Hey all, been scheming up some progression ideas either for one dozen or even chances. Thought this up awhile ago but couldn't quite figure it, came back to it after remembering that if one uses the fibonacci sequence on ECs but instead of the regular way, going down an extra notch after a win, one can be even if winning exactly 33% of the time. This is because one level of the progression clears exactly 2 levels below it, (i.e. 3+5 = 8, if you win 8 you can go back to 3 which will then clear the prev 2 before that..) that becomes 33% as it's a 2:1 win. Anyways, it's still obviously way too dangerous a progression even with the no zero penny table I'm betting on. What I'm looking for is a much smaller change in amount but possibly with an exact level to go down to after a win? Maybe so one would only have to win 45% of all bets over time on an EC. I'd been experimenting winning the last level lost plus half of the next one down but wasn't sure how to progress down after that, tried a level inbetween the two but then what? Sorry my brains just been drained from a lot going on recently and I'm guessing maybe this would have to be a dynamic rather than a static/mechanical progression. Any thoughts? :thumbsup:
P.S. - Yes I DO realize how dangerous this could still be, EVEN with a penny/no zero table..
Thanks in advance!
- Matty B
Sorry just wanted to add, the two 'mechanical' progressions I'd been most interested in so far were either using one dozen and knocking out 3 levels, effectively only needing to win 25% of the time, or covering 5/12 streets, covering a bit over 41% of the board and clearing 2 levels effectively needing to win only 33% of the time to breakeven, both are about the same difference percentage-wise, but I'm hoping to find the least distance possible to still account for Standard Deviation, more of a grind if you will with less BR panic. Anyways.. :)