coding needed plz

[ikarianman]

the system works like this:
take  the  3 last colours sequence (example)
3rd spin R
2nd spin R
1st spin  b
     
r
r
  b 

now IF the next 2 colurs (that means 4th and 5th spin is B and R),bet black before the sixth spin against the 3rd event of the previous sequence)
so if we see this

?     ->6th spin bet black
r     ->5th spin                   ----------->2nd sequence
  b  ->4th spin
----
r    ->3rd spin     
r    ->2nd spin           ---------->1st sequence   
  b ->1st spin

if with the 6th spin the 3rd event of the 2nd sequence is the same as the 3rd event of the 1 st sequence we lose*,otherwise we win and search for the next sequence to shape (our first basic sequence and the next sequence with 1st and 2nd numbers SAME as the first sequence betting the 3rd event of 2nd sequence)

*if we lose our bet in the 3rd event of the second sequence,we bet(doubling bet) against the first event of the first or second sequence which are twins now.if we lose again we bet(doubling) against the 2nd event of 1st or 2nd sequence(its the same),if we lose again we double the bet and bet against the 3rd event.if we lose again it will look like this,we bet a last time against the 1 st event and we hope its quite impossible for the sequence to start over again because of randomness.


r
r             ->1st
  b
----------
r
r              ->2nd
  b
----------
r
r               ->3rd
  b

IF ANY ZERO COMES WE CANCELL THE PROCEDURE AND START OVER AGAIN.is it possible for this to be coded in RX?
THANKS

[MXkid77]

Have a look at the attached code below, open the code in RX and see if it is similar. This code bets patterns. You may be able to edit the spins and the patterns yourself.

All the best

[MXkid77]

-