NEW KEN'S SYSTEM

[New Ken]

New Ken here. Here's a silly little system I came up with: you record 38 spins, and play "against" columns, and "segments".

Divide board into four equal segments of 9 nos each: 1-9, 10-18, 19-27, 28-36.
Now let's say the following constitute the first nos spun (of the 38):

15
27
19
02
14
13
etc...

In new 38 spins I simply play "against" last 38. for example:

The first no. (15) belongs to segment 2 (10-18), and also column 3 (3, 6, 9, 12, etc). I leave out these nos (18 in all) and play the remaining nos (20 nos including zeros).


I'm betting that the same column and segment will not replay in the order of the previous 38 spins.

I'm aware that New Spin No. Three, for example, may contain a number from the column and/or segment of Previous Spin No. Three---when this occurs, I initiate a progression to reclaim loss.

What are the odds of spins 3, 4, 5, and 6 corresponding exactly with previous spins 3, 4, 5, etc?

Am I making any sense..?

[New Ken]

AH...made a little mistake with the posting there ---sorry!

[VLSroulette]

What mistake?, I see it properly placed at "full systems" section

Victor

[New Ken]

Thanks, Victor. I sent Two Cat Sam A BETTER explanation yesterday. Would love to see it tested...

[xman1970]

Hi New Ken Welcome aboard 

Hope you find what your looking for here [smiley=thumbsup.gif]

Any chance you could post your "BETTER explanation" here as 2Cats is out of the game for a while.....

After we are here to help.....

[cps10]

I would be happy to test if you would like for me to.

[New Ken]

($1,000 bankroll---winning $200 average every 38 spins)


Hey, guys, thanks for the kind offers, I appreciate them. I'm simply saying that in a series of 76 spins, the the second 38 spins will not be identical to the first 38.

Also, I have divided the numbers into 4 groups: 1 to 9.   10 to 18.   19 to 27.  28 to 36.

Now, if no. 8 plays in the first spin of the first 38---I do two things: I leave out the group that number belongs to (1 to 9)---and I leave out the column it belongs to also (2, 5, 8, 11, 14, etc).

I am now left with 20 numbers. I PLAY THESE NUMBERS IN THE FIRST SPIN OF THE NEW (or second) 38 SPINS.

WHY?
BECAUSE I BELIEVE THE SECOND 38 WILL NOT BE A CARBON COPY OF THE FIRST 38.

AND THAT CONSECUTIVE LOSSES WILL BE LIMITED, THEREBY ALLOWING FOR A REASONABLE RECOVERY (AND GAIN) PROGRESSION.
.
Here's an example (using Jim Kerr's actuals):




TESTING NEW KEN'S SYSTEM

From Jim Ferr's Actuals---(76 CONSECUTIVE SPINS)

8 17 36 33 27 6 2 20 25 31 32 36 20 26 9 00 4 30 20 24 11 33 5 15 16 6 3 16 00 16 32 36 33 1 30 32 4 13 10 34 17 30 21 36 18 29 14 19 21 18 16 26 3 17 11 26 32 1 5 11 21 35 32 26 4  8 29 28 19 27 1 25 18 0 31 17


TEST ---

* 1ST 38 spins:

8 17 36 33 27 6 2 20 25 31 32 36 20 26 9 00 4 30 20 24 11 33 5 15 16 6 3 16 00 16 32 36 33 1 30 32 4 13



* 2nd (OR FOLLOWING) 38 spins :

10 34 17 30 21 36 18 29 14 19 21 18 16 26 3 17 11 26 32 1 5 11

21 35 32 26 4  8 29 28 19 27 1 25 18 0 31 17

(First 38 spins on LEFT, new or following 38 spins on RIGHT)



8---10  W
17—34 W
36 –17 W
33—30 L
27—21 L
6---36  L
2---18  W
20—29 L
25—14 W
31—19 L
32—21 W
36—18 L
20—16 W
26—26 L
9---3   L
00—17 na *
4—11  W
30--26 W
20—32 L
24—1   W
11—5   L
33—11 W
5—21   W
15—35 W
16—32 W
6—26    W
3---4     L
16—8    W
00—29  na*
16—28  L
32—19  W
36—27  L
33—1    W
1—25    L
30—18  L
32—0    W
4—31    L
13—17  L


19 wins---17 losses (na* signifies: not playing against the zeros).
Nothing to write home about---we're playing 20 numbers, anyway.


BUT LOOK AT THE L'S---THREE LOSSES IN A ROW ONLY ONCE HERE, IN 38 SPINS.

So, I'm thinking, with a proper progression, one can recover or regain reasonably quickly.

What's a good progression for 20 numbers?

[New Ken]

And just to clear up---I do the same for each  following number as I did for the first ( the number 8 in the example).


FOR MADNESS' SAKE, HERE'S A $1,000 BANKROLL, 5-STEP PROGRESSION for my system! 

20 nos x 1=   20—win 15
20 nosx 2=    40—win 10
20 nosx 5=   100—win 15
20 nosx 12=  240—win 20
20 nosx 30=  600—win 50

Now, all someone has to do is show me SIX consecutive losses from actuals or RNG...but until then...!


UNTIL THEN I'M MAKING AVERAGE $200 EVERY 38 SPINS...!

[New Ken]

hey, cpsIO, the "explanation" of my system that was sent to Two Cat as a PM was meant for you!...I'm  still feeling my way around here...

[Natural9]

Need it better explained so some can run few tests on it

We need find out why it wins how it overcomes the edge will it win more that loses if you get that 6 losses in a row what to say it wont happenstraight away that could be a BR killer

Afteall this is roulette

[sean43]

First Spins      Second Spins   
31      1   W
11      0   L
10      14   W
20      9   W
33      4   W
35      11   W
34      1   W
10      29   W
4      29   W
23      25   W
1      2   L
13      29   W
11      14   W
25      12   W
7      26   W
13      5   W
26      24   W
1      31   W
36      24   W
16      36   W
24      7   W
18      24   L
26      9   W
29      0   L
25      16   W
22      36   W
22      16   L
33      16   W
31      21   W
34      28   L
20      16   L
29      21   W
30      29   L
15      25   W
28      29   L
10      33   W
7      25   W

Hope you understand, just done from RNG. I have played it different in the sense I bet against the corresponding dozen, seems to be going ok.

[Natural9]

you bet two dozens

[sean43]

Yes I have been betting on 2 Dozens, heres some more results following on from the first set. You could call this 2 sessions (3 sets of 37)

1   W      28   W
0   L      4   N/A
14   W      31   W
9   W      15   W
4   W      10   L
11   W      9   L
1   W      15   W
29   W      18   W
29   W      22   W
25   W      33   L
2   L      6   L
29   W      20   W
14   W      18   L
12   W      15   W
26   W      28   L
5   W      33   W
24   W      14   L
31   W      35   L
24   W      9   W
36   W      15   W
7   W      32   W
24   L      22   L
9   W      24   W
0   L      31   N/A
16   W      5   W
36   W      9   W
16   L      29   W
16   W      6   W
21   W      21   L
28   L      25   L
16   L      36   W
21   W      32   W
29   L      34   L
25   W      14   W
29   L      26   L
33   W      2   W
25   W      34   L

Only testing with 10p bets. So plus £4.90 in around 10 minutes, with pounds it would have been £49 with the maximum ever bet of £6.

[Natural9]

Yes I have been betting on 2 Dozens, heres some more results following on from the first set. You could call this 2 sessions (3 sets of 37)

1   W      28   W
0   L      4   N/A
14   W      31   W
9   W      15   W
4   W      10   L
11   W      9   L
1   W      15   W
29   W      18   W
29   W      22   W
25   W      33   L
2   L      6   L
29   W      20   W
14   W      18   L
12   W      15   W
26   W      28   L
5   W      33   W
24   W      14   L
31   W      35   L
24   W      9   W
36   W      15   W
7   W      32   W
24   L      22   L
9   W      24   W
0   L      31   N/A
16   W      5   W
36   W      9   W
16   L      29   W
16   W      6   W
21   W      21   L
28   L      25   L
16   L      36   W
21   W      32   W
29   L      34   L
25   W      14   W
29   L      26   L
33   W      2   W
25   W      34   L

Only testing with 10p bets. So plus £4.90 in around 10 minutes, with pounds it would have been £49 with the maximum ever bet of £6.

This seesion would have been a loser would it not unless you are  using some sort of progression i got the first session as winning 11 units or so


Regards Rodney

[sean43]

Hello,

Yes a progression on each dozen of 1,3,9,27. I think its best if you stop at the 2nd loss and start again.

[sean43]

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