,2,3 and 5. So far I have won 5 consecutive bets and I am winning 10 chips.


enrique malou

I am betting the way I would play as I am watching the video. I have a really old computer and it is very slow  ;D

05=1   1   3   (2,4,5,6)   

so my seventh bet because there is no 6 on a 1 would be to bet on 2,3,4 and 5. So far so good and I am winning 12 chips.

enrique malou

27=5   3   4   (1,2,6) 

So my eigth bet because there is no 6 on a 5 would be to bet on 1,2,3 and 4. So that is 7 winning consecutive bets and I am up 14 chips.


02=1   3   2   (4,5,6)

That is now 8 winning bets on the trot. I am winning 16 chips.

so my 9th bet because there is no 6 on a 1 would be to bet on 2,3,4 and 5.

enrique malou

36=6   1   5   (2,3,4)

So for me that is a loss and I stop betting. I have won 12 chips in total.

I am going to the casino this afternoon but will be back late this evening and will spend some time trying to explain it in a bit more detail and give another example.
Bearing in mind I can play this in my sleep now, maybe I did not put it over in as  easy a manner as I thought.

Also Sam I would like to thank you for making the video and spending the time to test it out. You put a lot of effort into working on peoples methods and you are to be congratulated.

regards

enrique.

enrique malou

Funny enough Sam, the way you played it did better in those spins than the way I would play :)
I never thought to play it like that but it could be worth a look.
Before the smoke started coming out of my pc it seemed like you had about 11 winners on the trot. I should put up the white flag.  Seriously though this is a good way to play and it does give you some really long winning streaks. When I get ahead a good few units I sometimes use a positive progression with it. then if your luck is in you can come away with a nice few units profit.

regards

enrique

madupz4

I tried searching this system but I couldn't find it?  Can someone post the link?

Thanks

mistarlupo


TwoCatSam

enrique

Thanks for you kind words.  I will now go back and print your instructions and study them.  I thought on the last group of instructions, you were just betting the missing d/s--all of them.

That is why I posted the video.  For instruction.

Sam

TwoCatSam

enrique

I fail to see what I'm doing differently than you.  Here is your post:



01=1   2   4   (3,5,6) I win again. my next bet is 2,3,4 and 5.

17=3   4   2   (1,5,6) I win again. my next bet is 1,2,4 and 5.

04=1   2   4   (3,5,6) I win again. my next bet is 2,3,4 and 5.

18=3   4   2   (1,5,6) I win again and now my total profit is up 14 chips. my next bet is 1,2,4 and 5.

04=1   2   4 (3,5,6) I win again. my next bet is 2,3,4 and 5.

20=4   5   3   (1,2,6) I win again. my next bet is 1,2,3, and 5.

32=6   2   2   (1,3,4,5) This is a loss and now I stop. the good news is that I made 16 chips profit very quickly.

Correct me if I'm wrong, but the blues are simply the double streets not included in the reds.  That is the way I played it.

Sam

TwoCatSam

Quoting you

02=1   3   2   (4,5,6).......the 6 d/s came making a winner.
36=6   1   5   (2,3,4).......the 3 d/s came making a winner.
3 d/s 3 3 4   (1,2,5,6)......the 6 d/s came again next spin, a winner.
6 d/s
So for me that is a loss and I stop betting. I have won 12 chips in total.

me now........

As I understand it, your last bet would be on the 2,3,4 and the 3 came.  How is that a loss?

enrique, I will post  trot of numbers with video and accompanying scanned chart so you can see my hand writing.  You may compare easier that way.

Sam

TwoCatSam


TwoCatSam

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