Is there a system that ensures that at least 2 numbers will not come in every spin?
You can never "ensure" that even one number will not come the next spin
What kind of flamming question is that?
Insidebet
Quote from: insidebet on October 20, 2012, 06:15:27 PM
What kind of flamming question is that?
Insidebet
Thought it was just me!!
Hi, Klaki, I agree with 2kittySam ;-) If that would be the case we all would be millionairs. Could you explain what your after? Fill the whole board except 2 numbers? I've tried a reverse strategy once. Bet all numbers and remove the ones that hit. I does not work, but It's fun. With a bit of luck you can get some winnings. For a while...
3x14 +13 x2 = 68 = 1,6 / 0,4 Number 68 is the sum of cost of chips on the board.
It is 68 euros or 6.8 million (if the casino has a game for 0.1 euro). 1.6 / 0.4 was obtained when the amount of gain = 1.6 euro and 0.4 euro. (Play for less money in 0.1 euro).1.6 euro's gain when it gets some of the numbers: from 1 - 18 and 0.4 euro's gain when it gets some of the numbers from 25 - 36 and No. 23rd The arrows in the figure indicate how many tokens invested in tabli.Velicina chips depends on the casino.: 0.01, 0.05, 0.1 0.25, 0.5, 1, 2, 5 .. euro.
We now need to know which 2 - 6 Number will not come out in the next spin??? These same numbers will be pokriveno.Da Does anyone know of any forums or Software that can be based on 5-6 previous spins 5 -6 pre-determined number of fallen 2 -5 numbers that will not come out in the next spin? If they know every time to get. :dance1:
Help !
bye-bye Klaki !
Dear Klaki. The answer you seek is simple. Nobody will be able to predict witch number will not come up. To know that would be to know witch number will fall. It's as likely that the last number will repeat as for the sleeper of 460 spins to fall. There is no memory in the game and no fixed pattern. Maybe you could explain a bit better with an example what your game play is. If your only looking for certainties, I cannot help you and I predict lots of loss. That I am certain of. Wanna test? Play all streets (payout 11:1) and only leave one open. Rotate the open street. At random or follow a fixed pattern. So leave open street 1 then 2 then 3 etc. Another one I tried, leave open the one who sleeps the longest. You'll soon find out how hard it is to predict what not comes up.
Thanks for odgovoru.Moje question is based on a bunch of programs that I've seen
the netu.Jedan of them is not based on the last 5 numbers of fallen determined to go next ... Your response tells me that this program is just another scam.Rely on luck and how bude.A these systems we developed and mathematically correct, the only requirement is that not one of the free fall I brojeva.Razradio and systems of only two free number that are really good chance to win ...
The condition is not only a fall of two of the math does not lie, and the picture speaks for itself. I can send you an e mail if you leave it but I have parts in my big files ...
bye-bye Klaki !