John Gold's Blog.

[WARRIOR]

Sounds complicated.

[John Gold]

Hello Warrior.

The parts to the method will look complicated but you will see at the end how they all come together and compliment each other to turn it into what I consider the most poweful bet I have ever come across.

I should add it's not something I can relay in a day or so. It will likely take a few weeks just adding a new bit each day.

The bet is based on the dozens and columns.

[John Gold]

The bet is based on dozens and columns.
1 = 1A.
2 = 1B.
3 = 1C.
4 = 1A.
5 = 1B.
6 = 1C.
7 = 1A.
8 = 1B.
9 = 1C.
10 = 1A.
11 = 1B.
12 = 1C.
13 = 2A.
14 = 2B.
15 = 2C.
16 = 2A.
17 = 2B.
18 = 2C.
19 = 2A.
20 = 2B.
21 = 2C.
22 = 2A.
23 = 2B.
24 = 2C.
25 = 3A.
26 = 3B.
27 = 3C.
28 = 3A.
29 = 3B.
30 = 3C.
31 = 3A.
32 = 3B.
33 = 3C.
34 = 3A.
35 = 3B.
36 = 3C.

So if you look at the very first snapshot that I posted up.

[attachthumb=#]

You can see that the first number 36 is represented by 3c.
The next number out was 10 which is represented by 1a.
The (n) next to the 1a means it was not a repeat of either the previous dozen (3) or the previous column (c).
The next number out was 9 which is represented by 1c.
This has a (y) next to it because there is a repeat here of the previous dozen.
That is easy enough to follow but you will also notice two other rows with dozen/column markings and either a (y) or (n) in them.
This is where the two sets of charts will come into play. I will explain in detail how to use them in my next post which will be up some time tomorrow. Thanks.

[WARRIOR]

ok i get it so far.

[iggiv]

thanx a lot John.

very interesting, pls go on

[John Gold]

Now I will explain how to use the 2 sets of charts. (I should add that you won't need to go through all this manually when you are playing or it would be impossible. You will be surprised how it all comes together at the end. It is a bit like a jigsaw puzzle. I want to show you all the pieces first and explain how they all work. I feel that will give you a good insight into the method itself.)

So if you look at the first snapshot again, you will see the first number in the first row was 36 which is represented by 3c for the 3rd dozen and column c.
The next number out was 10 which is represented by 1a for the 1st dozen and column a.
The (n) tells you that neither the previous dozen (3) or column (c) repeated.

Now let's look at what's going on in the second row. You will see there is a 2b and this is followed by a 1b (y). I am now going to show you how I arrived at this.
This is where you will use the first lot of the 2 sets of charts you wrote out.
The first number out was 36. So the next number after 36 on the single zero wheel is 11. (This is where you will work from.)
You will have a group of numbers in your charts that starts at 11 and works around to 13.
I will assign them the following markings which represents the dozens and columns.
11 = 1A.
30 = 1B.
8 = 1C.
23 = 1A.
10 = 1B.
5 = 1C.
24 = 1A.
16 = 1B.
33 = 1C.
1 = 1A.
20 = 1B.
14 = 1C.
31 = 2A.
9 = 2B.
22 = 2C.
18 = 2A.
29 = 2B.
7 = 2C.
28 = 2A.
12 = 2B.
35 = 2C.
3 = 2A.
26 = 2B.
0 = 2C.
32 = 3A.
15 = 3B.
19 = 3C.
4 = 3A.
21 = 3B.
2 = 3C.
25 = 3A.
17 = 3B.
34 = 3C.
6 = 3A.
27 = 3B.
13 = 3C.

Let's recap.
The first number out was 36 which went to 10. You can see that the 10 is represented by 1b looking at the numbers above.  The b in the 1b has repeated because previously there was a 2b. That's why there is a (y) Obviously y = repeat, n = no repeat.
I will do one more.
The next number out after 10 is 9. So the next number after 10 on the single 0 wheel is 5. (This is where you will work from.)
You will have a group of numbers in your charts that starts from 5 and works around to 23.
I will assign them the following markings which represents the dozens and columns.
5 = 1A.
24 = 1B.
16 = 1C.
33 = 1A.
1 = 1B.
20 = 1C.
14 = 1A.
31 = 1B.
9 = 1C.
22 = 1A.
18 = 1B.
29 = 1C.
7 = 2A.
28 = 2B.
12 = 2C.
35 = 2A.
3 = 2B.
26 = 2C.
0 = 2A.
32 = 2B.
15 = 2C.
19 = 2A.
4 = 2B.
21 = 2C.
2 = 3A.
25 = 3B.
17 = 3C.
34 = 3A.
6 = 3B.
27 = 3C.
13 = 3A.
36 = 3B.
11 = 3C.
30 = 3A.
8 = 3B.
23 = 3C.

So let's recap again.
The number 10 went to number 9. You can see this time that the 9 is represented by 1c. The 1 has repeated this time from the previous 1b and that is why you find a (y) next to the 1c in the snapshot.

I will show you how to use the set of charts for the third row in my next post and then round things up a bit before moving onto the next component of the method.

[robert]

. . . . . . Now let's look at what's going on in the second row.  You will see there is a 2b and this is followed by a 1b (y). . . .

Thank you John for sharing your winning method.  It is very generous from you. 
So far I understand everything, except I cannot figure out where the 2b came from. 
I would apprecite if you could explain it to me.

Kind regards
Robert

[John Gold]

Hello Robert, don't worry about the 2b. At the beginning, you will normally see something like the following.

23 2B.

8 1B (y) 3C 2A.

15 2C (n) 2B (n) 1A (y) = 6.


The 36 you see in the snapshot was not the first number out. Sorry for any confusion.


Here I will show you how to use the second lot of charts.
Looking at the first snapshot again, you will see the first number out was 36.
In your second lot of charts, you will have a group of numbers which starts from 0 and works around to 35. (remember, you are working from number after the 36)
Here are the markings which represents the dozens and columns.
0 = 1A.
1 = 1B.
2 = 1C.
3 = 1A.
4 = 1B.
5 = 1C.
6 = 1A.
7 = 1B.
8 = 1C.
9 = 1A.
10 = 1B.
11 = 1C.
12 = 2A.
13 = 2B.
14 = 2C.
15 = 2A.
16 = 2B.
17 = 2C.
18 = 2A.
19 = 2B.
20 = 2C.
21 = 2A.
22 = 2B.
23 = 2C.
24 = 3A.
25 = 3B.
26 = 3C.
27 = 3A.
28 = 3B.
29 = 3C.
30 = 3A.
31 = 3B.
32 = 3C.
33 = 3A.
34 = 3B.
35 = 3C.

So the 36 went to 10 and you can see the 10 is represented above by 1b. The 1 is a repeat from the previous 1a if you look at the snapshot and that's why you see a (y) next to the 1b.
I will do one more. So the number out now is 10. (I need to work from one number after the 10 which is 11.) You will have a group of numbers which starts at the 11 and works around to the 9.

11 = 1A.
12 = 1B.
13 = 1C.
14 = 1A.
15 = 1B.
16 = 1C.
17 = 1A.
18 = 1B.
19 = 1C.
20 = 1A.
21 = 1B.
22 = 1C.
23 = 2A.
24 = 2B.
25 = 2C.
26 = 2A.
27 = 2B.
28 = 2C.
29 = 2A.
30 = 2B.
31 = 2C.
32 = 2A.
33 = 2B.
34 = 2C.
35 = 3A.
36 = 3B.
0 = 3C.
1 = 3A.
2 = 3B.
3 = 3C.
4 = 3A.
5 = 3B.
6 = 3C.
7 = 3A.
8 = 3B.
9 = 3C.
So the 10 went to 9. You can see the 9 is represented by 3c. There is an (n) here.
That explains how the 2 sets of charts work. There is enough examples in the first 2 snapshots to work through to get the picture.

Ok, so what do the (y) and (n) do?
There are 8 possible combinations going across the 3 rows.
1, y y y.
2, y y n.
3, y n n.
4, y n y.
5, n n n.
6, n n y.
7, n y y.
8, n y n.
This is what decides what numbers or combination of numbers will be bet. I will cover this in my next post.

[robert]

Thanks John for your quick reply.  Everything is clear now.
I'm looking forward to your next posts.

Kind regards
Robert

[John Gold]

Now I am going to explain more about the (y) and the (n) and how they form into 8 sets of numbers.
1, y y y.
2, y y n.
3, y n n.
4, y n y.
5, n n n.
6, n n y.
7, n y y.
8, n y n.

Going back to the first snapshot again. 36 went to number 10. Now number 10 belongs to 1a.
So if a (y) was going to appear in the first row after the next number, it would require one of the following numbers to appear.
1,2,3,4,5,6,7,8,9,10,11,12,13,16,19,22,25,28,31,34. All these numbers belong to 1a (first dozen or column a)

What about for row 2 and 3 working from the number 5 in the first set of charts and working from number 11 in the second set of charts.
Have a look at the following snapshot.

[attachthumb=#]

[John Gold]

So for a (y) to appear in the second row, a number from 1b would have to appear.

5,24,16,33,1,20,14,31,9,22,18,29,28,3,32,4,25,6,36,8.

For a (y) to appear in the third row, a number from 1b would have to appear.

11,12,13,14,15,16,17,18,19,20,21,22,24,27,30,33,36,2,5,8.

The following snapshot shows how it would all look.

[attachthumb=#]

[John Gold]

As it turned out, number 9 came out. This is y y n belonging to group 2.

Here are all the numbers in their correct groups. So when the 36 went to 10, you would have had the following 8 groups in front of you when deciding to place a bet or not for the next spin.

1  (y y y) = 5,8,16,22.
2  (y y n) = 1,3,4,6,9,25,28,31.
3  (y n n) = 7,10,34.
4  (y n y) = 2,11,12,13,19.
5  (n n n) = 0,23,26,35.
6  (n n y) = 15,17,21,27,30.
7  (n y y) = 14,18,20,24,33,36.
8  (n y n) = 29,32.

I will show you tomorrow the best combination of groups to use and when. Some of the group combinations are amazing because of the way they allow you to lay out your chips. The key to the whole method is how to use these groups effectively.

[John Gold]

Here is an unrelated example to anything else. It will just give you an idea if you are trying to figure it out.
5 appears as your first number.
5 = 1B.
The Next number out is 22.
5 = 1B.
22 = 2A (n) 1C 2B.
The next number out is 3.
5 = 1B.
22 = 2A (n) 1C 2B.
3 = 1C (n) 1A (y) 2C (y) = 7.

Now you will have the following groups in front of you for the next bet.
1 = 2,6,15,18,21,24,27.
2 = 1,4,11.
3 = 3,5,7,8,10.
4 = 9,12,30,33,36.
5 = 13,14,29,35.
6 = 16,20,22.
7 = 17,19,23,25,26.
8 = 0,28,31,32,34.
One combination I would be considering here is the 5, 6, 7 and 8 groups.
It can be covered nicely with 8 splits (ignoring the zero)
13/16, 14/17, 19/20, 22/23, 25/26, 28/29, 31/32, 34/35.

[medo]

---Very familiar with some improvements from last year.
    Could be improved even to better with a slight tweak.

[John Gold]

Hello Medo, I hope you are well and having fun. It would be good to hear of any suggestions from yourself.

By now, it will be obvious that the hard work comes from writing out all the different 8 combinations. There is a different set of combinations each time a number goes to another number.
Here is an example.
The number 1 appears and then the next number out is number 2.
So you have 1 – 2 = 1B  2B  1A.
The 8 combinations will be the following.
1, y y y = 3,4,5,9,11,14.
2, y y n = 1,17,20,23,29,32.
3, y n n = 2,26,35.
4, y n y = 6,7,8,10,12.
5, n n n = 0,19,25,34.
6, n n y = 13,15,21,30,36.
7, n y y = 18,24,27,33.
8, n y n = 16,22,28,31.

But.... suppose the 1 appears and then the next number out is 3.
Now you have 1 – 3 = 1C  1C  1B.
The 8 combinations will be the following.
1, y y y = 4,5,6,7,8,15.
2, y y n = 2,21,33,36.
3, y n n = 3,18,24,27,30.
4, y n y = 1,9,10,11,12.
5, n n n = 16,28,31.
6, n n y = 13,20,23,29.
7, n y y = 14,17,26,32,35.
8, n y n = 0,19,22,25,34.

I spent a few hours every day writing out all the different combinations and I don't have the time to write them all out again on here. Maybe someone with programming skills would be kind enough to do it and save everyone a mountain of work. I would be happy to pay to have it done to help everyone if someone is prepared to do it. Just let me know. Thanks.

I have all the combinations in a small (well worn) book which is easy enough to flick through the pages. The top looks like...

23 -34 = 3A 3B 1B.
Then it has the 8 combinations below that. Below that is the numbers split into the different groups that I look out for. There is no real point in me going into the specifics until anybody interested is up to speed with all the different combinations. So I will be happy to continue once we are all singing from the same sheet. Feel free to fire any general questions in the meantime.

[John Gold]

-