In some of my other posts, I talked about patterns and how they were generally not very useful. Although this system does make use of patterns, it is really more based on permutations of outcome possibilities.
Let me briefly explain. For the even chances, there are only three possibilities: Red (r), Black (b), and Zero (z) - Or, if you prefer, Odds, Evens, etc. For the sake of this system, I'm using only permutations based on the colors and on zero.
Because there are only three possibilities, in any three spins there are these possibilities:
1. rrr
2. rrb
3. rrz
4. rbr
5. rzr
6. rbb
7. rzb
8. rbz
9. rzz
10. bbb
11. bbr
12. bbz
13. brb
14. bzb
15. brr
16. bzr
17. brz
18. bzz
19. zzz
20. zzb
21. zzr
22. zbz
23. zrz
24. zbb
25. zrr
26. zrb
27. zbr
Now, by themselves, these permutations are not very useful. However, if we log 6 spins instead of three, we actually come up with 729 permutations - PATTERNS of six spins - all from three possible outcomes. For example, one pattern of six might go like this: bbrzbr
The Sixth Sense System
Rules:
1. A "Pattern" consists of 6 spins. The general odds of any full pattern repeating itself back to back is 1 in 4096, or a 0. 244% probability.
2. The odds of either color coming up on any given spin is 48. 648%. The odds of zero coming up on any given spin is 2. 702%.
3. There are a total of 729 possible patterns of six. Therefore, there is a 1 in 729 chance of any one pattern (consisting of six spins) showing, or a 0. 137% probability.
4. After a color has come up six times in a row in a pattern (i. e. , rrrrrr), there is a 127 in 128 chance that the next color will be the opposite - a 99. 218% probability.
5. After a color has come up six times in a row, there is a 1 in 128 chance that the next color will be the same - a 0. 781% probability, or, a less than 1% chance.
If you were to bet $67 using a limited martingale (and not factoring in the zero), that the pattern of six would not repeat itself, you would win 4095 times before you lost once. That means that the probability would bring a profit of $4095 - $63 = $4032 - Theoretically anyway - the real world is often much harsher!
Betting against a pattern requires betting on the colors using this progression: 2,5,11,24,51,108[229]. Also, the bet requires to bet on the zero at the same time using this progression: 1,1,1,2,3,4[13].
Because the odds are "general" (i. e, not a true 1 in 4096 chance because of the greater odds of the zero), it would be better to wait for a pattern of six to show that did not have any zeros in it, then bet against it using the betting progression above.
RECAP
1. Write down the last six spins: EG - RBRRBB. If a zero comes up, finish off the pattern up to the sixth spin, then start again.
2. Now bet against that pattern repeating itself. For example, on spin 7 you will bet that it will not be the same as spin 1. Spin 8 will not be the same as spin 2. Use the progression until you win.
3. Progression for the Even Chances: 2,5,11,24,51,108 (and 229, if you want to bet up to the seventh spin - not recommended).
4. Progression for the Zero: 1,1,1,2,3,6 (and 13, if you want to bet up to the seventh spin - not recommended).
FAQ'S
Q: How often have you played this system?
A: Actually, hardly at all. I just finished the probabilities and the permutations today, so I'm still obviously trying it out.
Q: Do you think this will be a long term winner?
A: I think we're all still waiting for that one to be invented. However, I will say about this system, that when the zeros come up, you will make a pretty decent amount of money.
Q: When do you quit or start over?
A: The stop loss is your sixth bet, win or lose (or seventh, depending on your pocketbook and your confidence). You will win more than you lose, especially when the zeros come into play. But when you lose - and you will lose, you will be trying to make up a total loss of $215.
When you win on say the third spin do you play out the last 3 spins without betting then chart the next 6 in a row
Dear Nullified,your probabilities calculations are ridiculos.
I'm afraid your math knowledge is very low.
All your statements are completely wrong!
Don't you think that Casinos should be aware of what you say since centuries?
I don't correct your post,because I'm afraid that you wouldn't understand.
Quote from: nullified on May 05, 2011, 01:41:59 AM
4. After a color has come up six times in a row in a pattern (I. e. , rrrrrr), there is a 127 in 128 chance that the next color will be the opposite - a 99. 218% probability.
5. After a color has come up six times in a row, there is a 1 in 128 chance that the next color will be the same - a 0. 781% probability, or, a less than 1% chance.
I'm afraid that your calculations are quite wrong here; the required chance is 18 in 37, NOT 127 in 128. Remember, each spin is independent of the last. :thumbsup:
Quote from: beretta28 on May 05, 2011, 03:19:31 AM
Dear Nullified,your probabilities calculations are ridiculos.
I'm afraid your math knowledge is very low.
All your statements are completely wrong!
Don't you think that Casinos should be aware of what you say since centuries?
I don't correct your post,because I'm afraid that you wouldn't understand.
How about for the rest of us seeing as you're so knowledgable?
Mike,more patient than me,gave the good answer|
I will not go into all the mathematazmics, but I think you would be better off constantly using the last pattern of six, but only betting as far as the first four steps of your progression - 2,5,11,24. If you haven't got a winner by then, dump the bet and start again with the current six spin pattern.
I would forget about the zero bets, and ignore it when building patterns.
Test it out and see?
:)
Quote from: Mike on May 05, 2011, 06:49:20 AM
I'm afraid that your calculations are quite wrong here; the required chance is 18 in 37, NOT 127 in 128. Remember, each spin is independent of the last. :thumbsup:
i think what nully meant was the odds of 7 reds in a row from start. Once 6 reds have appeared the odds of the next colour being red or black is exactly the same, but don't forget the zero of course.....
Calculating the probability of a single outcome for roulette is easy.
For the even chances (discounting zero for the moment) you have only two possibilities, red or black.
So the probability of any one coming up in one lone spin is 1 in 2 possibilities, or 1 in 2.
Calculating for two reds in two consecutive spins is not a 50/50 probability. Instead, you have a one in two chance on the first spin, and a 1 in two chance for the second spin. Therefore, the probability for two reds in a row is 1/2 times 1/2, which is 1/4. So the odds of getting two reds in a row is 25%.
The same calculation applies for seven reds in a row. There are seven spins, each one with a possibility of 1/2. So we multiply 1/2 by 1/2 seven times like: 1/2 x 1/2 x 1/2 x 1/2 x 1/2 x 1/2 x 1/2 = 1/128.
This is a very basic and easily solvable probability.
I think what most of you are looking at is on the seventh spin you have a 50/50 chance of betting correctly, which is true. What the probabilities are saying is that if this situation happens to you, most of the time (127 times out of 128) the "streak" will stop at six, and once it will go to seven.
Don't confuse your probabilities as a player with the probabilities of the game. The probability of the game producing seven colors in a row is always the same, 1 in 128. If you're betting after the sixth red that the next spin will not be red, your immediate chance is 50/50 that you're right. If you bet after every sixth run of colors, you will find yourself winning way more than 50/50.
If you are going to bash a person's system, don't just throw out the whole system because you cannot do simple math. I think most of us here have had to learn basic probability and statistics when trying to find an edge in playing the game. Personally I've been delving into chaos theory, fractals and number permutations to see what I could find.
Obviously, that's a lot further along than simple probability.
Quote from: Antibet on May 05, 2011, 04:02:30 PM
I think what nully meant was the odds of 7 reds in a row from start. Once 6 reds have appeared the odds of the next colour being red or black is exactly the same, but don't forget the zero of course.....
In all fairness nully, to say that after 6 or the same colour the very next one will be likely one colour than the other is
totally wrong that is what got people annoyed but the odds of seven of the same colour coming out one after the other
is a different thing. This forms part of my working :- write 7 e/cs down on paper ie red/black/odd /even/high/high/red,
no tracking at all, see how hard it is to get the next 7 spins to match (or not match if you like makes no difference) Most
of the time you will win but you will lose and the odds of the game will make you lose by the magrin of the house edge
eventually. If you really want to know how to beat roulette go to smartlive casino and look at their winners for
each recent month!
Quote from: nullified on May 05, 2011, 11:53:09 PM
Don't confuse your probabilities as a player with the probabilities of the game. The probability of the game producing seven colors in a row is always the same, 1 in 128. If you're betting after the sixth red that the next spin will not be red, your immediate chance is 50/50 that you're right. If you bet after every sixth run of colors, you will find yourself winning way more than 50/50.
If you are going to bash a person's system, don't just throw out the whole system because you cannot do simple math. I think most of us here have had to learn basic probability and statistics when trying to find an edge in playing the game. Personally I've been delving into chaos theory, fractals and number permutations to see what I could find.
This is what you wrote in your first post and it seems pretty unambiguous:
Quote4. After a color has come up six times in a row in a pattern (I. e. , rrrrrr), there is a 127 in 128 chance that the next color will be the opposite - a 99. 218% probability.
but now you seem to be saying that it wasn't what you meant after all. Never mind...
However, you are contradicting yourself by saying that:
1. If you're betting after the sixth red that the next spin will not be red, your immediate chance is 50/50 that you're right.
2. If you bet after every sixth run of colors, you will find yourself winning way more than 50/50.
In (1) you're saying the immediate chance is 50/50 (which is correct) but then in (2) you say you will win more than 50/50. :-\
In both cases, you have just seen a run of six colors and are betting on the seventh. Regardless of what color you bet on the 7th spin, the probability of success is the same.
Nullified,
I'm afraid you are a bit confused.
I don't repeat what Antibet and Mike said.They are definetly right.
If you have studied cahos theory,fractals,Bayes,Bernoulli etc and you are convinced that your statements are correct,I make the conclusion that the "schools"(University?) you have attended must be closed immediately(or you were a bad student!!)
Don't give illusions to young players,with your incredible and stupid theories.
Thanks
Quote from: Antibet on May 06, 2011, 02:00:26 AM
If you really want to know how to beat roulette go to smartlive casino and look at their winners for
each recent month!
What's the deal with these guys? How are there so many winners making so much money at roulette on smartlive?
Sam
Quote from: birdhands on May 06, 2011, 09:18:46 AM
What's the deal with these guys? How are there so many winners making so much money at roulette on smartlive?
Sam
Sam,
But....... Do we KNOW the losses of those "winners "??
BTW. In the END GAME the winner is always the casino.
Nathan Detroit
.
You guys are funny. Why don't you cut out the BS and anaylze the system? If you need to win by the sixth spin of this progression then you are going to lose 1 & 1/2 times per every 100 spins for a straight 50/50 coin flip.
This is obviously set up for the single zero wheel. So the odds to lose every 100 spins is actually 1.8 times. With each grand martingale typed bet you win 1 unit per spin. So you win 98 spins to a loss of 229 once or twice. But that is a very out of balanced result for a good system.
The single zero will hit 2.7 times for every 100 spins. What's strange is the 1,1,1,2,3,4 - (13) progression for the single zero. The grand Martingale is a waste of money. You would be far better off just playing the single zero with a progression. You need a far more balanced progression for that. You mathematically only get 2 or 3 zeros in each 100 spins. That zero can sleep for 200 spins. It's a worthless system. You can't find balance with a grand martingale that also pays for the bets on the zeros.
Okay, probability is obviously not some people's strong point. But I guess that's okay. Just a quick suggestion, if you're going to comment on my "poor math" you should check it out first. Go to iTunes University and download an introduction to Probability, or just Google it. You'll be better off for it, and it will certainly improve your roulette playing.
Enough said.
Now, I want to talk about why I've set this system up exactly the way it is. I've included a bet on the zero. And I've included a limited Martingale bet as well. Without these two features, this bet is absolutely useless and would be far too Mickey-Mouse to seriously consider.
So let me go through the math again.
What I am working on is the actual permutations of outcome possibilities for three spins, and then again for six spins. Have a look again at the list of 27 permutations at the top of this topic. The reason there are 27 permutations is because I have factored in the zero. But, if I factor out the zero, then there are only 8 permutation outcomes for three spins, instead of the 27 we have when we use the zero.
Here are the permutations for outcomes of three spins, without the zero:
1. rrr
2. rrb
3. rbr
4. rbb
5. bbb
6. bbr
7. brb
8. brr
If you think this is nit-picking, you're dead wrong. Factoring out the zero means there are now only 64 possible permutations for any run of six spins (8 X 8 = 64). However, if I leave in the zero and factor it into the permutations, I now have 27 X 27 = 729 outcome permutations, compared to only 64.
Why does this matter? First of all, because we are betting on the zero, so we enjoy a profit when it does hit. But more importantly, it means that there are 11 times more possible permutations that the wheel or the software can "choose" a pattern from, making it 11 times more likely that your particular pattern is not going to duplicate itself.
Now, why did I choose to use the limited Martingale instead of some other exotic betting scheme?
The answer is - because there's still too much damned chaos in roulette, even when we map out every possible permutation of six spins. Waiting for the exact same pattern to come up a second time, and then betting 1 unit that it won't start a third time would take far too much time, and you probably wouldn't make a lot of money that way.
I thought about logging all 729 permutations as they appear, and then start betting against each one separately after they come up a second time - but again, I don't want to be recording spins all night - I just want to play!
So, as much as we all hate the Martingale, I've used it here (with a stop loss) to save time, and because I figured it was the best way to profit quickly, with only a small chance of losing your $215 - (see attached).
An added bonus is that, by only "picking out" the patterns that don't have a zero, and betting against them is that, you are taking from a pool of 64 possible patterns (because there is not the zero) and then "opening up the full gamut" of 729 patterns for the roulette wheel to choose from in order to try and match it. In other words, your odds of winning just went up again, because there is now a 1 in 729 chance that the wheel will be able to exactly duplicate it's own pattern.
I understand that this method may still not make a lot of sense to some of you, unless you do the math. If you do the math, you'll see that this is actually a very good way to play - otherwise, you can start from the top post and study what I've written out.
By the way, I will post the whole 10 pages of permutations in the downloads section and as an attachment. The permutations are only for six spins, but maybe some of you can find an even more sure way of playing, using this tool.
The picture attachment shows the win/loss table for this bet.
Quote from: nullified on May 06, 2011, 09:26:26 PM
Okay, probability is obviously not some people's strong point. But I guess that's okay. Just a quick suggestion, if you're going to comment on my "poor math" you should check it out first. Go to iTunes University and download an introduction to Probability, or just Google it. You'll be better off for it, and it will certainly improve your roulette playing.
Enough said.
Now, I want to talk about why I've set this system up exactly the way it is. I've included a bet on the zero. And I've included a limited Martingale bet as well. Without these two features, this bet is absolutely useless and would be far too Mickey-Mouse to seriously consider.
So let me go through the math again.
What I am working on is the actual permutations of outcome possibilities for three spins, and then again for six spins. Have a look again at the list of 27 permutations at the top of this topic. The reason there are 27 permutations is because I have factored in the zero. But, if I factor out the zero, then there are only 8 permutation outcomes for three spins, instead of the 27 we have when we use the zero.
Here are the permutations for outcomes of three spins, without the zero:
1. rrr
2. rrb
3. rbr
4. rbb
5. bbb
6. bbr
7. brb
8. brr
If you think this is nit-picking, you're dead wrong. Factoring out the zero means there are now only 64 possible permutations for any run of six spins (8 X 8 = 64). However, if I leave in the zero and factor it into the permutations, I now have 27 X 27 = 729 outcome permutations, compared to only 64.
Why does this matter? First of all, because we are betting on the zero, so we enjoy a profit when it does hit. But more importantly, it means that there are 11 times more possible permutations that the wheel or the software can "choose" a pattern from, making it 11 times more likely that your particular pattern is not going to duplicate itself.
Now, why did I choose to use the limited Martingale instead of some other exotic betting scheme?
The answer is - because there's still too much damned chaos in roulette, even when we map out every possible permutation of six spins. Waiting for the exact same pattern to come up a second time, and then betting 1 unit that it won't start a third time would take far too much time, and you probably wouldn't make a lot of money that way.
I thought about logging all 729 permutations as they appear, and then start betting against each one separately after they come up a second time - but again, I don't want to be recording spins all night - I just want to play!
So, as much as we all hate the Martingale, I've used it here (with a stop loss) to save time, and because I figured it was the best way to profit quickly, with only a small chance of losing your $215.
An added bonus is that, by only "picking out" the patterns that don't have a zero, and betting against them is that, you are taking from a pool of 64 possible patterns (because there is not the zero) and then "opening up the full gamut" of 729 patterns for the roulette wheel to choose from in order to try and match it. In other words, your odds of winning just went up again, because there is now a 1 in 729 chance that the wheel will be able to exactly duplicate it's own pattern.
I understand that this method may still not make a lot of sense to some of you, unless you do the math. If you do the math, you'll see that this is actually a very good way to play - otherwise, you can start from the top post and study what I've written out.
By the way, I will post the whole 10 pages of permutations in the downloads section. The permutations are only for six spins, but maybe some of you can find an even more sure way of playing, using this tool.
You can't change the house edge, bettting zero or not makes no difference, you would need infinate bankroll and no
table limit to have the edge....... I tested this on random.org and of course you win some and lose some and the exact
margin of loss is the house edge, that said i am a fan of marty and i do like this type of system, so use now and then
and enjoy but as with all systems be prepared to lose long term?
QuoteYou can't change the house edge, bettting zero or not makes no difference, you would need infinate bankroll and no
table limit to have the edge....... I tested this on random.org and of course you win some and lose some and the exact
margin of loss is the house edge
Antibet,
Actually, I'm not even trying to beat the house edge. The fact that I'm betting on zero is only to increase my chances of the wheel NOT replicating it's own pattern. When I don't win on zero, I still win on my color, so that zero is absorbed in the bet, even if it doesn't show all day. It really doesn't matter if it shows or not. What does matter is that, by factoring in the zero, I have increased my chances of winning by more than 11 times.
Hope that clears things up.
Yep, the system sounds better without all the BS you spouted. I never originally commented on your patterns
etc as I saw through it. I often use some form of Marty in my strategy and I am using your six step progression without
the zero and treating 0 as a lost colour. The progression then becomes like a Grand Martingale which produces quick
profits.
Trouble is everybody here wants the holy grail and when a system such as yours which fails long term comes along
(again) we all get disappointed. Here's a thought.....
Why have we never seen 1 2 3 4 5 6 come up on the national lottery?
Answer is there are 13,000,000+ other combinations that haven't shown either.
The number 1 ball does not know it has number 1 on it. If you pick numbers 1 2 3 4 5 6 and they win though you will be
sharing your jackpot with 50,000 other people.
Keep up the good work Nulli
Once again Antibet is completly right.
Nullified
You have studied probabilities on Google,but I'm afraid that you have not understood them.
We have not discussed your theories since years in this Forum,because also the most novice players has well understood they are completly wrong.
I'm 52 and chemical engineer.
May I know your age and education?
Quote from: beretta28 on May 07, 2011, 06:40:50 AM
Once again Antibet is completly right.
Nullified
You have studied probabilities on Google,but I'm afraid that you have not understood them.
We have not discussed your theories since years in this Forum,because also the most novice players has well understood they are completly wrong.
I'm 52 and chemical engineer.
May I know your age and education?
You really have got patronisng people down to a fine art, Baretta well done.
I second Kagatori.
I see dead presidents.
Sorry. Couldn't resist.
Playing Martingale on the even chances the zero has a special roll.
You expect a 10 row shall not repeat.You bet Martingale.The zero means the row is repeating.It is a no-hit but the roulette gives bach the half of the bet.After 9 no-hits the row doesnot repeat.You win 1 unit.
H H 1 0
H H 2 0
L L 4 0
L L 8 0
L L 16 0
H H 32 0
L ZERO 64 32
H H 128 0
H H 256 0
H L 512 1024 hit
Total bet 1023 payout 64 units