I have been concentrating majority of my 'research' into even money methods of play
What if you could guarantee that an even money chance (red/black hi/lo even/odd) would appear in 12 spins, how would you play this. . . it could appear more than once in these 12 spins, but worst case is one time on spin 12
I am looking at waiting for it NOT to appear in first 6 spins and then playing Martingale on it. . . but the wait would be too long for just one bet.
It averages on spin 8 but has gone to spin 12 (tested over 10 000 spins) any more and its going to bust my 'bubble' and become another losing system. . .
Welcome to the forum Takur :thumbsup:
You could consider 'other' types of even-money bets other than the standard, it might help.
Obviously you have Red/Black, Odd/Even, High/Low (The standard three)
Here is a double street version: European Wheel: (A) 1st Dozen, 25-30 (B) 2nd Dozen, 31-36
American Wheel (although you can use this for European as well): (A) 1-6, 13-18, 31-36 (B) 7-12, 19-24, 25-30
And a Single Street version: (A) 1,2,3: 7,8,9: 16,17,18: 19,20,21: 25,26,27: 34,35,36
(B) 4,5,6: 10,11,12: 13,14,15: 22,23,24: 28,29,30: 31,32,33
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You could divide the wheel (wheel-order) in half starting from clockwise of zero: (European Wheel, for example)
(A): (0), 32,15,19,4,21,2,25,17,34,6,27,13,36,11,30,8,23,10
(B): 5,24,16,33,1,20,14,31,9,22,18,29,7,12,28,35,3,26
Hope this helps.
thanks - I have tried similar approach
but what I want to know is if there is any advantage in 'a guarantee' of getting at least one red in 12 spins of 11 blacks - this eliminates long streaks of 12+ even chances that can bust your bank roll if not following the table
there should be some betting approach to take advantage of this. . .
From my experience, 90% of the time there has been a hit in 12 spins. (Nothing is guaranteed in Roulette for the bettor, sorry).