single zero roulette
3 chips on 2,5,8,11
4 chips on 15,19,21,24
2 chips on 25,28,31,33
3 chips on the 2nd, and 3rd twelve
6 chips on first column of 12
4 chips on the second column of 12
2 chips on the third column of 12
Start with a bankroll of 500 chips. When your bankroll is somewhere between a thousand, and two thousand chips quit.
I took a quick look. Here is what you would win or lose on each number.
0. -54.
1. -36.
2. +66.
3. -48.
4. -36.
5. +66.
6. -48.
7. -36.
8. +66.
9. -48.
10. -36.
11. +66.
12. -48.
13. -27.
14. -33.
15. +105.
16. -27.
17. -33.
18. -39.
19. +117.
20. -33.
21. +105.
22. -27.
23. -33.
24. +105.
25. +45.
26. -33.
27. -39.
28. +45.
29. -33.
30. -39.
31. +45.
32. -33.
33. +33.
34. -27.
35. -33.
36. -39.
Only 12 numbers are winners and the average win is 69.
25 numbers are losers. I can't see the logic behind it. Would it not be better just to play a single dozen giving you the same chance of a win and limiting your exposure against the house. Playing this way described by Norman could have you losing a hell of a lot before you even hit one of your 12 winning numbers. You would need to be hitting some of the key numbers in quick succession to rack up some profits with this.
QeUSTION, HOW DO YOU USE CHIPS IN DOLLORS.whe inside bets have min. and outside bet have min..
Thanks a lot for the input. I bought roulette xtreme 2.0, and used to figure this out. When you run it a few times you can see what I'm talking about. Please try again with only a 500 chip bankroll. I sure hope this works. Please respond
how many time and spins have you ran this?
and for a double zero?