Jish & Keels system

[Jish]

What do you mean +3?

Wait for 8, then 3rd step of progression

[betatester]

Hello Jish & keel.
Hello Forum.
I think that i didn't understand exactly what are you two doing.
Could you put in black over white. Please.

In the meanwhile, as i didn't understand how to select the 8 beatable streets with all this letters, i figure out a way to track your ideas.

I can easily set a excel sheet (controlling only one set of 12 numbers, the normal ones) and know in each spin, which were the 4 last spun streets.

Something like that:

Nº   #   Street   L1   L2   L3   L4         
1   0   0            
2   13   5   0         
3   1   1   5   0      
4   5   2   1   5   0   
5   5   2   2   1   5   0    (no 4 diff streets)
6   33   11   2   1   5   0    (no 4 diff streets)
7   35   12   11   2   1   5   +
8   35   12   12   11   2   1   - (1)
9   2   1   12   11   2   1   - (2)
10   33   11   1   12   11   2   - (3)
11   20   7   11   1   12   2   +
12   4   2   7   11   1   12   +
13   15   5   2   7   11   1   +
14   17   6   5   2   7   11   +
15   30   10   6   5   2   7   +
16   6   2   10   6   5   2   - (1)
17   32   11   2   10   6   5   +
18   16   6   11   2   10   6   - (1)
19   1   1   6   11   2   10   +
20   31   11   1   6   11   2   - (1)
21   28   10   11   1   6   2   +
22   25   9   10   11   1   6   +
23   3   1   9   10   11   1   - (1)
24   19   7   1   9   10   11   +
25   34   12   7   1   9   10   +
26   0   0   12   7   1   9   -
27   14   5   12   7   1   9   +
....
....


Then I can control if the actual street for the actual spin was in the last 4 spuned.
If I find that it was is a (-) sign. If not is a (+)

Then it suffices to keep tracking the size of each (negative) strike, and wait "how many times" it can reach (1, 2, 3, 4, 5, 6, 7, or greater).
But i don't if this way is exactely as you do with the letters (hijk)

The last thing I've understand of your system is that you wait for "n" -I've signs (if this selection method fits your ideas), and then go with a progression.

You wrote:

"I am finding plenty of opportunities of 7. Obviously, if the streak ends after 8, you won't be on it, but so what.  Another 7 in a row is right around the corner.  I believe the hit rate is very good.

1 unit per 8 street after 7 misses in a row
3 units per 8 street after 9 misses in a row
9 units per 8 street after 11 () misses in a row.......if lose STOP chasing"

Here the data: (I'm using the same set as per another system in another thread, anyway...)
Those are the results for 14.637 spins

1   2258
2   722
3   263
4   101
5   38
6   10
7   2 <<
8   2 *
9   0 *
10   1 *
11   0
12   0

2 times you hit at first. +2 units
2 times in 2 step. + 2 units
0 times i 3third step. 0 units
You lost once your progression : -104 units.

That's a poor performance...

But i'think that you must explain if that way of selecting (non in the last 4 different streets spuned) is correct or you use antother approach.

Thanks a lot.

Betatester.

[keel44]

Your way of tracking is very much the same as my way of tracking.  I find mine easier.  You just use paper and pen with mine and track as you go.  The letters just identify the street.  Always count back the previous 4 different letters.  I find more opportunities using this tracking method.  7, 8, 9 in a row are fairly common.  5 in a row happens a lot.  Maybe the first leg of the progression should start with 5 in a row-----skip 1 -----then 7-----skip1------- then 9------ then 11


If the streak ends when your not on it.  Wait for another.

[Jish]

OK betatester & keel,
in the real wheel data I have the maximum for 12 numbers was 12 consecutive spins, so in my opinion we have 2 options IF you were using a 5 step progression, you have the *max output* which is using the maximums from the test, or the *safety progression* which keeps 2 spare progressions up the sleeve, I will abreviate them as MO&SP

1   105002
2   33705
3   10822
4   3721>>MO step 1
5   1115
6   387>>MO step 2
7   134
8   36 >>>MO step 3
9   10
10   6>>>>MO step 4
11   2
12   1>>>>>MO step 5

1   105002
2   33705
3   10822
4   3721
5   1115
6   387
7   134
8   36 >>>MO step 1
9   10
10   6>>>>MO step 2
11   2
12   1>>>>>MO step 3

Just what do you do when it wins inbetween???, it looks like you are making countermeasures for something that will inevitably lose- that is why the idea was to wait for 8 because it DIDNT lose && I still had 2 steps left in my progression for anything out of the ordinary

[Jish]

Payed this, won won, won, won, won, won... hit a set of 15, GAME, SET, MATCH

[Jish]

I did find a way to make this system win- just not the progression, if you can make the progression cost less and in 4 steps this will win, post here if you have ideas

1/3/9/27 = 39 per dozen so 78 for 2 dozens-

what i was working on was a big percentage of them were falling 6-9, not very many over this at all
my average was there was +9 bout 1 in 1000 spins

[Rebirtha]

Payed this, won won, won, won, won, won.  .  .   hit a set of 15, GAME, SET, MATCH

I´ve been playing a way where you go to a roulette table and record the last 10 numbers and cross off each street as it hits.   Usually after about 10 numbers have hit you have covered 8 streets leaving you a dozen left.   A 5 step progression could easily be set up for this.   I only play though if I have covered 8 streets with 10 or more spins.   Just what I´ve been doing, though not betting with real money, the problem with testing this is it takes a very long time to get reliable data without programming it.   

[Rebirtha]

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