The 'eclipse method'

[John Gold]

This is a bit of an offshoot from something I was working on recently.

The best way to explain it will be to go through it step by step using an example. Hopefully that will give you an idea as to what is going on.

The actual bet itself is a dozens bet. You will be betting on two six lines.

The six lines comprise of the following.

1-6 = 1.
7-12 = 2.
13-18 = 3.
19-24 = 4.
25-30 = 5.
31-36 = 6.

The progression for the bet is as follows.


*EDIT*  The progression is in the next post.


So let's get started with the example.

36 is the first number out. What you need to do is keep a count of all the six lines and keep a rolling count of how many times they are missing.

So because 36 was the first number out, your count would look like this.

1 (1) 2 (1) 3 (1) 4 (1) 5 (1) 6 (0)

OK, let's move onto the next number.

35  You also need to check if the new six line that has just appeared is an alternate from the last one.
In this instance, it is not. So I like to mark it like this.

35 (N)  

How does the rolling count look now. 1(2) 2 (2) 3 (2) 4 (2) 5 (2) 6 (0)

next number.

22  Now this is an alternating six line. So I mark it like this.

22 (Y) (1) the 1 is another count to keep track on how many alternating six lines I am getting..

The rolling count now looks like this. 1 (3) 2 (3) 3 (3) 4 (0) 5 (3) 6 (1)

Next number.

16 (Y) (2)      ROLLING COUNT. 1 (4) 2 (4) 3 (0) 4 (1) 5 (4) 6 (2)

Next number.

27 (Y) (3)       ROLLING COUNT. 1 (5) 2 (5) 3 (1) 4 (2) 5 (0) 6 (3)

Next number.

28 (N) (0)      ROLLING COUNT. 1 (6) 2 (6) 3 (2) 4 (3) 5 (0) 6 (4)

35 (Y) (1)      ROLLING COUNT. 1 (7) 2 (7) 3 (3) 4 (4) 5 (1) 6 (0)

3 (Y) (2)       ROLLING COUNT. 1 (0) 2 (8} 3 (4) 4 (5) 5 (2) 6 (1)

19 (Y) (3)      ROLLING COUNT. 1 (1) 2 (9) 3 (5) 4 (0) 5 (3) 6 (2)

35 (Y) (4)      ROLLING COUNT. 1 (2) 2 (10) 3 (6) 4 (1) 5 (4) 6 (0)

3 (Y) (5)        ROLLING COUNT. 1 (0) 2 (11) 3 (7) 4 (2) 5 (5) 6 (1)

12 (Y) (6)      ROLLING COUNT. 1 (1) 2 (0) 3 (8} 4 (3) 5 (6) 6 (2)

3 (Y) (7)         ROLLING COUNT. 1(0) 2 (1) 3 (9) 4 (4) 5 (7) 6 (3)

36 (Y) (8}       ROLLING COUNT. 1 (1) 2 (2) 3 (10) 4 (5) 5 (8} 6 (0)

Here is where you have the first bet. Once you see the current six line has alternated at least 8 times, that signals there could be a possible bet.
What you then need to do is go over to the rolling count and check for the furthest back six line.
Here it is the 3 which has missed 10 times. (The qualifying target for a possible bet  is 8+. If there are more than one with 8+, always play the one which has missed for the longest.)

So both qualifying targets have occurred.

How do you bet? I am going to bet for the current six line to repeat. (In this instance, it's the 6)
I am also going to bet for the longest missing six line in the rolling count to appear. (In this instance, it's the 3)

So betting the 6 six line and the 3 six line combines as a dozens bet. I am going to use the 10 step progression.

16 (Y) (9)         ROLLING COUNT. 1 (2) 2 (3) 3 (0) 4 (6) 5 (9) 6 (1)

That was a winning bet on the 1st step of the progression. The missing 3 from the rolling count came in.

You will notice that there is also another bet straight away.  Why?

Because the six lines are still alternating (currently standing at 9 which qualifies for a bet and the 5 six line in the rolling count is also at 9. This also qualifies.

So now I am betting for a repeat on the 3 six line and also betting the 5 six line.

28 (Y) (10)          ROLLING COUNT. 1 (3) 2 (4) 3 (1) 4 (7) 5 (0) 6 (2)

That was a winning bet on the 1st step of the progression. The missing 5 from the rolling count came in.

There is now no bet on the next spin. There are no qualifiers in the rolling count.

8 (Y) (11)           ROLLING COUNT. 1 (4) 2 (0) 3 (2) 4 (8} 5 (1) 6 (3)

There is a bet now because we have a qualifier in the rolling count.
I am looking for a repeat of the 2 six line and also playing the missing 4 six line.

25 (Y) (12)       ROLLING COUNT. 1 (5) 2 (1) 3 (3) 4 (9) 5 (0) 6 (4)

That was a losing bet. I will now move up to step 2 in the progression and I am betting for a repeat 5 six line and the missing 4 six line.

6 (Y) (13)        ROLLING COUNT. 1 (0) 2 (2) 3 (4) 4 (10) 5 (1) 6 (5)

That was another losing bet and I will now move up to step 3 in the progression. I am betting for a repeat 1 six line and the missing 4 six line.

7 (Y) (14)       ROLLING COUNT. 1 (1) 2 (0) 3 (5) 4 (11) 5 (2) 6 (6)

That was another losing bet and I will now move up to step 4 in the progression. I am betting for a repeat 2 six line and the missing 4 six line.

22 (Y) (15)       ROLLING COUNT. 1 (2) 2 (1) 3 (6) 4 (0) 5 (3) 6 (7)

A win there on the missing 4 six line.

There is no bet on the next spin.

27 (Y) (16)         ROLLING COUNT. 1 (3) 2 (2) 3 (7) 4 (1) 5 (0) 6 (8}

There is a bet on the next spin. I am betting for a repeat on the 5 six line and also looking for the missing 6 six line.

20 (Y) (17)         ROLLING COUNT. 1 (4) 2 (3) 3 (8} 4 (0) 5 (1) 6 (9)

That was a losing bet on step 1 of the progression.

I am betting again on the next spin and looking for a repeat of the 4 six line or the missing 6 six line.

31 (Y) (18)         ROLLING COUNT. 1 (5) 2 (4) 3 (9) 4 (1) 5 (2) 6 (0)

A win there on the 2nd step of the progression.

There is another bet on the next spin. I am looking for a repeat of the 6 six line or the missing 3 six line.

25 (Y) (19)         ROLLING COUNT. 1 (6) 2 (5) 3 (10) 4 (2) 5 (0) 6 (1)

That was a loss on the 1st step of the progression. I will be betting again looking for a repeat of the 5  six line or the missing 3 six line.

30 (N) (0)           ROLLING COUNT. 1 (7) 2 (6) 3 (11) 4 (3) 5 (0) 6 (2)

That was a win on the 2nd step of the progression. Finally the street repeated. (I just pulled this card out of one of my files and I have to say that is a lot of alternating six lines in succession. You will not see that happen very often. Still it shows the method working well.

There is no bet on the next spin and it will take a while now for one of the qualifying rules to work it's way back up to at least 8 again.

So there were 5 bets there in all never going past step 4 in the progression.

I personally think that this is a great little bet. You don't need a huge bankroll and the wins seem to come steady enough.

[John Gold]

Ok, revised progression chart, LoL.  I copy and pasted the other one and that would be for betting dozens as they appear on the layout. With this one, we are betting two six lines. Sorry for any confusion.

Step 1.   bet 2 (1 on each six line) win +4  /  lose -2.
Step 2.   bet 2 (1 on each six line) win +2  /  lose -4.
Step 3.   bet 4 (2 on each six line) win +4  /  lose -8.
Step 4.   bet 6 (3 on each six line) win +4  /  lose -14.
Step 5.   bet 8 (4 on each six line) win +2  /  lose -22.
Step 6.   bet 12 (6 on each six line) win +2  /  lose -34.
Step 7.   bet 18 (9 on each six line) win +2  /  lose -52.
Step 8.   bet 28 (14 on each six line) win +4  /  lose -80.
Step 9.   bet 42  (21 on each six line) win +4 /  lose -122.
Step 10. bet 62  (31 on each six line) win +2 /  lose -184.


What I noticed was that it is unusual a lot of the time to have 8 alternating six lines in succession. Then I thought if one of the six lines is also absent for a long time, it then means you only have 5 which must keep alternating for 18 times to bust the 10 step progression.
I have not seen that in any of my files. Of course it is out there waiting to happen some time. But I am impressed with my results so far.

[John Gold]

Just as an example, I was downloading the numbers as they came out from the Spielbank-Wiesbaden Casino in Germany this afternoon.

The first three bets were all winners on the first step of the progression.

4
19 (Y) (1)    R/C. 1 (1) 2 (1) 3 (1) 4 (0) 5 (1) 6 (1)
28 (Y) (2)    R/C. 1 (2) 2 (2) 3 (2) 4 (1) 5 (0) 6 (2)
18 (Y) (3)    R/C. 1 (3) 2 (3) 3 (0) 4 (2) 5 (1) 6 (3)
09 (Y) (4)    R/C. 1 (4) 2 (0) 3 (1) 4 (3) 5 (2) 6 (4)
09 (N) (0)    R/C. 1 (5) 2 (0) 3 (2) 4 (4) 5 (3) 6 (5)
29 (Y) (1)    R/C. 1 (6) 2 (1) 3 (3) 4 (5) 5 (0) 6 (6)
13 (Y) (2)    R/C. 1 (7) 2 (2) 3 (0) 4 (6) 5 (1) 6 (7)
02 (Y) (3)    R/C. 1 (0) 2 (3) 3 (1) 4 (7) 5 (2) 6 (8}
36 (Y) (4)    R/C. 1 (1) 2 (4) 3 (2) 4 (8} 5 (3) 6 (0)
18 (Y) (5)    R/C. 1 (2) 2 (5) 3 (0) 4 (9) 5 (4) 6 (1)
18 (N) (0)    R/C. 1 (3) 2 (6) 3 (0) 4 (10) 5 (5) 6 (2)
34 (Y) (1)    R/C. 1 (4) 2 (7) 3 (1) 4 (11) 5 (6) 6 (0)
23 (Y) (2)    R/C. 1 (5) 2 (8} 3 (2) 4 (0) 5 (7) 6 (1)
14 (Y) (3)    R/C. 1 (6) 2 (9) 3 (0) 4 (1) 5 (8} 6 (2)
20 (Y) (4)    R/C. 1 (7) 2 (10) 3 (1) 4 (0) 5 (9) 6 (3)
27 (Y) (5)    R/C. 1 (8} 2 (11) 3 (2) 4 (1) 5 (0) 6 (4)
10 (Y) (6)    R/C. 1 (9) 2 (0) 3 (3) 4 (2) 5 (1) 6 (5)
28 (Y) (7)    R/C. 1 (10) 2 (1) 3 (4) 4 (3) 5 (0) 6 (6)
15 (Y) (8}    R/C. 1 (11) 2 (2) 3 (0) 4 (4) 5 (1) 6 (7)  BET ON 3+1. WIN.
01 (Y) (9)    R/C. 1 (0) 2 (3) 3 (1) 4 (5) 5 (2) 6 (8}  BET ON 1+6.  WIN.
35 (Y) (10)  R/C. 1 (1) 2 (4) 3 (2) 4 (6) 5 (3) 6 (0)
29 (Y) (11)   R/C. 1 (2) 2 (5) 3 (3) 4 (7) 5 (0) 6 (1)
15 (Y) (12)   R/C. 1 (3) 2 (6) 3 (0) 4 (8} 5 (1) 6 (2)  BET ON 3+4.  WIN.
16 (N) (0)     R/C. 1 (4) 2 (7) 3 (0) 4 (9) 5 (2) 6 (3)

(in the examples above, remember the bets are for the following spin.)

It would take a while now to get the next bet because of the reset on the (0) when 16 came up. I think I would have probably quit the session anyhow. Can't get much better than that. 

[John Gold]

I went and played this live this morning for a few hours at my local casino.
I quit at +36 units. What amazed me was the times it kept winning on the very first bet. Just one of them lucky days I suppose. I may go again tonight well my luck is in. 

I was using the 10 step progression I listed above.
Another idea for a progression could be to go 1,1,1,2,2,2,3,3,3,4,4,4.  Up 1 on a loss and down 2 on a win. Not really sure what difference if any it would make. I will do some testing with it and see what happens.

cheers.

[John Gold]

I have managed to do a fair bit of testing with this during the afternoon.
There are some pretty slow sessions as the graph below shows. In this session, it took 294 spins to make 52 units profit. Now you know why I called it the 'eclipse'  
The zero was coming up like crazy in this session and it is probably a good idea to have it covered somehow. I will need to work on that one.

[attach=#]

[John Gold]

Continuing on......

It took 638 spins to reach over the +100 unit profit mark.

This is great! You can tell the wife that you are just popping out to try the latest roulette system.
You have an excuse to go AWOL for a few days. 

[attach=#]

[John Gold]

Just over the 1000 spin mark!

check the balance '666' 

So +166 units after 1000 spins.

[attach=#]

[John Gold]

Something else I wanted to see is how long it would take to win a complete bankroll.
If I use the 10 step progression outlined above, it will cost me 184 units.

It took 1,110 spins to make a profit of 186 units and cover myself. (think of the comp points)

I am going to stop this test here. I still think they may be one or two ways to tweak this a bit and make it even better. I will sleep on it.

[attach=#]

cheers.

[John Gold]

I still think they may be one or two ways to tweak this a bit and make it even better. I will sleep on it.

Well, I slept on it for 2 months and can't think of anything! 

Maybe just increase the first section from 8 to 10 because you can get a long run of alternating streets.
It's a grind but holds up well!

[simongae]

hi...
is possible have the DGT file (for Roulette xtreme) for test my 100000 boules ?
thanks  :-)

[schoenpoetser]

I have described a similar system.The sixlines are part of my strategy.I use three strategies.First I account the repeaters.Second Which is a cold sixline.Third how many spins a sixline doesnot repeat.
In more than 35 years the longest sixline in a row was 8.For a cold sixline you must wait at least 12 spins.The betting schedule I use is :1-1-1-1-1-2-2-2-3-3-4.The expectation is the sixline will fall in 23 spins.If you watch my demonstration every system shall pass in the session.For the more experience players two random single streets are also a sixline.3-6-9-12-15-18 Is for me also a sixline etc

[John Gold]

simongae, all my testing is done manually. I don't really know how to use programmes like roulette extreme for long term testing. Maybe someone would like to write a code for this or whatever is needed to do some more tests.

I am able to scan a days results from the german casino which comprises about 300-400 spins and I can roughly work out in about 15-20 minutes how the day would have went.

The method seems pretty solid and I am amazed how many winners it throws up on either first or second bet.
Taking that into consideration, it may be that a martingale type progression is not really a good idea (in fact, when is a martingale type progression ever a good idea) for this method. Maybe a more subtle approach would be better.

Having looked at it again, waiting for 10 consecutive alternating streets in the first part of the charting works well.
I would still keep the qualifying rules at 8+ for the second part of the charting. These qualifying rules seem to throw up plenty of winners early. At the end of the day, it is just another variation for playing dozens.
But if it can help to keep the variance down by using the qualifying rules, it is maybe worth the effort.

schoenpoetser, Thank you for your post,  I will take a look at that. I think the sixlines present a very good opportunity for winning at the game of roulette.

[John Gold]

For a quick example. Here is Table 2 results from today at the Spielbank-Wiesbaden Casino in Germany.

28                      1 (1) 2 (1) 3 (1) 4 (1) 5 (0) 6 (1)
08  Y   (1)          1 (2) 2 (0) 3 (2) 4 (2) 5 (1) 6 (2)
02  Y   (2)          1 (0) 2 (1) 3 (3) 4 (3) 5 (2) 6 (3)
22  Y   (3)          1 (1) 2 (2) 3 (4) 4 (0) 5 (3) 6 (4)
20  N   (0)          1 (2) 2 (3) 3 (5) 4 (0) 5 (4) 6 (5)
28 Y    (1)          1 (3) 2 (4) 3 (6) 4 (1) 5 (0) 6 (6)
29 N    (0)          1 (4) 2 (5) 3 (7) 4 (2) 5 (0) 6 (7)
09 Y    (1)          1 (5) 2 (0) 3 (8] 4 (3) 5 (1) 6 (8]
21 Y    (2)          1 (6) 2 (1) 3 (9) 4 (0) 5 (2) 6 (9)
19 N    (0)          1 (7) 2 (2) 3 (10) 4 (0) 5 (3) 6 (10)
09 Y    (1)          1 (8] 2 (0) 3 (11) 4 (1) 5 (4) 6 (11)
19 Y    (2)          1 (9) 2 (1) 3 (12) 4 (0) 5 (5) 6 (12)
07 Y    (3)          1 (10) 2 (0) 3 (13) 4 (1) 5 (6) 6 (13)
34 Y    (4)          1 (11) 2 (1) 3 (14) 4 (2) 5 (7) 6 (0)
32 N    (0)          1 (12) 2 (2) 3 (15) 4 (3) 5 (8] 6 (0)
33 N    (0)          1 (13) 2 (3) 3 (16) 4 (4) 5 (9) 6 (0)
04 Y    (1)          1 (0) 2 (4) 3 (17) 4 (5) 5 (10) 6 (1)
35 Y    (2)          1 (1) 2 (5) 3 (18) 4 (6) 5 (11) 6 (0)
25 Y    (3)          1 (2) 2 (6) 3 (19) 4 (7) 5 (0) 6 (1)
36 Y    (4)          1 (3) 2 (7) 3 (20) 4 (8] 5 (1) 6 (0)
16 Y    (5)          1 (4) 2 (8] 3 (0) 4 (9) 5 (2) 6 (1)
28 Y    (6)          1 (5) 2 (9) 3 (1) 4 (10) 5 (0) 6 (2)
22 Y    (7)          1 (6) 2 (10) 3 (2) 4 (0) 5 (1) 6 (3)
36 Y    (8]          1 (7) 2 (11) 3 (3) 4 (1) 5 (2) 6 (0)
14 Y    (9)          1 (8] 2 (12) 3 (0) 4 (2) 5 (3) 6 (1)
23 Y    (10)        1 (9) 2 (13) 3 (1) 4 (0) 5 (4) 6 (2)

Here is where the first bet would be. There are 10 alternating six lines in the first part of the charting. So I would bet the 4 looking for a repeat.
The 2 in the second part of the charting is the furthest back. So I am betting the 4 (19-24) and the 2 (7-12)

09 Y     (11)        1 (10) 2 (0) 3 (2) 4 (1) 5 (5) 6 (3)

So that was a winner at the first attempt  and a gain of +4.
Now I would bet for the 2 to repeat and the 1 is the furthest back. So I am betting on 2 and 1.

15 Y     (12)       1 (11) 2 (1) 3 (0) 4 (2) 5 (6) 6 (4)

That was a loss of 2 units and I am back to +2 in total.
Now I would bet for the 3 to repeat and the 1 is the furthest back. So I am betting on the 3 and 1.

19 Y     (13)       1 (12) 2 (2) 3 (1) 4 (0) 5 (7) 6 (5)

That was a loss of 2 units and I am back to level.
Now I would bet for the 4 to repeat and the 1 is the furthest back. So I am betting on the 4 and 1.

02 Y     (14)       1 (0) 2 (3) 3 (2) 4 (1) 5 (8] 6 (6)

That was a winner and back to +4 again in total. (this is assuming I am flat betting and not using any progression)

Now I would bet for the 1 to repeat and the 5 is the furthest back. So I am betting the 1 and the 5.

34 Y   (15)      1 (1) 2 (4) 3 (3) 4 (1) 5 (9) 6 (0)

A loss of 2 units and back to +2 in total.
Now I would bet for the 6 to repeat and the 5 is the furthest back. So I am betting on the 6 and the 5.

03 Y   (16)     1 (0) 2 (5) 3 (4) 4 (2) 5 (10) 6 (1)

A loss of 2 units and back to level again.
Now I would bet for the 1 to repeat and the 5 is the furthest back. So I am betting the 1 and the 5.

06  N  (0)       1 (0) 2 (6) 3 (5) 4 (3) 5 (11) 6 (2)

A winner and the total is back to +4 again.

Now that the first charting part has reset itself to zero, it could be a while before there are any more bets. It can be a bit of a grind but the qualifying rules seem to promote a lot of early wins.

I was not using a progression in the above example but I suppose you could make one up to suit your personal taste.

[schoenpoetser]

JG I have studied the sixline with excel and a pseudo RNG.In the real casino it is my favourite strategy.For a test sample you need a verylarge sample.
If you think for EC is a sample of 300 spins enough than you need a 900 sample for  the dozens and a 1800 sample for the sixline.Your idea is very good but in practice,in my opinion,to complicated.I can send you excelprograms

[schoenpoetser]

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