NEW KEN'S SYSTEM

[Natural9]

Hello,

Yes a progression on each dozen of 1,3,9,27. I think its best if you stop at the 2nd loss and start again.

Yeh Second loss might be ok

Ok I got you as usual we need ask the question how often will a progression lose and if it does lose can we recover will losses kill our BR

I mean one can just play LD that works quite wel ltoo just ask Lanky and Victor


Regards Rodney

[sean43]

Yea 2nd loss is going good so far, what do you mean by LD sorry? Heres some more

34      3   W
6      36   W
27      9   W
5      31   W
1      26   W
29      36   L
7      6   L
1      14   W
8      33   W
31      36   L
33      35   L
34      28   L
23      34   W
5      32   W
34      26   L
21      9   W
21      21   L
27      23   W
34      31   L
11      2   L
25      9   W
3      34   W
3      7   L
35      30   L
17      36   W
20      11   W
21      32   W
18      9   W
35      8   W
5      4   L
22      10   W
8      32   W
30      35   L
23      21   L
24      7   W
16      7   W
11      21   W

+23

[hermes]

I can guarantee you that there will be never carbon copy of 38 spins but I can guarantee you also that sometimes there will be a carbon copy of 10 spins even when you will bet 2 dozens against one. You can bet 10 spins against 10 spins like that:
10 Dozens vs 10 dozens    x= loss
2        1
1   x    1     
2   x    0
1        3
1        2
1   x    1
2        1
2   x    2
2   x    2
1   x    1

Good luck
Hermes

[Natural9]

LD last dozen

[New Ken]

Thanks for examining my system, guys.

Ok, first of all I'm not playing dozens. I'm playing 20 nos, and I always will be playing with the zeros (but if a zero appears in the first 38, I skip that particular spin). I'm playing four groups (see above), and the three columns. Every no. (except the zeros) belongs to a group and column.

I'm playing not only against the numbers ( and their groups, cols) of the first 38 spins---I'M PARTICULARLY PLAYING AGAINST THEIR ORDER OF APPEARANCE.

What are the odds of six consecutive number groups and cols REPLAYING IN THE EXACT ORDER AND POSITIONS of the previous 38 spins?

(I

[New Ken]

..I will call each position in every 38 spins a "slot place".

So the first number of every 38 spins will be "Slot 01", followed by Slot 02, Slot 03, etc. down to Slot 38.

What are the odds of, say, slots 05, 06, 07, 08, 09, 10 carrying the same number groups and columns---in two consecutive 38 spins?

What do the math and probability gurus say on this, I'd like to hear.


New Ken

[cps10]

Thanks NEW KEN!

I will take a test really quick. Will report some later.

[cps10]

Hi NEW KEN,

Just did a test of 369 spins...unfortunately, I did find a bad streak...there was a 9-spin losing streak at one point. There were also 6 total losses of 5 spins within the group.

One thing I think would work would be to wait for a 5-spin loser. If it happened every 60 spins or so, then you are really going through one cycle before seeing it come up. That way, since the highest losses I have seen so far is 9, then you are looking at a 4-step progression MAX right now.

Just my two cents...I will continue to test more.

This batch:

369 spins, Hi: 16, Lo -2920, End -2872 (yes, I hit a loss right out of the gate).

[New Ken]

Thanks, cps10---are you saying that a streak of nine consecutive spins from one 38 perfectly mirrored that of the previous?

Get back to you on that...


Here's a test using the same nos---but I'm only playing against the previous six spins.

Biggest losing streak is 4 losses!



TESTING NEW KEN'S (NEW?) SYSTEM


New approach---here I don't wait for 38 spins.

I am simply playing against the previous six spins.



From Jim Ferr's Actuals---(76 nos, consecutive spins)

8 17 36 33 27 6 2 20 25 31 32 36 20 26 9 00 4 30 20 24 11 33 5 15 16 6 3 16 00 16 32 36 33 1 30 32 4 13 10 34 17 30 21 36 18 29 14 19 21 18 16 26 3 17 11 26 32 1 5 11 21 35 32 26 4  8 29 28 19 27 1 25 18 0 31 17



Start:


8   17   36 33  27  6


2   20  25  31  32 36
L     L    W   L   W   L

20   26  9   00  4   30
L      L   W  W  W   L

20 24  11  33   5  15
L    L   W   na*  L   L


16  6    3  16   00  16
W   L   W   W   W   L



32  36  33  1   30   32
W   L    L    L  na*  W






4   13  10  34  17  30
W   W   W    L    W    L





21  36  18  29  14  19
W   W   L    L    L    W



21 18  16   26  3   17
L    L    L     L   W   W




11 26  32   1   5   11
W  W   W   W   L    L





21 35  32  26   4  8
W  L    L    W    L    L




29  28 19  27 1  25
W   L   W   L   L   W


18   0   31  17
W   W   L    W

[cps10]

Okay...that isn't bad either.

I will modify my most recent test for that. The most recent was for 392 spins:

Longest streak was 8.

Hi: 1,020
Lo: -3,252

End: -2,400

As you can see, it gets streaky.

[cps10]

Okay, modifiying it to the last 6 spins was a little better:

392 spins
Hi: +1081
Lo: -759

End: -287

Losses: 4

Long Streak: 9

[Natural9]

They are huge Drawdowns not sure my stomach could handle that

[New Ken]

TWO 4 STEP PROGRESSIONS FOR New Ken's Modified System


20 nos x 1=   20—win 15
20 nosx 2=    40—win 10
20 nosx 5=   100—win 15
20 nosx 12=  240—win 20

ABOVE PROGRESSION--$400

20 nosx 2= win 30
20 nosx 4= win 20
20 nosx 10= win 30
20 nosx 24= win 40

above progression---$800

Modified SyStem---$1,200 BANKROLL (---CATERS FOR 2 WIPEOUTS).

USING MY MODIFIED SYSTEM (PLAYING AGAINST LAST SIX SPINS), I WAIT FOR TWO Ls THEN BEGIN PLAYING.

TO LOSE  1ST $400 THERE MUST BE 6 Ls IN A ROW. (after 6Ls, I wait for entire series of losses to finish before beginning again)

TO LOSE next $800 THERE MUST BE ANOTHER 6 Ls IN A ROW. (after  SECOND 6Ls THEN I'VE LOST)

ARE BOTH losses GOING TO HAPPEN regularly?


The testers are wonderful,--- but where are the math and probabilities people on this forum??



(USING SAME JIM FERR'S ACTUALS ABOVE, I WIN AVERAGE $110 ---PLAYING ELEVEN TIMES AFTER ELEVEN 2L'S---WITHOUT GOING INTO SECOND BANKROLL PROGRESSION)

SO, THERE.

[New Ken]

HERE I GO AGAIN...


Using the same recorded 76 nos as before, I look for where the REPEAT nos EMANATED in the first 38 nos.

I decide the new repeat nos will emanate from elsewhere in the new string of 38 nos.

In the new 38, I will not play in those slot places where the first repeat nos emanated.

I stop after two hits (whether in profit or not).


double asterisks(**) shows where repeats emanated--single asterisks(*) show where hits occured

first 38 spins on left (L)---second 38 spins on right(R)


(L)          (R)
         
8             10 
17            34
36 **       17 no play
33 **       30 no play
27            21 **
6  **        36  no play
2             18 **
20 **       29 no play
25            14
31            19
32 **        21 no play
36 *         18 *first hit  (10x6units, 34x5, 21x4, 18x3, 14x2, 19x1 )   

expense  = 21 units

WIN 15



20 *          16
26             26
9                3   
00 **        17 no play
4  **        11  no play
30 **        26 no play
20 *          32
24             1   
11             5   
33 *         11
5              21 *second hit (10x14 u,
etc                       34x13,21x12,18x11,14x10,19x9, 16x7, 26x6,3x5,32x4,1x3, 5x2,11x1

      units expense overall =97 units


WIN $43 OVERALL-----23 SPINS, all flat bets, single units


wait for new 38 to complete, reset.


Now, I need a TESTER...

[New Ken]

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