New Ken here. Here's a silly little system I came up with: you record 38 spins, and play "against" columns, and "segments".
Divide board into four equal segments of 9 nos each: 1-9, 10-18, 19-27, 28-36.
Now let's say the following constitute the first nos spun (of the 38):
15
27
19
02
14
13
etc...
In new 38 spins I simply play "against" last 38. for example:
The first no. (15) belongs to segment 2 (10-18), and also column 3 (3, 6, 9, 12, etc). I leave out these nos (18 in all) and play the remaining nos (20 nos including zeros).
I'm betting that the same column and segment will not replay in the order of the previous 38 spins.
I'm aware that New Spin No. Three, for example, may contain a number from the column and/or segment of Previous Spin No. Three---when this occurs, I initiate a progression to reclaim loss.
What are the odds of spins 3, 4, 5, and 6 corresponding exactly with previous spins 3, 4, 5, etc?
Am I making any sense..?
AH...made a little mistake with the posting there :o :-\---sorry!
What mistake?, I see it properly placed at "full systems" section ;)
Victor
Thanks, Victor. I sent Two Cat Sam A BETTER explanation yesterday. Would love to see it tested...
Hi New Ken Welcome aboard ;)
Hope you find what your looking for here [smiley=thumbsup.gif]
Any chance you could post your "BETTER explanation" here as 2Cats is out of the game for a while.....
After we are here to help..... 8)
I would be happy to test if you would like for me to.
($1,000 bankroll---winning $200 average every 38 spins) :)
Hey, guys, thanks for the kind offers, I appreciate them. I'm simply saying that in a series of 76 spins, the the second 38 spins will not be identical to the first 38.
Also, I have divided the numbers into 4 groups: 1 to 9. 10 to 18. 19 to 27. 28 to 36.
Now, if no. 8 plays in the first spin of the first 38---I do two things: I leave out the group that number belongs to (1 to 9)---and I leave out the column it belongs to also (2, 5, 8, 11, 14, etc).
I am now left with 20 numbers. I PLAY THESE NUMBERS IN THE FIRST SPIN OF THE NEW (or second) 38 SPINS.
WHY?
BECAUSE I BELIEVE THE SECOND 38 WILL NOT BE A CARBON COPY OF THE FIRST 38.
AND THAT CONSECUTIVE LOSSES WILL BE LIMITED, THEREBY ALLOWING FOR A REASONABLE RECOVERY (AND GAIN) PROGRESSION.
.
Here's an example (using Jim Kerr's actuals):
TESTING NEW KEN'S SYSTEM
From Jim Ferr's Actuals---(76 CONSECUTIVE SPINS)
8 17 36 33 27 6 2 20 25 31 32 36 20 26 9 00 4 30 20 24 11 33 5 15 16 6 3 16 00 16 32 36 33 1 30 32 4 13 10 34 17 30 21 36 18 29 14 19 21 18 16 26 3 17 11 26 32 1 5 11 21 35 32 26 4 8 29 28 19 27 1 25 18 0 31 17
TEST ---
* 1ST 38 spins:
8 17 36 33 27 6 2 20 25 31 32 36 20 26 9 00 4 30 20 24 11 33 5 15 16 6 3 16 00 16 32 36 33 1 30 32 4 13
* 2nd (OR FOLLOWING) 38 spins :
10 34 17 30 21 36 18 29 14 19 21 18 16 26 3 17 11 26 32 1 5 11
21 35 32 26 4 8 29 28 19 27 1 25 18 0 31 17
(First 38 spins on LEFT, new or following 38 spins on RIGHT)
8---10 W
17—34 W
36 –17 W
33—30 L
27—21 L
6---36 L
2---18 W
20—29 L
25—14 W
31—19 L
32—21 W
36—18 L
20—16 W
26—26 L
9---3 L
00—17 na *
4—11 W
30--26 W
20—32 L
24—1 W
11—5 L
33—11 W
5—21 W
15—35 W
16—32 W
6—26 W
3---4 L
16—8 W
00—29 na*
16—28 L
32—19 W
36—27 L
33—1 W
1—25 L
30—18 L
32—0 W
4—31 L
13—17 L
19 wins---17 losses (na* signifies: not playing against the zeros).
Nothing to write home about---we're playing 20 numbers, anyway.
BUT LOOK AT THE L'S---THREE LOSSES IN A ROW ONLY ONCE HERE, IN 38 SPINS.
So, I'm thinking, with a proper progression, one can recover or regain reasonably quickly.
What's a good progression for 20 numbers?
And just to clear up---I do the same for each following number as I did for the first ( the number 8 in the example).
FOR MADNESS' SAKE, HERE'S A $1,000 BANKROLL, 5-STEP PROGRESSION for my system! ::) ;) ;)
20 nos x 1= 20—win 15
20 nosx 2= 40—win 10
20 nosx 5= 100—win 15
20 nosx 12= 240—win 20
20 nosx 30= 600—win 50
Now, all someone has to do is show me SIX consecutive losses from actuals or RNG...but until then...!
UNTIL THEN I'M MAKING AVERAGE $200 EVERY 38 SPINS...!
hey, cpsIO, the "explanation" of my system that was sent to Two Cat as a PM was meant for you!...I'm still feeling my way around here...
Need it better explained so some can run few tests on it
We need find out why it wins how it overcomes the edge will it win more that loses if you get that 6 losses in a row what to say it wont happenstraight away that could be a BR killer
Afteall this is roulette
First Spins Second Spins
31 1 W
11 0 L
10 14 W
20 9 W
33 4 W
35 11 W
34 1 W
10 29 W
4 29 W
23 25 W
1 2 L
13 29 W
11 14 W
25 12 W
7 26 W
13 5 W
26 24 W
1 31 W
36 24 W
16 36 W
24 7 W
18 24 L
26 9 W
29 0 L
25 16 W
22 36 W
22 16 L
33 16 W
31 21 W
34 28 L
20 16 L
29 21 W
30 29 L
15 25 W
28 29 L
10 33 W
7 25 W
Hope you understand, just done from RNG. I have played it different in the sense I bet against the corresponding dozen, seems to be going ok.
you bet two dozens
Yes I have been betting on 2 Dozens, heres some more results following on from the first set. You could call this 2 sessions (3 sets of 37)
1 W 28 W
0 L 4 N/A
14 W 31 W
9 W 15 W
4 W 10 L
11 W 9 L
1 W 15 W
29 W 18 W
29 W 22 W
25 W 33 L
2 L 6 L
29 W 20 W
14 W 18 L
12 W 15 W
26 W 28 L
5 W 33 W
24 W 14 L
31 W 35 L
24 W 9 W
36 W 15 W
7 W 32 W
24 L 22 L
9 W 24 W
0 L 31 N/A
16 W 5 W
36 W 9 W
16 L 29 W
16 W 6 W
21 W 21 L
28 L 25 L
16 L 36 W
21 W 32 W
29 L 34 L
25 W 14 W
29 L 26 L
33 W 2 W
25 W 34 L
Only testing with 10p bets. So plus £4.90 in around 10 minutes, with pounds it would have been £49 with the maximum ever bet of £6.
Quote from: sean43 on November 13, 2008, 09:38:53 PM
Yes I have been betting on 2 Dozens, heres some more results following on from the first set. You could call this 2 sessions (3 sets of 37)
1 W 28 W
0 L 4 N/A
14 W 31 W
9 W 15 W
4 W 10 L
11 W 9 L
1 W 15 W
29 W 18 W
29 W 22 W
25 W 33 L
2 L 6 L
29 W 20 W
14 W 18 L
12 W 15 W
26 W 28 L
5 W 33 W
24 W 14 L
31 W 35 L
24 W 9 W
36 W 15 W
7 W 32 W
24 L 22 L
9 W 24 W
0 L 31 N/A
16 W 5 W
36 W 9 W
16 L 29 W
16 W 6 W
21 W 21 L
28 L 25 L
16 L 36 W
21 W 32 W
29 L 34 L
25 W 14 W
29 L 26 L
33 W 2 W
25 W 34 L
Only testing with 10p bets. So plus £4.90 in around 10 minutes, with pounds it would have been £49 with the maximum ever bet of £6.
This seesion would have been a loser would it not unless you are using some sort of progression i got the first session as winning 11 units or so
Regards Rodney
Hello,
Yes a progression on each dozen of 1,3,9,27. I think its best if you stop at the 2nd loss and start again.
Quote from: sean43 on November 13, 2008, 09:52:52 PM
Hello,
Yes a progression on each dozen of 1,3,9,27. I think its best if you stop at the 2nd loss and start again.
Yeh Second loss might be ok
Ok I got you as usual we need ask the question how often will a progression lose and if it does lose can we recover will losses kill our BR
I mean one can just play LD that works quite wel ltoo just ask Lanky and Victor
Regards Rodney
Yea 2nd loss is going good so far, what do you mean by LD sorry? Heres some more
34 3 W
6 36 W
27 9 W
5 31 W
1 26 W
29 36 L
7 6 L
1 14 W
8 33 W
31 36 L
33 35 L
34 28 L
23 34 W
5 32 W
34 26 L
21 9 W
21 21 L
27 23 W
34 31 L
11 2 L
25 9 W
3 34 W
3 7 L
35 30 L
17 36 W
20 11 W
21 32 W
18 9 W
35 8 W
5 4 L
22 10 W
8 32 W
30 35 L
23 21 L
24 7 W
16 7 W
11 21 W
+23
I can guarantee you that there will be never carbon copy of 38 spins but I can guarantee you also that sometimes there will be a carbon copy of 10 spins even when you will bet 2 dozens against one. You can bet 10 spins against 10 spins like that:
10 Dozens vs 10 dozens x= loss
2 1
1 x 1
2 x 0
1 3
1 2
1 x 1
2 1
2 x 2
2 x 2
1 x 1
Good luck
Hermes
LD last dozen
Thanks for examining my system, guys.
Ok, first of all I'm not playing dozens. I'm playing 20 nos, and I always will be playing with the zeros (but if a zero appears in the first 38, I skip that particular spin). I'm playing four groups (see above), and the three columns. Every no. (except the zeros) belongs to a group and column.
I'm playing not only against the numbers ( and their groups, cols) of the first 38 spins---I'M PARTICULARLY PLAYING AGAINST THEIR ORDER OF APPEARANCE.
What are the odds of six consecutive number groups and cols REPLAYING IN THE EXACT ORDER AND POSITIONS of the previous 38 spins?
(I
..I will call each position in every 38 spins a "slot place".
So the first number of every 38 spins will be "Slot 01", followed by Slot 02, Slot 03, etc. down to Slot 38.
What are the odds of, say, slots 05, 06, 07, 08, 09, 10 carrying the same number groups and columns---in two consecutive 38 spins?
What do the math and probability gurus say on this, I'd like to hear.
New Ken 8) 8)
Thanks NEW KEN!
I will take a test really quick. Will report some later.
Hi NEW KEN,
Just did a test of 369 spins...unfortunately, I did find a bad streak...there was a 9-spin losing streak at one point. There were also 6 total losses of 5 spins within the group.
One thing I think would work would be to wait for a 5-spin loser. If it happened every 60 spins or so, then you are really going through one cycle before seeing it come up. That way, since the highest losses I have seen so far is 9, then you are looking at a 4-step progression MAX right now.
Just my two cents...I will continue to test more.
This batch:
369 spins, Hi: 16, Lo -2920, End -2872 (yes, I hit a loss right out of the gate).
Thanks, cps10---are you saying that a streak of nine consecutive spins from one 38 perfectly mirrored that of the previous? :o
Get back to you on that...
Here's a test using the same nos---but I'm only playing against the previous six spins.
Biggest losing streak is 4 losses!
TESTING NEW KEN'S (NEW?) SYSTEM
New approach---here I don't wait for 38 spins.
I am simply playing against the previous six spins.
From Jim Ferr's Actuals---(76 nos, consecutive spins)
8 17 36 33 27 6 2 20 25 31 32 36 20 26 9 00 4 30 20 24 11 33 5 15 16 6 3 16 00 16 32 36 33 1 30 32 4 13 10 34 17 30 21 36 18 29 14 19 21 18 16 26 3 17 11 26 32 1 5 11 21 35 32 26 4 8 29 28 19 27 1 25 18 0 31 17
Start:
8 17 36 33 27 6
2 20 25 31 32 36
L L W L W L
20 26 9 00 4 30
L L W W W L
20 24 11 33 5 15
L L W na* L L
16 6 3 16 00 16
W L W W W L
32 36 33 1 30 32
W L L L na* W
4 13 10 34 17 30
W W W L W L
21 36 18 29 14 19
W W L L L W
21 18 16 26 3 17
L L L L W W
11 26 32 1 5 11
W W W W L L
21 35 32 26 4 8
W L L W L L
29 28 19 27 1 25
W L W L L W
18 0 31 17
W W L W
Okay...that isn't bad either.
I will modify my most recent test for that. The most recent was for 392 spins:
Longest streak was 8.
Hi: 1,020
Lo: -3,252
End: -2,400
As you can see, it gets streaky.
Okay, modifiying it to the last 6 spins was a little better:
392 spins
Hi: +1081
Lo: -759
End: -287
Losses: 4
Long Streak: 9
They are huge Drawdowns not sure my stomach could handle that
TWO 4 STEP PROGRESSIONS FOR New Ken's Modified System
20 nos x 1= 20—win 15
20 nosx 2= 40—win 10
20 nosx 5= 100—win 15
20 nosx 12= 240—win 20
ABOVE PROGRESSION--$400
20 nosx 2= win 30
20 nosx 4= win 20
20 nosx 10= win 30
20 nosx 24= win 40
above progression---$800
Modified SyStem---$1,200 BANKROLL (---CATERS FOR 2 WIPEOUTS).
USING MY MODIFIED SYSTEM (PLAYING AGAINST LAST SIX SPINS), I WAIT FOR TWO Ls THEN BEGIN PLAYING.
TO LOSE 1ST $400 THERE MUST BE 6 Ls IN A ROW. (after 6Ls, I wait for entire series of losses to finish before beginning again)
TO LOSE next $800 THERE MUST BE ANOTHER 6 Ls IN A ROW. (after SECOND 6Ls THEN I'VE LOST)
ARE BOTH losses GOING TO HAPPEN regularly?
The testers are wonderful,--- but where are the math and probabilities people on this forum??
(USING SAME JIM FERR'S ACTUALS ABOVE, I WIN AVERAGE $110 ---PLAYING ELEVEN TIMES AFTER ELEVEN 2L'S---WITHOUT GOING INTO SECOND BANKROLL PROGRESSION)
SO, THERE.
HERE I GO AGAIN...
Using the same recorded 76 nos as before, I look for where the REPEAT nos EMANATED in the first 38 nos.
I decide the new repeat nos will emanate from elsewhere in the new string of 38 nos.
In the new 38, I will not play in those slot places where the first repeat nos emanated.
I stop after two hits (whether in profit or not).
double asterisks(**) shows where repeats emanated--single asterisks(*) show where hits occured
first 38 spins on left (L)---second 38 spins on right(R)
(L) (R)
8 10
17 34
36 ** 17 no play
33 ** 30 no play
27 21 **
6 ** 36 no play
2 18 **
20 ** 29 no play
25 14
31 19
32 ** 21 no play
36 * 18 *first hit (10x6units, 34x5, 21x4, 18x3, 14x2, 19x1 )
expense = 21 units
WIN 15
20 * 16
26 26
9 3
00 ** 17 no play
4 ** 11 no play
30 ** 26 no play
20 * 32
24 1
11 5
33 * 11
5 21 *second hit (10x14 u,
etc 34x13,21x12,18x11,14x10,19x9, 16x7, 26x6,3x5,32x4,1x3, 5x2,11x1
units expense overall =97 units
WIN $43 OVERALL-----23 SPINS, all flat bets, single units
wait for new 38 to complete, reset.
Now, I need a TESTER... :-\ ;)