Popular pages:

Roulette System

The Roulette Systems That Really Work

Roulette Computers

Hidden Electronics That Predict Spins

Roulette Strategy

Why Roulette Betting Strategies Lose

Roulette System

The Honest Live Online Roulette Casinos

Introduction to Markov Chains

Started by manistra, March 13, 2008, 02:06:09 PM

0 Members and 1 Guest are viewing this topic.

JLP

Hi Kawa,
Here is a little test of what you refer :

DUBLINBET TODAY
DEALER KATEJ

34
0
22
26
4
13
18
24
33
3
14
9
20
28
32
8
15
3     KATEB
23
36
3
10
34
20
19
   ------>bet 17 18 19 20 21 22
10
8
4
14
32
14
18   W
18   W  ---->bet 16 17 18 19 20
30
36
18   W
0
31
13
11
 ----->bet 9 10 11 12 13 14 15
22
1

JLP.-

JLP

DUBLINET
DEALER TOM

4
8
12
19
11
 --->bet 9 10 11 12 13 14
23
5
17
17  
5    
31
10   W
8  
 ---->bet 6 7 8 9 10 11 12
27
12  W
9    W
30  
23  
4    
19  
32
2
0
9
33
27  
29  
---->bet 25 26 27 28 29 30 31
24
20
33
31  W
----->bet 29 30 31 32 33 34 35
34  W
18  
4
2  
34  W
13
9
33  W
23
12
25  
10
25  
36
19
34  W
33  W
1    

Cheers,
JLP.-

kawa4711

Hi, JLP,

QuoteHi Kawa,  
Here is a little test of what you refer :

This idea is from @ winkel, a very active roulette specialist and he has detected a lot of roulette phenomens.

I wanted to bring his ideas to this forum so we can perhaps exchange our ideas between the two forums.

With best regards

and thanks to @Victor for his great ROULETTEFORUM

winkel

Hi @all,

my name is winkel and my friend kawa4711 directed me to this forum. As far as I read here  :thumbsup:

kawa brought my name in so I decided to register for being able to answer questions.

I hope my English is good enough to be understood.

@JLP
your first test is not following the rules.
1) Between the ignating numbers there has to be another number e.g. 6-x-8
2) this number x mustn´t touch the ingnating numbers: e.g. 6-7-8 = don´t play 6;8
3) there mustn´t be a touching number in this way: 32-33-x-34 = don´t play 33;34
4. only bet once the following Ball behind the trigger.

I give you the statistics i got so far.courtesy of @webpirat

Markov-Signal A0 means there were 5 numbers to play
A1 there were 6 numbers to play
A2 there were 7 numbers to play

As far as we can see is the bestsolution to play A0 once.



best regards
winkel

JLP

Hello Winkel,

Welcome to the Forum.

[highlight]@JLP
your first test is not following the rules.  
1) Between the ignating numbers there has to be another number e.g. 6-x-8
2) this number x mustn´t touch the ingnating numbers: e.g. 6-7-8 = don´t play 6;8
3) there mustn´t be a touching number in this way: 32-33-x-34 = don´t play 33;34
4. only bet once the following Ball behind the trigger.
[/highlight]

Now the rules are clear.
In the point 4 you bet only searching for 1 win and stop and wait for new instances??
According to the table statistics betting with 5 numbers is more profitable than the others (6 & 7 numbers).

Cheers,
JLP.-

winkel

Hi JLP,

[highlight]In the point 4 you bet only searching for 1 win and stop and wait for new instances?? [/highlight]

my friend @webpirat and I tested it in many ways to play but then stopped testing due to other ideas.
This way to bet ist the most effectiv. You can play all three selections but only once.
The statics show how long a winning number is missing. A progression is not recommended as you can count out.

add:
Tr.Z 1
Tr.Z 2
...

That means e.g.:  if we got 20.x.20 wie play 18.19.20.21.22
18 is Z1
19 is Z2
20 is Z3
21 is Z4
22 is Z5

the statistics shows how often the Center-Number is a winner or one of the neighbors

[highlight]According to the table statistics betting with 5 numbers is more profitable than the others (6 & 7 numbers). [/highlight]

simply:Yes but all three are winning over the distance. Sometimes the game gives no ignating numbers for a long time. so I play it just when I´m waiting for a trigger playing other strategies.

Hint:
As I Think there is another connection to the Fibonacci-Numbers. 0 1 1 2 3 5 8 13 21 ....
But it is not tested or finally discussed:

Coup/Numbers/Fibo
01 - 20
02 - xx - 0
03 - 21 - 1
04 - xx - 1
05 - xx - 2
06 - xx - 3
07 - xx -
08 - xx - 5
09 - xx -
10 - xx -
11 - xx - 8
...
17 - xx - 13

We would bet only the balls which compare to the Fibonacci-count
What is still to prove is: Where to start with the Fibo-Row?
Is the first ingnition-Number Fibo-count 0?
Is the dividing Number the Fibo-Count 0?
Is the second ignition-Number Fibo-Count 0?

Please know: Markov talks about a Hidden Markov Sequence (HMS) or Hidden Markov Movement (HMM)
That means: In the way the Generator gies us the numbers there is a hidden way to select the next number. this way we cannot identify. All we know is the result.
But this hidden way is more often repeating than all other ways when we find connecting numbers.

to play it on the mathematical order 0.1.2.3.4.....36 or on the order in the roulette 35.3.26.0.32.15.19....
makes no difference to the results.

lots of fun testing it 8-)

br
winkel


JLP

Hi All,

Here is another test at Dublinbet of the Markov chains using the rules proposed by Winkel.
As the opportunities to bet are limited with this method it must be used as a secondary system waiting for the right instances to make bets.



Cheers,
JLP.-

bloomone2002

It looks like the neighbors approach is a good supplement JLP.
The repeat approach you posted is great primary. I completed a test, where I play up to 3 repeats, then drop off the oldest one when the 4 repeats shows up, therefore, im only playing a max. of 6 numbers. See my results below:

39 spins, 213 u
JLP, what do you think about this approach?

Session 1 table 3 , 1/3/08
Neighbors

1,      2
2      4
3      13
4      35
5      25
6      16
7      12
8      9
9      19
10      20
11      5
12      9, bet 22, 31
13      17
14      6, start here, on 22, 31
15      24, (22, 31) +1                  -2
16      35, bet 3, 12 , (22, 31) +1      -4
17      22, (3,12,31)+1, h22            -8+36=28
18      31, (3,12)+1, h31            -3+36=33
19      33, (3,12)+1                  -2
20      2, bet (21, 25)+1, wait            -4
21      29,
22      18
23      23
24      29, bet (7,18) & 21,25
25      0, (7,18,21,25)      +1                  -8
27      30, (7,18,21,25)+1,                   -12
28      9, bet 22, 31 wait, (7,18,21,25)+1      -16
29      21, (7,18,21,22,25,31)+1, h21            -22+36= 14
30      6, (22,27,31,34)+1 bet, 27,34            -4
31      31, (22,27,31,34)+1, h31            -8+36= 28
32      31, (22,27,31,34)+1, h31            -4+36= 32      
33      0, (22,27,31,34)+1                  -4
34      26, (22,27,31,34)+1                  -8
35      19, (22,27,31,34)+1, bet 4,15            -12
36      15, (4,15,22,27,31,34)+1, h15            -18+36= 18
37      27, (4,15,22,27,31,34)+1, h27            -6+36= 30                  
38      35, (4,15, 27,34), bet 3,12            -6
39      4, (3,4,12,15,27,34)+1, h4            -6+36= 30

Summary: 28+33+14+28+32+18+30+30= 213
Bloom

JLP

QuoteIt looks like the neighbors approach is a good supplement JLP.
The repeat approach you posted is great primary. I completed a test, where I play up to 3 repeats, then drop off the oldest one when the 4 repeats shows up, therefore, im only playing a max. of 6 numbers. See my results below:

39 spins, 213 u
JLP, what do you think about this approach?

Session 1 table 3 , 1/3/08
Neighbors

1,      2
2      4
3      13
4      35
5      25
6      16
7      12
8      9
9      19
10      20
11      5
12      9, bet 22, 31
13      17
14      6, start here, on 22, 31
15      24, (22, 31) +1                  -2
16      35, bet 3, 12 , (22, 31) +1      -4
17      22, (3,12,31)+1, h22            -8+36=28
18      31, (3,12)+1, h31            -3+36=33
19      33, (3,12)+1                  -2
20      2, bet (21, 25)+1, wait            -4
21      29,
22      18
23      23
24      29, bet (7,18) & 21,25
25      0, (7,18,21,25)      +1                  -8
27      30, (7,18,21,25)+1,                   -12
28      9, bet 22, 31 wait, (7,18,21,25)+1      -16
29      21, (7,18,21,22,25,31)+1, h21            -22+36= 14
30      6, (22,27,31,34)+1 bet, 27,34            -4
31      31, (22,27,31,34)+1, h31            -8+36= 28
32      31, (22,27,31,34)+1, h31            -4+36= 32      
33      0, (22,27,31,34)+1                  -4
34      26, (22,27,31,34)+1                  -8
35      19, (22,27,31,34)+1, bet 4,15            -12
36      15, (4,15,22,27,31,34)+1, h15            -18+36= 18
37      27, (4,15,22,27,31,34)+1, h27            -6+36= 30                  
38      35, (4,15, 27,34), bet 3,12            -6
39      4, (3,4,12,15,27,34)+1, h4            -6+36= 30

Summary: 28+33+14+28+32+18+30+30= 213
Bloom

Hi Bloom,

Yes, it can be also playing more numbers neighbours as it appears (maybe till 6 numbers total).
Also Turbo Genious suggested in other new thread to search for a repetition of the repeater.
It can be too.
The first system posted by Edgardo I haven´t tested too much yet.

Cheers,
JLP.-

bloomone2002

JLP, thanks for the reply, I will look at the repitition of repeaters thread.

Look at the session below, I did a flatbet and a pluscoup, but could not recover. I ended the session at -56, because at the last spin, the neighbors were changing every spin but no matches:
There maybe something here to improve upon.

Continue & restart session on next spin

1,      2
2      28
3      15
4      15, bet 19, 32 wait
5      31
6      2, bet 21, 25, (19,21,25,32)+1 next spin
7      21, (19,21,25,32)+1, h21            -4+36= 32
8      3, (19,21,25,32)+1                  -4
9      13, (19,21,25,32)+1                  -8
10      17, (19,21,25,32)+1                  -12
11      15, (19,21,25,32)+1                  -16
12      18, (19,21,25,32)+1                  -20
13      24, (19,21,25,32)+1                  -24
14      6, (19,21,25,32)+1                  -28
15      29, (19,21,25,32)+1                  -32
16      11, (19,21,25,32)+1                  -36
17      14, (19,21,25,32)+1                  -40
18      2, (19,21,25,32)+1                  -44
19      23, (19,21,25,32)+1                   -48
20      33, (19,21,25,32)+1                  -52
21      14, (19,21,25,32)+1, bet 20, 31      -56
22      35, (19,20,21,25,31,32)+1            -62
23      29, (21,25,20,31)+1, bet 7, 18            -68
24      33, (20,31, 7,18)+1, bet 1,16            -74
25      9, (20,31, 7,18, 1,16)+1            -80
26      22, (20,31, 7,18, 1,16)+1            -86
27      18, (20,31, 7,18, 1,16)+1, h18      , bet 22,29      -92+36= -56 (add +1)
28      15, (7,18, 1,16, 22,29)+2, bet 19, 32      -68
29      21, (1,16, 22,29, 19,32)+2, bet 2,4      -80
30      15, (22,29, 19,32, 2,4)+2,            -92
31      7, (22,29, 19,32, 2,4)+2            -104
32      35, (22,29, 19,32, 2,4)+2 bet 3,12      -116
33      32, (19,32, 2,4, 3,12)+2, h32            -128+72= -56
Bloom

winkel

Hi bloom, hi JLP

the problem is simple to solve:
You want too much and that too fast.

1. don´t play, when the numbers are connected: e.g.
3      15
4      15, bet 19, 32

2. Do only play the following ball
win in ball 7, bet 2 win 36 = +34
loss in ball 22,23,24,25,29,33 bet 6x2=-12
all together +22

Don´t overact!

br
winkel

bloomone2002

QuoteHi bloom, hi JLP

the problem is simple to solve:
You want too much and that too fast.

1. don´t play, when the numbers are connected: e.g.
3      15
4      15, bet 19, 32

2. Do only play the following ball
win in ball 7, bet 2 win 36 = +34

loss in ball 22,23,24,25,29,33 bet 6x2=-12
all together +22
(I dont understand what you are doing in this section of the session. What numbers are you betting? and why? Please show the example in the workout)

Don´t overact!

br
winkel
thanks
Bloom

bloomone2002

JLP, i looked at the turbo's repeater thread, but I how do you know which number is gonna repeat?
Bloom

winkel

Hi bloom,

i took the the balls of your example. I just marked the numbers of the balls you played.
But would have played each selection only once.

So i would have played in 6 balls your selected numbers an would have lost.
One win and 6 losses is totally +22 Units

Hope you can get ist now.
Sorry for the misswriting

winkel


bloomone2002

QuoteHi bloom,

i took the the balls of your example. I just marked the numbers of the balls you played.
But would have played each selection only once.

So i would have played in 6 balls your selected numbers an would have lost.
One win and 6 losses is totally +22 Units

Hope you can get ist now.
Sorry for the misswriting

winkel


Ok, I understand. So, I only bet the 2 numbers for only the next spin.
Also, in JLP's sample session in reply #8, he would only have 2 hits(wins) if bet the same way.

Bloom

bloomone2002

-