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4Selecta system - the sequel

Started by Arteinvivo, January 18, 2009, 07:51:40 PM

0 Members and 2 Guests are viewing this topic.

Arteinvivo

I took the liberty to open this thread in order to deepen our understanding of this system developped by Mr Chips.

Part 1 - SELECTIVE SPINS
 
The 4Selecta system requires streets to be set out as follows :
 
The Lower Group (LG)
-----------------
1, 2, 3
10,11,12
19,20,21
28,29,30
 
The Middle Group (MG)
-----------------
4, 5, 6
13,14,15
22,23,24
31,32,33
 
The Higher Group (HG)
-----------------
7, 8, 9
16,17,18
25,26,27
34,35,36
 
I will use Spielbank-Wiesbaden 17.7.08 Table 3 as it is very instructive.
 
The first few spins are as follows :
 
9
30
34
----
12
5
20
----
13
7
9
----
26
6
32
----
4
15
21
31
----
22
36
16
----
10
1
1
16
24
----
26
7
19
24
----
2
13
18
----
 
The lines have separated the spins into SECTIONS. Each Section must have 3 Groups. A COMPLETE (C) Section for example will contain a representative from each Group e.g.

2 LG
13 MG
18 HG
----
 
Unfortunately random numbers will not oblige and always produce a Complete section and therefore it will be necessary to have 3 Groups as follows :
 
9 HG
30 LG
34 HG
----
 
As long as a Section contains 3 Groups two HG and one LG qualifies as a Section.
 
12 LG
5 MG
20 LG
----
Two LG and one MG qualify.
 
13 MG
7 HG
9 HG
----
26 HG
6 MG
32 MG
----
4 MG
15 MG
21 LG
31 MG
----
Here there are two MG then LG and finally MG. There can only be one representative from each Group, therefore 4 MG and 15 MG count as one representative from the M Group.
 
10 LG
1 LG
1 LG
16 HG
24 MG
----
 
10 LG, 1 LG, 1 LG, count as one representative from the L Group, followed by 16 HG and 24 MG to complete the Section.

Part 2  -  The 4 GROUPS
 
I will work through the Spielberg example then hopefully it will be clear how the system works.
 
Firstly we need a Table labelled as follows :
 
LG    MG    HG   C (Complete)
 
As the numbers come in we will also need to record them in their Groups as follows :
 
34, 9, 16, 18, 8, 26
 
20, 11, 28, 12, 30, 3,
1
 
32, 31, 24, 6, 13, 4,
5
 
The first Section starts :
 
9
30
34
----
 
We take the final number in each Section e.g. 34 and record it in the number Group and note the Table. In this case it came from an HG Section so we record it as follows :
 
LG MG HG  C
          1

The next Section  is :
 
12
5
20
----
This is an LG Section as two LG's and one MG are present.
We therefore record the number 20 in the number Group and note the Table
 
LG   MG   HG   C
1.             1
 
I have place a . by the 1 to denote that LG is the recent active Group and any action will come from the last Group to be noted if the Groups are equal.
 
At this stage we can turn our attention to the betting. The first Section was an HG, we would therefore want and expect the next Section to also be an HG, but that is impossible as there is no representative H Group in this next Section. If we had recorded an L or M number then we could place a bet.
 
12
5
?
----
 
13
7

I mentioned above that action would be taken by either a Group in the lead or if equal the recent active Group. You will see that there is no LG in this Section, therefore we go back to the last Group to be noted unless there is a Group in the lead. We will take the HG number 34 the only HG number available.
 
The bet lost as 9 came in. 9 will therefore join 34 in the number Group and 13, 7, 9 is an HG Section so the Table will look as follows :
 
LG   MG   HG   C
1              1
               2
 
The Table shows HG in the lead.
 
26
6
 
At this stage we want an HG Section, so the bet will be numbers 34 and 9 as they are the only HG numbers available to us.
 
The bet loses as 32 comes in.
 
The numbers available to us are :
 
34, 9
 
20
 
32

The Table still shows HG in the lead :
 
LG   MG   HG   C
1     1.   1
               2
 
4
15
21
 
There is no representative H Group and therefore the next action Group was MG as denoted by the . The bet will be number 32 as this is the only MG number available.
 
The bet loses, unfortunately the correct Group came in but not the available number 32
 
34, 9
 
20
 
32, 31
 
LG   MG   HG   C
1     1    1
      2.   2
 
22
36
 
The Table shows MG and HG equal, but MG is the action Group, therefore the bet will be 32 & 31
 
The bet loses and 16 came in and HG is now in the lead in the Table.
 
10
1
1
16
 
We want an HG number to come in and numbers 34, 9, 16 are available.
 
The bet loses and 24 came in and this is the first Complete Section.

At this stage I will do a recap and show the Table as follows :
 
LG   MG   HG   C
1     1    1    1
      2    2
           3
 
Number Group
 
34, 9, 16
 
20
 
32, 31, 24
 
 
26
7
19

As HG is still in the lead the bet is 34, 9, 16
 
The bet loses and 24 comes in. As 24 has appeared again it now becomes a two unit bet and is noted [24]
 
2
13
 
There is no HG representative therefore the next action Group is C and the bet will therefore be 34, 9, 16
 
The bet loses and 18 came in. HG and C have 3 entries each in the Table, but C is the active Group.
 
8
13
 
The bet will be 20 an LG is wanted for the C Group.
 
The bet loses and 11 came in.
 
7
10
 
An MG is wanted and numbers 32, 31, [24] are available
 
The bet loses and 6 comes in. It was an MG, so the the C Group is now in the lead.
 
17
13
 
An LG is wanted and numbers 20 & 11 are available.
 
The bet loses and 28 came in. It was an LG and increases the C Group to 6 in the Table.
 
0
14
12
 
The zero is ignored and an HG is wanted and numbers 34, 9, 16, 18 are available.
 
16 wins and the previous losses are cancelled out and there is a profit of + 10 units.
 
A recap of the Table and Group numbers is as follows :
 
34, 9, [16], 18
 
20, 11, 28
 
32, 31, [24], 6
 
LG   MG   HG   C
1     1    1   1
      2    2  (2)
           3   3
               4
               5
               6
              (7)
 
29
8
12
----
6
5
3
9
----
 
51 spins profit + 36 units
 
0
35
15
30
----
1
35
13
----
4
12
3
----
12
30
6
4
----
20
35
13
----
 
68 spins profit + 44 units
 
2
3
27
5
----
22
4
2
3
----
13
8
3
----
 
79 spins profit + 95 units
 
3
34
13
----
 
82 spins profit + 158 units
 
14
6
3
8
----
14
10
26
----
1
27
30
----
22
19
1
----
13
6
24
35
13
----
11
11
3
29
36
30
----
26
31
3
----
 
109 spins profit + 203 units
 
Number Group
 
34, [9], [16], 18, 8, 26
 
20, 11, 28, 12, [[30]], [[[3]]]
 
32,31,[24], 6, [[[13]]], 4
5
 
LG   MG     HG    C
1     1      1    1
2     2      2   (2)
3     3      3    3
4     4           4
5                 5
6                 6
7                (7)
                 (8)
                  9
                  10
                 (11)
                  12
                 (13)
                 (14)
                  15
                  16
                 (17)

Part 3 - FURTHER EXPLANATIONS AND GUIDE LINES
 
After a few tests I have got a fair idea of how the system handles and works out. I would recommend an exit around 150 spins at the latest, most times it will be earlier. At around 100 spins if the session is losing at that point and very few hits have taken place seriously consider exiting at the first opportunity within the -50 unit range. So far the system has presented me with the opportunity to exit within or about - 50 units. I haven't as yet experienced a bad session !
 
A difficult decision is when you get say + 100 units at around 50 to 75 spins, whether to exit or not. I think with practice the decision may become easier, it is not an easy decision.
 
There are some amazing Group trends and on the occasions when say there are 3 equally continuous Groups this could well lead to a loss.
 
Further tests will decide if this system continues to make good profits in the long term.
 
If you have any queries or suggestions I will be happy to answer and respond to them
 
Mr Chips

Arteinvivo

First question...

How do we really qualify a section ?

It's a bit ambiguous, specially when he writes:

1) Each Section must have 3 Groups.
2) A COMPLETE (C) Section for example will contain a representative from each Group e.g.
3) Unfortunately random numbers will not oblige and always produce a Complete section

Up to this point this is understandable but...

4) it will be necessary to have 3 Groups as follows:
 
As long as a Section contains 3 Groups two HG and one LG qualifies as a Section.
 
12 LG
5 MG
20 LG
---

2 HG and 1 LG qualifies as a section

9 HG
30 LG
34 HG
----

This part is not clear. I see 2 groups not 3.

Later on, we have this:

4 MG
15 MG
21 LG
31 MG
---

or

10 LG
1 LG
1 LG
16 HG
24 MG <-- why this extra number ???

What difference between this:

10 LG
1 LG
1 LG
16 HG

and that...

9 HG
30 LG
34 HG
----

In both cases, we have 2 groups. Why do we need this extra number 24 MG to qualify this section ?


TwoCatSam

Arte

This is the hardest part of the system to understand.  I can explain it in my own words as I spent hours studying it.

To say it briefly, as long as your first two are different:

HG
LG
..........you have a bet on whichever Section is leading.  Here you could need an HG, an LG or MG depending on what you wanted to come.

When you have this:

HG
HG
LG......you toss out the first HG and you really have

HG
LG......

If another HG comes you have

HG
LG
HG.......which, you're right, is only two groups. 

At first I fought against this like I did winkel's "non-crossing crossing".  Finally, on both systems, I just gave up and accepted the way they said to do it.

Hope this helps.

Sam

Arteinvivo

QuoteTo say it briefly, as long as your first two are different

I can accept and understand that. So if the first two are different then the next spin whatever it is (if it's not a zero) will complete the section, right ? But to be considered really complete (C) a section needs to have 3 different groups in it, right ?

So in a sense, there are incomplete sections which are made of two groups but in a sense they are considered complete and there are also complete sections of three different groups which are considered the top we can have in terms of completeness. Is that correct ?  :'(

Arteinvivo

To have a section complete we need to count 1,2,3 but we don't increase the count until we have seen two different groups.

If we have this:

LG
LG
LG
LG
LG

We are still at count 1 since we have not seen two different groups.

When this occurs...

LG
LG
LG
LG
LG
MG

Then the count goes up to 2 and whatever follows will bring the count to 3.

It could be this...

LG
LG
LG
LG
LG
MG
MG

or that...

LG
LG
LG
LG
LG
MG
HG

Correct ?

The Spiders Kiss


The Spiders Kiss

LG
LG
LG
LG
LG
MG
MG
will give a middle group

LG
LG
LG
LG
LG
MG
HG
will give you a C group

TSK

TwoCatSam

So in a sense, there are incomplete sections which are made of two groups but in a sense they are considered complete and there are also complete sections of three different groups which are considered the top we can have in terms of completeness. Is that correct ? 


Correct.  I came to look at it like this:  When the last two Groups to come are different, the next Group--no matter what--makes a Section.

A Low Section could be

LG
MG
LG

or

LG
HG
LG

or

HG
LG
LG

or

MG
LG
LG

The Section is simple whatever the dominant Group happens to be unless it is a Complete Section.  Then there is always one of each.

LG
MG
HG.......in any order.

TSK,

Do you agree with this?

Arte,

Thanks for taking an interest in this.

Sam


The Spiders Kiss

Hi Sam
Yes I agree totally.
Nice to see an interest in 4selecta again.Not enough people gave it a chance cos of communication problems I think.But,in my opinion,its well worth a study and a try.
TSK

dennisbelle

LG   MG   HG   C
1     1    1      1
       2    2    (2)
            3      3
                   4
                   5
                   6
                  (7)

In this table why is the 2 in ( )? 

[smiley=3D-Smil/36_1_14.gif]

TwoCatSam


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