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100 % ?

Started by J.Daniels, February 13, 2008, 09:27:24 AM

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J.Daniels


J.Daniels

I got a question and I would be very grateful if someone answer:

Is it a 100% event that in a cycle of 37 numbers at least 1 number will repeat? or in another words:

in a cycle of 37 numbers, NEVER 37 DIFFERENT numbers will show up?

Thanks

JD.

admin

I doubt you could find in a natural real wheel sample a 37-number sequence without a repeat. I repeat NATURALLY, meaning the sets you play for real money manually at the real table.

If you [highlight]bruteforce[/highlight] the 37-spin sequence with an array/cluster of powerful computers working all day long generating RNG numbers until there is a sequence of "no repeats", then it means you are a math-boy... doing so just to have the last word!




Remember, if you ask the math boys they will say any combination of 37 numbers is the same, no difference in probability.

So, the accepted thing is : 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37
is as likely as the last 37-spin set you withnessed and it is TRUE in the terms of probability. But guess what? Playing naturally (as said above, without a computer-based RNG bruteforce) I won't bet my life for finding it in real money play :)

J.Daniels

[highlight]THANKS[/highlight] victor for your answer

Then if this is a hardly ever event, we can make good use of it. I mean according with this fact, we could arrange a progression within a cycle of 37 spins betting the numbers that are showing up. Or better wait a certain group of numbers that didnt repeat in the beginning of the cycle and then start the progression. As long as we know we have a nice percentage to win in the cycle, it wouldnt be a problem a losing cycle once or twice. I think its a good idea.

Ill work on it.

JD.

J.Daniels

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