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STREET ROULETTE SYSTEM THAN RESIST MILLONS SPINS TEST!!

Started by Alejo Ceballos, March 25, 2016, 07:08:33 PM

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Alejo Ceballos

I have found in the programme "Wave funtion" that if you bets only the 10% of the programme said the programme win as well, but the progression don't go up!

Alejo Ceballos

Today, I have tried an Atila progression to the last 12 sleeper numbers with a lot of success...

Alejo Ceballos

To make more efficient my system "Wave funtion" you can play it on last sleeper number...

Alejo Ceballos

Easy way to play "Wave funtion" roulette system:
You bet 1 chip to 1 number during a cycle of 36 balls, if you don't win anything you bet 2 numbers for 36 more balls, doubling the value of the bets.  If you don't win anything, you bet on 3 numbers for 36 more balls, doubling the bets and so on until you win something.  At the lowest win cut and start over with a single number x1 chip from the beginning.-

Alejo Ceballos

...now I am trying with cycles of 100 balls for more resistant...

Alejo Ceballos

I am experiencing a new type of martingale in chokehold.  I start by betting only 1 number (always for one unit), if it loses I bet 2 numbers (always for one unit), if it loses I bet 4 numbers (always for one unit), if it loses I bet 8 numbers (always for one unit), if it loses I bet 16 numbers (always for one unit), if I lose I bet 32 ​​numbers (always for one unit), if I lose this bet of 32 chips I cancel all bets and start from the beginning for 1 single number (always for one unit).  When I win a bet, I cancel all the bets and start from the beginning with only 1 number (always for one unit).  The balance of capital oscillates up and down all the time, but in the long run it leaves more profit than loss.  Try it!

Alejo Ceballos

A reduction algorithm can be used to hit roulette.  Sometimes having more data is not always good.  You can collect the numbers that come out in your bet.  To the last new number that comes out you add it to the bets by one chip, and you increase one chip to the previous ones.  In this way the oldest will have more chips.  Since the probability that 37 different numbers will come up in 37 roulette balls is close to impossible, you will see how the numbers you collect will be repeated to you.  Older ones with more chips are more likely to come out.  So at the first hit cut and start again from 1 number.  Check it!

Alejo Ceballos

And Also... with an Oscar's Grind progression on last dozen that has came you can make a profit because one dozen will come more that the others because the desviation of the tablet...

Alejo Ceballos

The Martingale of a lifetime consists of contributing 1 and if we lose, double down until we win, so that what is lost is recovered

and a unit is gained.  This system always fails because we get the consecutive Reds or Blacks (in our case HI/LO) necessary to make us lose and the roulette software has it quite easy, from time to time it rolls 17 Reds or Blacks in a row and the game is over. Martingale.  What is true and can be verified is that if we write down a sufficient number of throws, for example 1000, in the case of Roulette 30 "0" would come out, 485 Reds and 485 Blacks, nobody can complain that they have bad luck, what happens is that with the Martingale we bet exactly everything, to which we lose.



The system that I propose we roll betting 1 unit randomly does not matter HI or LO and if we lose we continue betting 1 unit.  When we win we double the bet, if we win we bet 1 again and start again and only double when we win again.  If we lose we bet 1 again, but the next time we win we bet 4 instead of 2. If we win we bet 1 again and start the system again.

What we are looking for for the Martingale is not to lose the previous one, with which we end up betting many times in a row by doubling.  We only double when we beat the previous one.



Summarizing:

1. When betting, change from HI to LO randomly, in reality it does not matter where you bet, what we are looking for is to win 2 times in a row.

2. If we ever do it wrong, that is, we have won 1 unit and we would have to bet 4 on the next one (since we have lost one of 2) and we make a mistake and bet 1, it does not matter we can bet the 4 units on the next one.

3. What this system tries to break is with the consecutive rounds doubling to the same place, thinking that this will not happen more than 10 or 12 times in a row.  It can really be done in many ways, another one is by betting the following amounts on HI/LO randomly:

1-1-1-1-2 if we win we start over and if we lose:

1-1-1-4 if we win we go back to the beginning and if we lose:

1-1-1-1-8 if we win we go back to the beginning and if we lose:

1-1-16 and so on.

How many times a unit is bet in each round does not matter exactly.  What matters is that we double down at a given moment until we win either with a predetermined sequence, as in the previous case, which we did every time we won, or with a random sequence on the fly.



With the following variant for a balance of 16,000 satoshis, we would do it in the following way:

1-1-1-1-4 if we win we start over and if we lose:

1-1-1-8 if we win we go back to the beginning and if we lose:

1-1-1-1-16 if we win we go back to the beginning and if we lose:

1-1-32 and so on.

What we get is to win 3 units instead of 1, per complete chain.  All the rolls in which we bet a unit will affect us in such a way that we will lose 5% of all those rolls, but we win more with the Martingale.



As we increase the balance we can increase the first jump which will give us more profits.



If we start with 8000 satoshis we can endure 13 losing spins in a row with a probability of 1/8000 that we lose everything, it is almost like the probability that we win the Christmas lottery.

If we do the Martingale of a lifetime we will be perplexed as in 20-30 minutes it has already happened to us.  It doesn't matter if we stay for 5 minutes, we leave and come back later, the casino software waits patiently for us with the same destructive sequence of Martingales.

Alejo Ceballos

Diversified Martingale: The classic Martingale doubles bets on a single chance to the table maximum to lose it all.  What I propose is to diversify the martingale on 3 simple chances at the same time.  When two or more chances lose, the bets on the 3 chances will be doubled and when 2 or more chances win, the bets will be restarted at 1 unit on the 3 chances.  Open fluctuations, the capital will go up and down, but in the long term it will leave profits.  In ancient China, boats were made of wicker and sank.  So the Chinese divided the merchandise into several ships, some sank and others reached their destination, ensuring that some merchandise would always reach its destination.  Try it!

Alejo Ceballos

Systems like the Martingale are fusion, because they join or merge more and more chips to the bet to produce a profit.  Sometimes it consumes more tokens than it produces.  It occurred to me to create a fission system, that is, play fewer and fewer chips and win more prizes at roulette.  To generate fission money, we will play 6 different streets, (half of the table), for example, the minor ones.  Every time we win on one of our streets we sweep it or remove it from the bet as it comes out, one by one, until all 6 streets are swept, then reload all 6 streets again and sweep them again each time. they go out  In this way money will be produced by fission of chips, in the long run in roulette, without using any progression.  You can do it with the value of chips you want.  Try it for yourself!

Alejo Ceballos

... but if you finish to clean all the street and you did not win nothing, you can start again this system, but with a double value on all the street...

Alejo Ceballos

... an easy way to play it is on 2 dozens... (no maximun problem)...
:-) Cheers!

Alejo Ceballos


Alejo Ceballos

A new type of "Split" Martingale can be created.  If we open a classic Martingale to 2 dozen we would have to triple the bets every time we lose over 2 dozen (for example first and second dozen).  The stakes would go way up and we'd hit the table highs pretty soon.  The solution I found is to triple only the first dozen and leave the second dozen with 1 unit.  If you lose again then triple the second dozen as well and leave the first at 3.  If you lose again, triple the first dozen and leave the second dozen at 3.  If you lose again, triple the second dozen and leave the first dozen at 9... and so on... When one of the 2 dozen hits once, reset the 2 dozen to 1 unit, to start all over again.  It won't make money on all balls, but it will leave positive profits on average over time... Very safe.  Check it out and try it for yourself!

Alejo Ceballos

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