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GHtidonTEoscImWh

Started by codegenic, October 22, 2008, 08:22:09 PM

0 Members and 1 Guest are viewing this topic.

ryan08

its because if you do get 36 unique numbers in 36 spins, in the next 18 spins at least 17 of those spins have to be a repeat and by magic you break even, i havent worked the maths out but codegenic knows her stuff and will have done her research and what she says will be reliable information, if your unsure how it will work i can only suggest you will have to work it out for yourself,

hope this helps
ryan

TwoCatSam

Kore

You're killing me!!  A pic of a roof for your avatar.  You must explain.  Welcome!

Sam

codegenic

Quote from: Kore on November 01, 2008, 06:13:44 PM
Hi Ryan,
yes, I agree it's almost impossible to have 36 spins without repeaters ;) I just take the same example Codegenic made.
Codegenic said it's pure math that also in the worst situation, we will break even on the 18th spin of the 2nd cycle, but I can't understand this part.

Hey Kore,

thank you and all for the interest in this system. The math behind this is quite simple. As with all bets, outside aswell as direct bets ( even bets excluded ). Take sixlines for example. They pay 6, so betting 1 sixline at a time while repeating last bets before you need to increase bets would be 1 +2 +3 = 3 times, if no hit then you raise bets. The same principal applies to betting streets, paying 12, so 1+2+3+4 = 4 times, before you need to increase, though you are 2 from betting 12 total. Now take direct bets.

1+2+3+4+5+6+7+8 = 8 bets. So in theory you would need a hit within 8 bets, hoping for a repeater. This happens more than ofte, but lets say it doesnt. Cycle to begins. 1+2+3+4+5+6+8 = 8 bets on 8 new numbers while betting the same previous numbers will give you the following: 8 bets first cycle, 8 bets + 8 bets 2 cycle, total numbers bet 24. The absence of repeaters in 16 spins, betting 16 numers, by which 8 of them are covered twice, is the dividend of 24/16 = 1.5. That is our success factor and the multiplyer by which we play to gain profit or break even if failed by cycle 2, or in other words, the difference  between the numbers hit and played without the missing ones. 3rd cycle is the break or make round. If you have been unlucky and 16 unique numbers have spun this round will make up for it, by setting a 2 win need. I will post a system soon that I spent nearly 6 months on. Its a private system that is a mix and sofar has been scrutinised with over 40.000 thousand ( forty ) spins, 20.000 ( twenty ) of them in real live play. Its somewhat based on this system, but nothing like it, since it involves a mix of bets and is controlled by math calcs for each spin. Each spin will be a new event thus requirerin a new strategy and bet size, but easy enough to figure out in the end. So far its flawed if played with a BR of less than 100 units, but if not, it has held up with profit.

See_Jerek

Quote from: codegenic on November 01, 2008, 07:05:14 PM
Quote from: Kore on November 01, 2008, 06:13:44 PM
Hi Ryan,
yes, I agree it's almost impossible to have 36 spins without repeaters ;) I just take the same example Codegenic made.
Codegenic said it's pure math that also in the worst situation, we will break even on the 18th spin of the 2nd cycle, but I can't understand this part.

Hey Kore,

thank you and all for the interest in this system. The math behind this is quite simple. As with all bets, outside aswell as direct bets ( even bets excluded ). Take sixlines for example. They pay 6, so betting 1 sixline at a time while repeating last bets before you need to increase bets would be 1 +2 +3 = 3 times, if no hit then you raise bets. The same principal applies to betting streets, paying 12, so 1+2+3+4 = 4 times, before you need to increase, though you are 2 from betting 12 total. Now take direct bets.

1+2+3+4+5+6+7+8 = 8 bets. So in theory you would need a hit within 8 bets, hoping for a repeater. This happens more than ofte, but lets say it doesnt. Cycle to begins. 1+2+3+4+5+6+8 = 8 bets on 8 new numbers while betting the same previous numbers will give you the following: 8 bets first cycle, 8 bets + 8 bets 2 cycle, total numbers bet 24. The absence of repeaters in 16 spins, betting 16 numers, by which 8 of them are covered twice, is the dividend of 24/16 = 1.5. That is our success factor and the multiplyer by which we play to gain profit or break even if failed by cycle 2, or in other words, the difference  between the numbers hit and played without the missing ones. 3rd cycle is the break or make round. If you have been unlucky and 16 unique numbers have spun this round will make up for it, by setting a 2 win need. I will post a system soon that I spent nearly 6 months on. Its a private system that is a mix and sofar has been scrutinised with over 40.000 thousand ( forty ) spins, 20.000 ( twenty ) of them in real live play. Its somewhat based on this system, but nothing like it, since it involves a mix of bets and is controlled by math calcs for each spin. Each spin will be a new event thus requirerin a new strategy and bet size, but easy enough to figure out in the end. So far its flawed if played with a BR of less than 100 units, but if not, it has held up with profit.


Really when will we see it? ;D

Kore

Hi Codegenic,
maybe I'm starting to understand something more... or maybe not: after 8th spin, do you double up the wager on the 8 numbers spun and go on wagering one unit on the next numbers as they hit, and so on and so on every 8 spins? You said after 16 spins without repeaters you have 24 bets, i.e. 16 number wich 8 of them covered twice.That's what I understand from your example, and if it's so, well I think this is the part I missed. I thought a number should be covered twice only after it hits for the second time.
Even if you don't do this after 8 spins, but it is how the system works on cycles of 36, doubling the wager after the 1st cycle is not the same than place a second unit if and only if a number shows for the 2nd time.

Uhmm, I'm confused. I think I need to reread all from the beginning. And sorry again for my bad english, I'm afraid all of you will have a bad headache after reading my posts.

Sam, I'd like a good analyst explains me why I've choose this avatar ;)

Tok2Dahand

 I have toyed with this on play money and it has only led to VERY big losses....   Im not sure that I'm doing it right...

Cycle 1 bet in 1 unit increments on each number that appears until you reach profit or 36 units....

Cycle 2 same as level 1 except 2 unit bets?  Do we keep the bets from round 1 on the table?

Cycle 3 same as level 1 except 4 unit bets?  Do we keep bets from round 1 and round two on the table?

I have tried it both ways (leaving the money on from last cycle and starting over from scratch on new cycle) and they both lead to extreme losses.....    easily munched up a 2k unit bank on fun money....

are you serious?

I just don't get it.....  especially the claim you make about being mathematically in profit after the 18th bet on the second cycle.... surely there is no need for a third cycle then....   

I think a proper example of your play is in order here...

I'm probably not the only person who seems to be missing the point here...


TwoCatSam

Kore

Have you ever had the shingles? 

Sam

Kore

Hi Tok2Dahand,
as I said before this system usually wins for me, but sometimes not. I'm confused too.

From what I get from Codegenic's explication, cycle 1 ends when you have a total bet of 36 units on the table, not when you are in profit of 36 units. And you double the wager in cycle 3 not in cycle 2 - am I wrong?

However... sorry, maybe I'm dumb but I still can't understand why we should eventually break even on 18th spin of cycle 2  :-\ When you start cycle 2, you start with 36 units on the table and many numbers are covered, but note that only numbers covered with 2 or more units give you a real profit. When a number covered with 1 unit hits, your profit is 36 minus the total wager, that is more than 36 in cycle 2. I see no guarantee to break even and I can't understand the thing of "pure math"... and yes I do the math. Where am I wrong? I'm missing something I suppose, maybe some mistake in the progression?

The way I'm playing it, I win much more sessions than I lose, but sometimes I can't recover the loss on the 18th spin of 2nd cycle nor at the end the 3rd one. It's not frequent but it happens sometime.

Sam: no, I never had the shingles, so there must be another explication for my avatar! And I had to ask to uncle Google to understand what the shingles are. I told my english is very bad, didn't I?

Carlitos

......... Codegenic, for Double streets 3 times repeater bett then you equalize. That is, play DS which has come up, play this again and the following DS that has spun and play these plus the 3th DS.






Carlitos  8)

TwoCatSam

Kore

Shingles are a disease of the skin.  Horrible!

I will continue to rack my brain for the logic behind your avatar!

Sam

Clothdog

Correction Sam. I'm a physician. It is a virus that manifests itself in painful lesions on the skin.
cd

TwoCatSam


Kore

I see. I'll have to change my avatar now, I think to herpes zoster every time I look at it!



MattyMattz

Code,

I'm really interested in this approach.  Have only just starting testing but looks promising to me. 
Look forward to chatting with you about it.

Cheers,
Matt

MattyMattz

Hey gang,

just finished my first short test of this idea, although I have no idea if I'm doing/playing it a'la Code.  But nonetheless, it show's promise.  After 500 spins, am up 800+units, with only 1 tough spot (drawdown of 590ish units).  The graph show's it all really.  In the table below I show my total BR and the spin I was on after a new high OR the end of the cycle.  I am restarting after reaching a new high.

[table=,]
BR,spin,cycle/notes
500,0,starting BR
508,8,
538,11,
568,14,
568,22,
585,32,
615,35,
648,37,
678,40,
704,44,
712,51,
745,53,
771,57,
645,93,36units on the board - starting cycle 2
735,132,72units on board - starting cycle 3
813,136,reset back to cycle 1
822,154,
843,159,
873,162,
881,169,
914,171,
716,206,36units on board - start cycle 2
956,231,reset back to cycle 1
964,238,
979,244,
987,251,
1022,252,
1025,282,
1033,298,
799,334,36units on board - start cycle 2
709,369,72units on board - start cycle 3
1129,409,reset to cycle 1 (I got up to 150units on the board. probably not correct style of play)
1155,413,
1217,441,
1243,445,
1249,456,
1249,464,
1255,475,
1288,477,
1321,479,
1329,486,
1344,492,
1397,505,
[/table]

Graph is below:

[attachimg=#1]

MattyMattz

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