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System based purely in Maths

Started by gingermolloy, January 02, 2009, 01:14:30 PM

0 Members and 1 Guest are viewing this topic.

gingermolloy

Quote from: Proofreaders2000 on January 10, 2009, 02:08:08 PM
I see you started out with .20 pence on the first attempt, so I started the betting at $1.00 and used a progression of 1,4,6,10,15,22,32,46,65,91 to coincide with you progression in British Pounds. 

I betted each time there were 10 unique numbers that were hit only once.
Each time a number hit, I resetted the progression back to $1.

Out of eleven attempts, there was only one hit.  Attempts 2-11 were misses.

Once you reset the progression you must wait for another 10 consecutive non repeaters to bet on!!!!!!!

gingermolloy

Konfused!

I think your approach is mathematically right if you treat each stage of the progression individually.

We know that the wheel cannot be beaten on a single spin basis, that is why we must bet on multiple spins by using a progression.

Think of my system as a bet on a set of 10 spins, rather than 10 bets on 10 individual spins!

I am betting that 1 of 10 numbers will appear in a set of 10 spins.

Where i win in the progression is of no consequence.

It is whether it happens at all that is important!

ginger

Kon-Fu-Sed

Dear gingermolly,

I am sorry but what you write here is not correct:
Quote

We could say that the average number of spins taken to win would be the average.
i.e. (1+2+3+4+5+6+7+8+9+10)/10 = 5.5 spins
The amount of money won in 5.5 spins (underestimated) is 5.5 x £7 = £38.5
So the average money won from the successful progression is £38.50.


The average amount of spins to win is far less...

You forget that you bet sooo many more times on the first stage than on the last because you quit on a win.

For the first stage you win 27,028 in 100,000 spins
For the second you win 19,723 in 72,972 spins
3rd stage is 14,392 hits in 53,249 spins
4th stage is 10,502 hits in 38,857 spins
5th stage is 7,664 hits in 28,355 spins
6th stage is 5,593 hits in 20,691 spins
7th stage is 4,081 hits in 15,098 spins
8th stage is 2,978 hits in 11,017 spins
9th stage is 2,173 hits in 8,039 spins
10th stage is 1,586 hits in 5,866 spins

Total is: 95,720 hits in 354,144 spins = 3,6998 spins to win x 7 = 25.898

So the average money won from the successful progression is £25.90
and for every progression lost (£584) we will win 22 (22 x £25.90) = £569.80

For each progression lost we will lose 14.20

Sorry :(


But please don't give up!
KFS

gingermolloy

Example on real spins!!

The trigger to begin the progression is when the last 10 numbers are all different from each other.

1 wait
9 wait
29 wait
17 wait
18 wait
29 repeater
17 repeater
9 repeater
18 repeater
32 wait
21 wait
27 wait
32 repeater
23 wait
22 wait
13 wait
4 wait
24 wait
9 wait
21 repeater
36 we now have 10 unique numbers (27 32 23 22 13 4 24 9 21 and 36)

so on the next spin we bet £0.2 on these 10 numbers

16 lose

bet £0.8 on them

17 lose

bet £1.2 on them

7 lose

bet £2 on them

11 lose

bet £3 on them

27 win £108

now we must wait for 10 consecutive unique numbers again.

we already do ( 27 11 7 17 16 36 21 9 24 and 4)

26 lose
2 lose
24 win

bet 24 2 26 27 11 7 17 16 36 and 21

20 lose
12 lose
1 lose
35 lose
27 win
24 repeater
16 wait
10 wait
11 wait
5 10th number

bet 5 11 10 16 24 27 35 1 12 and 20

36 lose
0 lose
15 lose
30 lose
32 lose
10 win

for every spin that was part of a progression we won £7

I rest my case

ginger

Kon-Fu-Sed

Quote

for every spin that was part of a progression we won £7


Yes, that's fine with me. I also wrote:
Quote

spins to win x 7 =


I said that your average number of spins to hit (5.5) is waaay too high: it's in fact (mathematically fact ;)) 3.6998


Best regards,
KFS

gingermolloy

Quote from: Kon-Fu-Sed on January 10, 2009, 03:10:52 PM
Dear gingermolly,

I am sorry but what you write here is not correct:
The average amount of spins to win is far less...

You forget that you bet sooo many more times on the first stage than on the last because you quit on a win.

For the first stage you win 27,028 in 100,000 spins
For the second you win 19,723 in 72,972 spins
3rd stage is 14,392 hits in 53,249 spins
4th stage is 10,502 hits in 38,857 spins
5th stage is 7,664 hits in 28,355 spins
6th stage is 5,593 hits in 20,691 spins
7th stage is 4,081 hits in 15,098 spins
8th stage is 2,978 hits in 11,017 spins
9th stage is 2,173 hits in 8,039 spins
10th stage is 1,586 hits in 5,866 spins

Total is: 95,720 hits in 354,144 spins = 3,6998 spins to win x 7 = 25.898

So the average money won from the successful progression is £25.90
and for every progression lost (£584) we will win 22 (22 x £25.90) = £569.80

For each progression lost we will lose 14.20

Sorry :(


But please don't give up!
KFS



I think you are right!

this would give the house a 2.43% advantage.

I concede that your maths are right on this point.

I suppose this 2.43% advantage is better than the 2.78% enjoyed by the house on a single spin.

It must be the waiting for the 10 unique numbers that makes this system work so well.

Thanks for your clarification.

ginger

TwoCatSam

Guys

I find this very interesting as I have been down this road many times.  At the end of the road was a big, black dog that always bit me arse!  Let me reduce this to the question I always asked:

What are the chances of loosing the progression  vs  how much will I make each time I don't loose the progression?  If I read correctly, Ginger says we will loose the progression once in 23 at-bats.  The question is, on the progressions we don't lose, do we overcome that one in twenty-three?

I'm going to study on this will 1 unit bets and a unit is whatever you may call it. 

This is very interesting!

Thanks GM

Sam

gingermolloy

Quote from: Kon-Fu-Sed on January 10, 2009, 03:10:52 PM
Dear gingermolly,

I am sorry but what you write here is not correct:
The average amount of spins to win is far less...

You forget that you bet sooo many more times on the first stage than on the last because you quit on a win.

For the first stage you win 27,028 in 100,000 spins
For the second you win 19,723 in 72,972 spins
3rd stage is 14,392 hits in 53,249 spins
4th stage is 10,502 hits in 38,857 spins
5th stage is 7,664 hits in 28,355 spins
6th stage is 5,593 hits in 20,691 spins
7th stage is 4,081 hits in 15,098 spins
8th stage is 2,978 hits in 11,017 spins
9th stage is 2,173 hits in 8,039 spins
10th stage is 1,586 hits in 5,866 spins

Total is: 95,720 hits in 354,144 spins = 3,6998 spins to win x 7 = 25.898

So the average money won from the successful progression is £25.90
and for every progression lost (£584) we will win 22 (22 x £25.90) = £569.80

For each progression lost we will lose 14.20

Sorry :(


But please don't give up!
KFS

Sam

see the above post by Konfused!

the 22 wins doesn't make up for the 1 loss!!! we end up £14.20 down.

But i think the waiting is the key factor here, that combined with the 95.7% chance of winning £7 a spin makes this a winning system.

I have not beat the maths as I thought i had! but the system has still never failed.

I think it is the same reason Wikels GUT works!

speedomes

Hi guys, have been tuning in and out for months. Just wondering if waiting for a set of 10 numbers that have not shown for say 25 spins (or more?) would change the outcome of this system?
Great thread
cheers
Mike

TwoCatSam

OK, Ginger or some European person.......

What is the little "P"?  Is it pence?  How many little "p"s in a pound?

Does 4.40 mean 4 pounds and 40 "p"?

Could we equate an American penny to a "p" and an American dollar to a Pound?

Sam

gingermolloy

Quote from: TwoCatSam on January 10, 2009, 06:16:34 PM
OK, Ginger or some European person.......

What is the little "P"?  Is it pence?  How many little "p"s in a pound?

Does 4.40 mean 4 pounds and 40 "p"?

Could we equate an American penny to a "p" and an American dollar to a Pound?

Sam

hahahahaha

sorry i forgot this is international

£ or GBP or pound is 100p

so yeah 1.2 means 1 pound and 20pence

its just the same if you do it with dollars and cents (if there are 100 cents in a dollar)

ginger (British)

TwoCatSam

Ginger

Thanks!  I thought that was it, but I wanted to be sure.

Yes, we are the world on this forum.  From Ireland to Australia and everywhere in between.  (Why did I just think of a kangaroo with a leprechaun in her pouch?)

Too much dust in the brain~~~!

Sam

Diarmaid

Quote from: TwoCatSam on January 10, 2009, 06:25:06 PM
Ginger

Thanks!  I thought that was it, but I wanted to be sure.

Yes, we are the world on this forum.  From Ireland to Australia and everywhere in between.  (Why did I just think of a kangaroo with a leprechaun in her pouch?)

Too much dust in the brain~~~!

Sam

LOL   TCS, you crack me up sometimes.  ;D

Jakkalsdraai

 ;) Hi Ginger,

Nice to see you back mate. I am playing other ways currently but I am always interested so thanks again and i will give it a go.

Cheers mate

Jakk

winkel

Quote from: gingermolloy on January 10, 2009, 04:03:14 PM
I think it is the same reason Wikels GUT works!

sorry, but you are wrong:

GUT works because
1. it is flat bet
2. it doesn´t bet always the same amount of numbers

it works because:
betting e.g. 10 numbers will make you win or lose and in the long run you will lose 2,7% of your wager
GUT is betting different amounts of numbers,  if  10# lose, 11# will win, if 12# lose 9# will win.
There is no danger to run in a losing streak that is too long to survive or to recover.

pls explain:
you started with Grand Martingale
now you are betting
0.2 1
0.8 4
1.2 6
2 10
3 15
4.4 22
6.4 32
9.2 46
13 65
18.2 91
which is not the GMg

You made a test-Area where should Red/Black be tested with just 4 bets. ? ? ?

Where is the red hering?
On what argument do you have your advantage that compensates the house-edge?
What is the point of waiting for 10 numbers? Why not 6 or 9 or 5 or even 1?

br
winkel

winkel

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