Hello there. This is my first system posted here. ;)
It's very easy: have a look at 3 sections - Low, Med, High (1-12, 13-24, 25-36). Spin a wheel until one section/dozen come three times in a row.
For example you got: . . . , 2, 7, 11 - then you start betting at the two last sections with progression 2, 6 (first time 1 chip for Med and 1 chip for High, next 3 chips for Med and 3 chips for High). Results are really outstanding. I played it for few hours and made over 150 euro from intial only 20.
This system was inspired by RPro75 unique repeater systems. ;)
When you lose, simply start catching new 3 dozens in a row and play opposite to them.
You will have much greater results, when you play with next stages progression, but it is only recommended for people with much more money.
Check out the bet calculator, stakes are getting high here very quickly! I do not recommend to play more than 3rd stage. Enjoy!
Edit: when zero comes when catching, you'd better start again. When betting - raise bets (it comes very rarely when betting).
Edit 2: certainly, you can wait for 4 or 5 same dozens/sections in a row (and make bets higher), but it happens once for about 100-500 spins. Depends on randomness. ;)
Thanks for taking the time to write your system for us "ElAmigos" :good:
Amigos = Friends :)
Let's be friends around here then.
Victor
Quote from: VLSroulette link=topic=9694. msg60080#msg60080 date=1243375999
Thanks for taking the time to write your system for us "ElAmigos" :good:
Amigos = Friends :)
Let's be friends around here then.
Victor
Actually, my nick name comes from Amiga computer. I had one when I was in high school and school mates gave me this name. But your association is good anyway, thanks!
Welcome elamigos!
Couple questions - do you progress bets as you win or as you lose? Also, after you've had a dozen repeat 3 times do you play the same other 2 dozens until you lose or with each bet do you alternate and play the last 2 that did not hit. For example - Dozen 1 (Low) repeats 3 times so I play Dozen 2 & 3 (Med/High). Then Dozen 3 hits, I win. Do I continue to play Dozen 2 & 3 or do I now switch to Dozen 1 & 2 b/c those are the last 2 to not hit? ie. the Jump Dozens
Just wanted to clarify :good:
Quote from: celiza427 link=topic=9694. msg60086#msg60086 date=1243377132
Couple questions - do you progress bets as you win or as you lose? Also, after you've had a dozen repeat 3 times do you play the same other 2 dozens until you lose or with each bet do you alternate and play the last 2 that did not hit. For example - Dozen 1 (Low) repeats 3 times so I play Dozen 2 & 3 (Med/High). Then Dozen 3 hits, I win. Do I continue to play Dozen 2 & 3 or do I now switch to Dozen 1 & 2 b/c those are the last 2 to not hit? ie. the Jump Dozens
Just wanted to clarify :good:
"do you progress bets as you win or as you lose?" - I am betting only for the first win, then I am catching new 3 dozens from the same section
"Then Dozen 3 hits, I win. Do I continue to play Dozen 2 & 3" - as above, when you win, you always should pick up three new dozens. But certainly if you want, you can count the last winning dozen for next 3 new. Examlpe:
13, 14, 15, - you play sect. I & III,
4 - you win
5, 6 - you can play sect. II & III (numbers 4, 5, 6 - three unique dozens :))
Quote from: elamigos on May 26, 2009, 07:42:40 PM
"do you progress bets as you win or as you lose?" - I am betting only for the first win, then I am catching new 3 dozens from the same section
"Then Dozen 3 hits, I win. Do I continue to play Dozen 2 & 3" - as above, when you win, you always should pick up three new dozens. But certainly if you want, you can count the last winning dozen for next 3 new. Examlpe:
13, 14, 15, - you play sect. I & III,
4 - you win
5, 6 - you can play sect. II & III (numbers 4, 5, 6 - three unique dozens :))
Ok, I've got it now. Thanks for the response!
I found something and I need testers.
Use the system as described above, but when you lose do not make a progression at next spin, but at next chance. Example:
15, 16, 17 - we play sections I & III (1 chip for Low, 1 chip for High)
17 - we lose & we wait for another chance
(. . . )
3, 4, 5 - we play II & III (3 chips for Med, 3 Chips for High)
7 - we lose & we wait for another chance
(. . . )
20, 21, 22 - we play I & III (9 chips for Low, 9 chips for High)
5 - we win, we wait for another chance with basic chips (1 unit for one dozen and 1 unit for second)
I was playing with this system for 2 hours on RNG wheel (about 1 spin per 2 seconds) and so far I didn't get more than 3 loses in a row. Even if, I made over 50 chips (1 lose costs 26 chips, check the bet calculator in post #1). Please post here your results.
Hi, in other words, u re betting against a dozen repeating 4 times right?
Is this in a no-zero roulette?
Quote from: rss link=topic=9694. msg62154#msg62154 date=1243885844
Hi, in other words, u re betting against a dozen repeating 4 times right?
Is this in a no-zero roulette?
Yes, after 3 times one dozen repets, I bet two others. So far I get no lose and I made over 70 chips, please make some test if you have free time.
Edit: certainly there is a one zero. If you are hunting for first dozen and numbers 2, 3 appeared and then 0, 4 - you better start hunting again from last number after zero (4 in this case).
Edit 2: I got 2 losses (although it was a profit of about 40 chips), I raise the level of waiting (one dozen must repeat 4 times, then betting two others) and see what happen.
Hey computer, you can do the same on columns. More chances to win and lose.
hermes ;D
Wow really interesing and simple :) I'll test it, and maybe if you wait till 4th spin you reduce the chance of loss a lot...but you'll have to wait a lot longer I guess :p
hey m8 im just learning rx coding and i think this could b good 1 to start. .
system bets if 2 dozens has sleeped for 3 spins
progression : stakes are raised only when that very same dozen comes to repeat 3 times that has lost last time
3 step progression 1,3,9
sorry i didnt get the progression criteria right as im new at rx but u still got the picture if u run the sys :yes:
system "elamigos3dozens"
{
Spin a wheel until one section/dozen come three times in a row.
For example you got: . . . , 2, 7, 11 -
then you start betting at the two last sections with progression 2, 6
(first time 1 chip for Med and 1 chip for High, next 3 chips for Med and 3 chips for High)
Use the system as described above, but when you lose do not make a progression at next spin, but at next chance. Example:
15, 16, 17 - we play sections I & III (1 chip for Low, 1 chip for High)
17 - we lose & we wait for another chance
(. . . )
3, 4, 5 - we play II & III (3 chips for Med, 3 Chips for High)
7 - we lose & we wait for another chance
(. . . )
20, 21, 22 - we play I & III (9 chips for Low, 9 chips for High)
5 - we win, we wait for another chance with basic chips (1 unit for one dozen and 1 unit for second)
}
method "main"
begin
if 1st dozen hit 3 begin put 1 record "2-3" data end else begin clear record "2-3" data end
if 2nd dozen hit 3 begin put 1 record "1-3" data end else begin clear record "1-3" data end
if 3rd dozen hit 3 begin put 1 record "1-2" data end else begin clear record "1-2" data end
if record "2-3" data = 1 begin put 1 list [2nd dozen, 3rd dozen] end
if list [2nd dozen, 3rd dozen] lost 1 begin add 1 record "2-3p" data end
if record "2-3p" data > 2 begin clear record "2-3p" data end
if record "2-3" data = 1 and record "2-3p" data = 1 begin put 3 list [2nd dozen, 3rd dozen] end
if record "2-3" data = 1 and record "2-3p" data = 2 begin put 9 list [2nd dozen, 3rd dozen] end
if record "1-3" data = 1 begin put 1 list [1st dozen, 3rd dozen] end
if list [1st dozen, 3rd dozen] lost 1 begin add 1 record "1-3p" data end
if record "1-3p" data > 2 begin clear record "1-3p" data end
if record "1-3" data = 1 and record "1-3p" data = 1 begin put 3 list [1st dozen, 3rd dozen] end
if record "1-3" data = 1 and record "1-3p" data = 2 begin put 9 list [1st dozen, 3rd dozen] end
if record "1-2" data = 1 begin put 1 list [1st dozen, 2nd dozen] end
if list [1st dozen, 2nd dozen] lost 1 begin add 1 record "1-2p" data end
if record "1-2p" data > 2 begin clear record "1-2p" data end
if record "1-2" data = 1 and record "1-2p" data = 1 begin put 3 list [1st dozen, 2nd dozen] end
if record "1-2" data = 1 and record "1-2p" data = 2 begin put 9 list [1st dozen, 2nd dozen] end
if record "2-3p" data > 0 and any dozen bet won 1 begin clear record "2-3p" data end
if record "1-3p" data > 0 and any dozen bet won 1 begin clear record "1-3p" data end
if record "1-2p" data > 0 and any dozen bet won 1 begin clear record "1-2p" data end
end
anyways heres a small tests i runned whith rx's rng
I think it wil probably tank at some stage you betteroff going with the trend remember the trend is your friend maybe play last dozen hit and longest dozen not hit
25 000 spins:
1051 wins
552 losses
if waiting after every L and using progression (eg L than wait for 3 D to repeat and bet next step of progression 1-3-9),
results were worse:
3 consecutive losses: 29 times
4 cons. L: 13 times
5L: 7times
6L: 2 times
Spins were real spins not rng
Quote from: rss on June 02, 2009, 12:50:18 PM
25 000 spins:
1051 wins
552 losses
if waiting after every L and using progression (eg L than wait for 3 D to repeat and bet next step of progression 1-3-9),
results were worse:
3 consecutive losses: 29 times
4 cons. L: 13 times
5L: 7times
6L: 2 times
Spins were real spins not rng
I had similar results when using RX code (thanks Viz for coding). There is currently no way to win a lot with this system. I giving it up, thanks anyway for feedback.
Edit: after raising the level of waiting to 4 or 5 (or more) - I had similar results too.
Try these Edward Dozens They correspond to the three parts of the wheel.
European
A. 1-6, 19-24
B. 7-12, 31-36
C. 13-18, 25-30
American
A. 7-12, 25-30
B. 1-6, 13-18
C. 19-24, 31-36
Wait for A, B, or C to hit 4 times in a row then bet the other two letters.