John Gold's Blog.

[John Gold]

For the 'missing 6' I prefer to use the 1/1 betting chart. However there are times when the trend can run against you and you bet the 1,2,5 for the '6 on a 4' and the 3 street shows up, then you bet the 1,2,5 and a 4 shows up. You have a choice here of either waiting for it to get back on track or change over to the 4 street betting chart.

Don't let the wheel beat you up. If a trend is going against you, find something else to bet or take a break. Stubborness can wipe out a bankroll in no time at all.

[John Gold]

I came up with all this stuff around 2007/2008. The problem I soon found which is the same for everyone is how can you predict anything with any accuracy. If the 1 street goes missing for 5 times in a row, does that make it more likely to be missing on the next spin as well? Of course not. And vice versa, if the one appears for 5 times in a row, does that make it any more likely to keep on appearing? no. This is where you get to with hot and cold numbers, streets etc...  You can spend years going around in circles trying to work this one out.
My personal opinion is that the answer lies in the 'timing' of your bets. You need to build a framework which gives you some solid betting triggers. This is where I will be heading next on this blog. I moved away from this original idea with the streets and started to look at the lanes and explored different ideas for finding the right moment to place a bet.

[col1879]

I agree with what you say John. I think another important key to the puzzle, which people sometimes forget, lies in virtual betting. You do not have to bet on every spin, put 1 on red and 1 on black and hope zero doesn't hit! lol

[John Gold]

Here are the first 60 results from today at the Spielbank-Wiesbaden Casino for testing purposes.

29 = 5.
24 = 4, 2, 5. (3) (1,3,6)
21 = 4, 6, 6. (2) (1,2,3,5)
23 = 4, 6, 6. (2) (1,2,3,5)
24 = 4, 6, 6. (2) (1,2,3,5)
10 = 2, 3, 4. (3) (1,5,6)
23 = 4, 3, 2. (3) (1,5,6)
1 = 1, 1, 3. (2) (2,4,5,6)
32 = 6, 1, 5. (3) (2,3,4)
15 = 3, 3, 3. (1) (1,2,4,5,6)
33 = 6, 3, 3. (2) (1,2,4,5)
22 = 4, 4, 4. (1) (1,2,3,5,6)
3 = 1, 1, 3. (2) (2,4,5,6)
18 = 3, 4, 2. (3) (1,5,6)
16 = 3, 6, 6. (2) (1,2,4,5)
35 = 6, 3, 3. (2) (1,2,4,5)
22 = 4, 4, 4. (1) (1,2,3,5,6)
28 = 5, 4, 1. (3) (2,3,6)
23 = 4, 2, 5. (3) (1,3,6)
15 = 3, 5, 5. (2) (1,2,4,6)
18 = 3, 6, 6. (2) (1,2,4,5)
10 = 2, 4, 5. (3) (1,3,6)
19 = 4, 3, 2. (3) (1,5,6)
17 = 3, 5, 5. (2) (1,2,4,6)
15 = 3, 6, 6. (2) (1,2,4,5)
10 = 2, 4, 5. (3) (1,3,6)
36 = 6, 5, 4. (3) (1,2,3)
28 = 5, 2, 5. (2) (1,3,4,6)
5 = 1, 3, 2. (3) (4,5,6)
32 = 6, 1, 5. (3) (2,3,4)
21 = 4, 4, 4. (1) (1,2,3,5,6)
9 = 2, 3, 4. (3) (1,5,6)
19 = 4, 3, 2. (3) (1,5,6)
21 = 4, 6, 6. (2) (1,2,3,5)
1 = 1, 1, 3. (2) (2,4,5,6)
6 = 1, 6, 6. (2) (2,3,4,5)
24 = 4, 5, 3. (3) 1,2,6)
7 = 2, 3, 4. (3) (1,5,6)
30 = 5, 1, 3. (3) (2,4,6)
19 = 4, 2, 5. (3) (1,3,6)
26 = 5, 4, 1. (3) (2,3,6)
13 = 3, 1, 4. (3) (2,5,6)
16 = 3, 6, 6. (2) 1,2,4,5)
35 = 6, 3, 3. (2) (1,2,4,5)
28 = 5, 2, 5. (2) (1,3,4,6)
10 = 2, 5, 3. (3) (1,4,6)
3 = 1, 4, 5. (3) (2,3,6)
14 = 3, 4, 2. (3) (1,5,6)
19 = 4, 1, 1. (2) (2,3,5,6)
20 = 4, 6, 6. (2) (1,2,3,5)
16 = 3, 5, 5. (2) (1,2,4,6)
21 = 4, 1, 1. (2) (2,3,5,6)
29 = 5, 4, 1. (3) (2,3,6)
24 = 4, 2, 5. (3) (1,3,6)
31 = 6, 2, 2. (2) (1,3,4,5)
18 = 3, 3, 3. (1) (1,2,4,5,6)
30 = 5, 5, 2. (2) (1,3,4,6)
2 = 1, 3, 2. (3) (4,5,6)
13 = 3, 4, 2. (3) (1,5,6)
27 = 5, 5, 2. (2) (1,3,4,6)
21 = 4, 2, 5. (3) (1,3,6)

If any of you guys have any ideas of your own regarding this, then please feel free to share.

[John Gold]

Something struck me last night as I was reading one of my favourite roulette books (no rest for the wicked  )
It's called 'Thirteen against the bank' by Norman Leigh. Some of you will be aware the author took a team over to France and more or less forced the casino to put up the white flag by the use of his 'reverse labouche' betting plan.

Take a look at the 60 results I typed out above and pay particular attention to the missing 1 in the last section.
I will type out when it appeared and missed using the following notation. W = HIT.   L = MISS.

WWWWWWLLWWWLWWWWLWWWWWWWWWWLLWWWWLLWWLWLLWWWW
LWLWWLLWWWWLWWW These are the 60 results.

As you can see there is plenty of scope here for using the reverse labouche. The trick will come in adjusting the stakes slightly when you are required to bet on 4 streets as opposed to 3. Maybe it is just a case of only backing the 1/1 bets that appear.

If the above scenario was an even money chance all the way through. This is what a reverse labouche would end up looking like which started at 1 1 1 1.
18,20,22,24,26,30,34,43,52,61,77,93,109,127,145,163. = 1044 units.

Norman leigh had a team playing all the even chances hoping one of them would produce a long winning string and break the table limit. The key to making a reverse labouche work is to avoid too many consecutive losses wiping out your string because as some of you know, you are only adding one figure onto your string on a win and taking two away on a loss. However the method I am describing on this blog does produce long consecutive winning runs. Therefore it may be worth exploring the reverse labouche in more detail.

[MauiSunset]

Here are the first 60 results from today at the Spielbank-Wiesbaden Casino for testing purposes.

29 = 5.
24 = 4, 2, 5. (3) (1,3,6)
21 = 4, 6, 6. (2) (1,2,3,5)
23 = 4, 6, 6. (2) (1,2,3,5)
24 = 4, 6, 6. (2) (1,2,3,5)
10 = 2, 3, 4. (3) (1,5,6)
23 = 4, 3, 2. (3) (1,5,6)
1 = 1, 1, 3. (2) (2,4,5,6)
32 = 6, 1, 5. (3) (2,3,4)
15 = 3, 3, 3. (1) (1,2,4,5,6)
33 = 6, 3, 3. (2) (1,2,4,5)
22 = 4, 4, 4. (1) (1,2,3,5,6)
3 = 1, 1, 3. (2) (2,4,5,6)
18 = 3, 4, 2. (3) (1,5,6)
16 = 3, 6, 6. (2) (1,2,4,5)
35 = 6, 3, 3. (2) (1,2,4,5)
22 = 4, 4, 4. (1) (1,2,3,5,6)
28 = 5, 4, 1. (3) (2,3,6)
23 = 4, 2, 5. (3) (1,3,6)
15 = 3, 5, 5. (2) (1,2,4,6)
18 = 3, 6, 6. (2) (1,2,4,5)
10 = 2, 4, 5. (3) (1,3,6)
19 = 4, 3, 2. (3) (1,5,6)
17 = 3, 5, 5. (2) (1,2,4,6)
15 = 3, 6, 6. (2) (1,2,4,5)
10 = 2, 4, 5. (3) (1,3,6)
36 = 6, 5, 4. (3) (1,2,3)
28 = 5, 2, 5. (2) (1,3,4,6)
5 = 1, 3, 2. (3) (4,5,6)
32 = 6, 1, 5. (3) (2,3,4)
21 = 4, 4, 4. (1) (1,2,3,5,6)
9 = 2, 3, 4. (3) (1,5,6)
19 = 4, 3, 2. (3) (1,5,6)
21 = 4, 6, 6. (2) (1,2,3,5)
1 = 1, 1, 3. (2) (2,4,5,6)
6 = 1, 6, 6. (2) (2,3,4,5)
24 = 4, 5, 3. (3) 1,2,6)
7 = 2, 3, 4. (3) (1,5,6)
30 = 5, 1, 3. (3) (2,4,6)
19 = 4, 2, 5. (3) (1,3,6)
26 = 5, 4, 1. (3) (2,3,6)
13 = 3, 1, 4. (3) (2,5,6)
16 = 3, 6, 6. (2) 1,2,4,5)
35 = 6, 3, 3. (2) (1,2,4,5)
28 = 5, 2, 5. (2) (1,3,4,6)
10 = 2, 5, 3. (3) (1,4,6)
3 = 1, 4, 5. (3) (2,3,6)
14 = 3, 4, 2. (3) (1,5,6)
19 = 4, 1, 1. (2) (2,3,5,6)
20 = 4, 6, 6. (2) (1,2,3,5)
16 = 3, 5, 5. (2) (1,2,4,6)
21 = 4, 1, 1. (2) (2,3,5,6)
29 = 5, 4, 1. (3) (2,3,6)
24 = 4, 2, 5. (3) (1,3,6)
31 = 6, 2, 2. (2) (1,3,4,5)
18 = 3, 3, 3. (1) (1,2,4,5,6)
30 = 5, 5, 2. (2) (1,3,4,6)
2 = 1, 3, 2. (3) (4,5,6)
13 = 3, 4, 2. (3) (1,5,6)
27 = 5, 5, 2. (2) (1,3,4,6)
21 = 4, 2, 5. (3) (1,3,6)

If any of you guys have any ideas of your own regarding this, then please feel free to share.

John,

In the above data, when do you decide to start betting?  Any rules of thumb?

In: 24 = 4, 2, 5. (3) (1,3,6)   what is the (3)?  It's not on your "Marking Template"  You seem to call it "The range".

Also, the cluster:
21 = 4, 6, 6. (2) (1,2,3,5)
23 = 4, 6, 6. (2) (1,2,3,5)
24 = 4, 6, 6. (2) (1,2,3,5)

Are from the same street, #4, does this enter into your decisions somewhere?


Thanks

[MauiSunset]

John, what am I doing wrong here?

9 = 5.
24 = 4, 2, 5. (3) (1,3,6)
21 = 4, 6, 6. (2) (1,2,3,5)
23 = 4, 6, 6. (2) (1,2,3,5)
24 = 4, 6, 6. (2) (1,2,3,5)

At this point I see 1 appearing so that's what I'm going to bet: #24 is Street 4, so 1 on a 4 and I bet streets:2,3,4,6.

10 spins and I am a winner $5 - $3 in bets = +$2

10 = 2, 3, 4. (3) (1,5,6)

I still see 1 and 5 showing up so I stick with 1 and bet #10 is Street 2, so 1 on a 2 and I bet streets: 2,4,6.

23 spins and I am a winner of $5 - $2 = $3


23 = 4, 3, 2. (3) (1,5,6)

I still see 1 and 5 and stick with 1 and bet with 1 and #23 is Street 4, so 1 on a 4 and bet streets: 2,3,4,6

1 spins and I lose $4

1 = 1, 1, 3. (2) (2,4,5,6)

I don't see street 1 but street 5 appears a lot and bet with 5 and #1 is Street 1, so 5 on a 1 and bet streets: 1,2,3

32 = 6, 1, 5. (3) (2,3,4)

32 spins and I lose $3

15 = 3, 3, 3. (1) (1,2,4,5,6)
33 = 6, 3, 3. (2) (1,2,4,5)
22 = 4, 4, 4. (1) (1,2,3,5,6)
3 = 1, 1, 3. (2) (2,4,5,6)
18 = 3, 4, 2. (3) (1,5,6)
16 = 3, 6, 6. (2) (1,2,4,5)

------------------------------------------------------------------

I'm down $2 so far - what am I doing wrong?

Thanks

[John Gold]

MauiSunset, I need to go out soon and take care of a few things. I will be back later and answer your questions.
One thing I noticed was your profits. If you place a chip on a street, you are returned 5/1 plus keep your original stake. So in the case of a win here, you are +2 units. I am not sure where you are getting the +1 from.

cheers.

[MauiSunset]

MauiSunset, I need to go out soon and take care of a few things. I will be back later and answer your questions.
One thing I noticed was your profits. If you place a chip on a street, you are returned 5/1 plus keep your original stake. So in the case of a win here, you are +2 units. I am not sure where you are getting the +1 from.

cheers.

What Mistake? (I sure goofed and adjusted the post just now)

Sorry, but still down in 4 trades (not that that's something new to me)

[John Gold]

MauiSunset asked a few questions which I am going to attempt to answer here.

As far as bet selection goes, the choices are endless but that is not really a good answer.

Here would be my favourites.

In the first couple of posts on this blog when I started explaining this concept, I suggested the 'pluscoup progression' I would like to make a small change to that now. I was reading some of GLC's threads over on the other forum regarding Brett Morton's book. Morton thought the pluscoup  progression was a good idea but he would reduce by 1 unit on a loss instead of sticking.
So the idea of pluscoup is that you are looking to make a unit profit and then start over.
The rules are pretty simple. You start betting with 1 unit. If you lose, you have to stick on one unit because you can't go any lower than that. If you win and you have not reached a profit of 1 for the series, then you up the bet to 2 units for the next bet. If you win this bet and are still not in profit for the series by 1 unit, then you need to raise the bet by 1 unit again. Any time you have a loss, reduce the bet by 1 unit. You quit the series when you are in profit by 1 unit.

Just a note on progressions and I think this is important. I never used to rate them. I thought if you could not win flat betting, you were wasting your time. I have changed my mind slightly. The ultimate aim is to win. However you care to go about it is up to you. Here is a good analogy.
Imagine you are challenged to a street fight and you turn up and you are just going to use your bare fists. You figure that is the noble thing to do. Now along comes the opponent and he has brought with him more tools than you would find in a hardware shop and he is going to use them. Well good luck to you chap because I think you are going to need it. You have to do whatever it takes to come out a winner.
You can be creative with progressions. I would imagine most players who use them play every spin. Where does it say that you need to play every spin with a labouchere or any other progression for that matter. I have not studied this area in depth yet but I will make it my business this year to really get stuck into having a look at all the various types of progressions and see if timing can help them perform well enough to come out on top.

Flat betting using good timing would be another way to bet this method. That is what the 'range' is for. If that is trending with 1's and 2's, then you know that you are going to have 4 or 5 numbers in the bracketed section and this gives you a good chance of going on a winning run. (it is just an option, you don't really need to use this if you don't want to.)

Finally, I am going to start testing over the next few days with the 'reverse labouchere'  I am thinking that maybe the best way to approach this is to play two numbers at the same time and start the string at 1 1 1 1. Looking at the 60 results I put up earlier, the 1 and 2 would have produced some good results with this type of bet. There will be lots of small losses along the way but in this instance, there would have also being some very nice wins as well.

So that kind of covers where I am at with the betting approach.

There are times when you may be betting for a street to remain missing. (example.. 6 on a 1) and you see that you are required to bet streets 3,4,5. (This is assuming you are playing using the even money betting chart) If the 2 comes up, you have lost. If you had used the betting chart for the 6 on a 1 where you are rquired to bet 4 streets, ie. 2,3,4,5. you would have won. This can go against you when playing the 1/1 bets. What I do is look out for this. If it happens once, stop betting that particular trigger or look for a street which is playing ball. If things are going against you, you don't need to stick with it. After all, that is what this is. It's a tool and you have to play it with your eyes open and see what's going on. It can help you spot trends and you can ride them. When they stop, you should stop and look for something else that is happening. It can be a grind and there are still times you are going to lose. I have not managed to find a way that overcomes the maths, I think at best, you can sometimes slide your way around it. There are more things to beat you than help you win at the roulette table. Only by trying to look underneath the game and get an idea of what is going on, can you try and stay on top of the variance and keep slightly ahead of the game.

I think that about covers it.

[John Gold]

Now I am going to present you with some figures and you can make of them what you will.
When I came up with this concept a few years ago, I shared it with a friend in Germany who was a great roulette enthusiast. Unfortunately he passed away early last year. He did a lot of testing with this idea and told me that the 3 and 4 street went missing in the last section more than any other street.
If this is the case and you are exploring the idea of playing some kind of reverse labouchere, I would do some research first.

Using the 60 spin sample from above, here are some statistics.

This shows the number of spins a street goes missing for throughout the 60 spins.

street 1) 2,1,1,2,2,1,2,1,1,2,1. So here the longest number of spins the 1 was absent for in the last section was only ever 2 at most. The total was only 16 out of 60. That is a great ratio for a reverse labouchere.

street 2) 1,2,1,1,2,1,2,2,1,1,2,1,2,5. The 5 at the end killed this one. A total of 24 out of 60.

street 3) 3,2,4,2,3,1,2,1,3,3,1,1,1,1,2. A total of 30 out of 60.

street 4) 6,1,1,3,2,2,4,2,3,4,3,1,1. A total of 33 out of 60.

street 5) 1,1,3,1,1,3,1,1,3,3,1,2,1,2. A total of 24 out of 30.

street 6) 3,1,1,2,1,1,1,1,1,1,2,1,1. A total of 17 out of 60.

Looking at the figures for the 3 and the 4 street certainly indicates what old Wolfgang was telling me. I would need to do some longer tests to be certain. When doing my testing on the reverse labouchere, I will be concentrating on streets 1,2,5 and 6.

[MauiSunset]

Now I am going to present you with some figures and you can make of them what you will.
When I came up with this concept a few years ago, I shared it with a friend in Germany who was a great roulette enthusiast. Unfortunately he passed away early last year. He did a lot of testing with this idea and told me that the 3 and 4 street went missing in the last section more than any other street.
If this is the case and you are exploring the idea of playing some kind of reverse labouchere, I would do some research first.

Using the 60 spin sample from above, here are some statistics.

This shows the number of spins a street goes missing for throughout the 60 spins.

street 1) 2,1,1,2,2,1,2,1,1,2,1. So here the longest number of spins the 1 was absent for in the last section was only ever 2 at most. The total was only 16 out of 60. That is a great ratio for a reverse labouchere.

street 2) 1,2,1,1,2,1,2,2,1,1,2,1,2,5. The 5 at the end killed this one. A total of 24 out of 60.

street 3) 3,2,4,2,3,1,2,1,3,3,1,1,1,1,2. A total of 30 out of 60.

street 4) 6,1,1,3,2,2,4,2,3,4,3,1,1. A total of 33 out of 60.

street 5) 1,1,3,1,1,3,1,1,3,3,1,2,1,2. A total of 24 out of 30.

street 6) 3,1,1,2,1,1,1,1,1,1,2,1,1. A total of 17 out of 60.

Looking at the figures for the 3 and the 4 street certainly indicates what old Wolfgang was telling me. I would need to do some longer tests to be certain. When doing my testing on the reverse labouchere, I will be concentrating on streets 1,2,5 and 6.

Statistics would say that out of 60 spins:
Street 1: 10 out of 60
Street 2: 10 out of 60
Street 3: 10 out of 60
Street 4: 10 out of 60
Street 5: 10 out of 60
Street 6: 10 out of 60

I'm not sure what you are saying John.

[John Gold]

Unfortunately I am no maths whizz. Creativity is probably more my forte.
It just seems that there are plenty of hits for the 1, 2 and 6 street in the last section. (In other words, not appearing in the first section) It is just a case of finding a bet that capitalizes on this and takes advantage of the good streaks.

[John Gold]

Hello.

I did a lot of thinking and testing last night regarding all of this and I think I have it narrowed down to what is probably the best way to play it.

It involves just concentrating on when the 6 street is in the last section.

I would also suggest using the full betting chart for the 6 which is as follows.

No 6 on a 1. bet 2,3,4,5.
No 6 on a 2. bet 1,3,4,5.
No 6 on a 3. bet 1,2,4,5.
No 6 on a 4. bet 1,2,3,5.
No 6 on a 5. bet 1,2,3,4.

What I am looking for is a parlay (two wins in a row) I am going to suggest the following progression.



1) a.  4. 00 = 4x1. 00 win 6. 00 lose 4. 00
b.  6. 00 = 4x1. 50 win 9. 00 lose 4. 00

2) a.  8. 00 = 4x2. 00 win 12. 00 lose 12. 00
b.  12. 00 = 4x3. 00 win 18. 00 lose 12. 00

3) a.  16. 00 = 4x4. 00 win 24. 00 lose 28. 00
b.  24. 00 = 4x6. 00 win 36. 00 lose 28. 00

4) a.  24. 00 = 4x6. 00 win 36. 00 lose 52. 00
b.  36. 00 = 4x9. 00 win 54. 00 lose 52. 00

5) a.  44. 00 = 4x11. 00 win 66. 00 lose 96. 00
b.  66. 00 = 4x16. 50 win 99. 00 lose 96. 00

6) a.  80. 00 = 4x20. 00 win 120. 00 lose 176. 00
b.  120. 00 = 4x30. 00 win 180. 00 lose 176. 00

7) a.  144. 00 = 4x36. 00 win 216. 00 lose 320. 00
b.  216. 00 = 4x54. 00 win 324. 00 lose 320. 00

8> a.  260. 00 = 4x65. 00 win 390. 00 lose 580. 00
b.  390. 00 = 4x97. 50 win 585. 00 lose 580. 00

9) a.  480 = 4x120. 00 win 720. 00 lose 1060. 00
b.  720. 00 = 4x180. 00 win 1080. 00 lose 1060. 00

total bankroll needed 1060. 00

win at different levels.

1)5. 00
2)6. 00
3)8. 00
4)2. 00
5)3. 00
6)4. 00
7)4. 00
8)5. 00
9)20. 00


This gives you a lot of chances to hit two in a row and come away with a profit.

You start of on level 1 looking to hit 2 consecutive wins. If you lose the first step of level 1, you move up to level 2.

You may win the first step on a level but lose the second step, you will then move up a level.

When you win both bets on any level, you are in profit and start all over again at level 1.

I have went through all my testing results and can't find any game which was a loser.

This looks like a rock solid bet to me.

I will be back with some examples later.

[John Gold]

Playing this idea with the 60 spin sample above would have produced the following results.

Win on level 4 on spin 7. (number 23)

Win on level 3 on spin 13. (number 3)

Win on level 3 on spin 18. (number 28)

Win on level 1 on spin 20. (number 15)

Win on level 2 on spin 23. (number 19)

Win on level 3 on spin 29. (number 5)

Win on level 2 on spin 32. (number 9)

Win on level 3 on spin 38. (number 7)

Win on level 1 on spin 40. (number 19)

Win on level 1 on spin 42. (number 13)

Win on level 3 on spin 46. (number 10)

Win on level 1 on spin 48. (number 14)

Win on level 2 on spin 52. (number 21)

Win on level 1 on spin 54. (number 24)

Win on level 2 on spin 57. (number 30)

Win on level 1 on spin 59. (number 13)

Win on level 1 on spin 61. (number 21)

I hope you get the idea, that was just a quick run through of the numbers above.

7 wins on level 1.

4 wins on level 2.

5 wins on level 3.

1 win on level 4.

Maybe you don't even need 9 levels. That can be played around with a bit.

The profit for the above would have reached +101.00.

[John Gold]

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