I have a new puzzle to solve.
Bet one unit on every chance of dozen three.
The next three spins are dozen 1, dozen 3 and dozen 2
Have you a profit, a loss or do you play quits ?
Please explain your answer.You can sent your answer also to rouletteplayersclub@hotmail.nl . I shall later on publish the results.
This problem is not very difficult.Though nobody report me the answer.Most designers of complicated betting schemes have no idea of the relation between the pay out for the different spins.This puzzle is a step forwards.
It is difficult to grasp exactly what you mean, but from my understanding I would quit after the second spin with 1 unit profit.
Bomber it is not the correct answer .Some have a problem ,what I mean with bet one unit on all chances.You must not only bet the numbers but also splits ,corners and so on.
So you are betting 1 unit on the third dozen for 3 spins and the results are dozen 1, 3 and 2 ?
In that case, you will break even, losing the 2 units total on the first+third and winning 2 units on the second spin.
The most balanced way to bet all the Doz 3 chances is by putting an extra .5 units on splits (25,28) (27,30) (31,34) (33,36). The total outlay would be 31 units, and no matter what number hit you would collect 62 units.
So a hit with doz 3 on the second spin would give 31 units proift. You could quit there, or push on to spin 3 and risk breaking even or gaining 93 units.
Why not just put 30 units on doz 3?
(https://www.vlsroulette.com/proxy.php?request=nolinks%3A%2F%2Fi499.photobucket.com%2Falbums%2Frr351%2Fskakus%2Fsspuzzle.jpg&hash=df1488fa6fd0ae21cf6786bc1b7058a9071a2cb8)
Bombus we come closer to the answer.The guestion is not what the best bet is.All chances must bet with one unit.
You have forgotten some splits.
Try again!
Free roulette your answeris not correct.
I see 265 viewers and still no correct answer.Is the puzzle so difficult?Try to solve the puzzle and learn the
mousetraps of systems most designers make.
On the forum we have some experts in roulette.Bombus has done a try.He was on the right way.Where are the other experts?You need no maths to solve the puzzle only common sense.
Has nobody "the common sense"to compute the answer?I am still waiting for the real roulette player.
Quote from: schoenpoetser on May 04, 2011, 09:16:28 AM
Has nobody "the common sense"to compute the answer?I am still waiting for the real roulette player.
Actually, I don't understand the question. Every time I think I do, I read it again and something else comes to mind.
Is there a chance you could clarify just what it is we're looking for or what are we trying to accomplish?
AD
schoenpoetser ,
It's not clear what you are asking. Is understanding the question, the riddle itself?
I thought it was clear when I wrote bet one unit on all chances of the last dozen .
12 numbers 12 units
4 streets 4 units
3 sixlines 3 units
6 corners 6 units
17 splits 17 units
1 dozen 1 unit
total 43 units.
The next spins are do 1,do3 and do2
Do you have a profit or do you lose?.Perhaps you play even.(equal )
Doesn't it depend on which number of the winning dozen the ball lands? For instance, if the winning number is 25, then this only includes 2 splits and 1 corner, but if it lands on 29 you will get payouts from 4 splits and 4 corners.
Quote from: Mike on May 05, 2011, 09:49:28 AM
Doesn't it depend on which number of the winning dozen the ball lands? For instance, if the winning number is 25, then this only includes 2 splits and 1 corner, but if it lands on 29 you will get payouts from 4 splits and 4 corners.
That's right, it's a drawn out answer... unless there's some twist, of course.
That's why I posted the balanced version earlier.
In this scenario,
If on spin 2 the winning number is 25,26,27,34,35,36 I would not bet the third spin.
25,27,34,36 giving 16 units profit.
26,35 giving 43 units profit.
If on spin 2 the winning number is 28,29,30,31,32,33 I would continue betting on the third spin.
28,30,31,33 giving 6 units profit.
29,32 giving 42 units profit.
Yes the answer is wright.It depends on the falling numbers in the third dozen.The common player with less experience should say there is no profit.
The numbers 25-27-34-and 36 give a lost.
29 and 32 give a profit.
The other numbers play even money.
The conclusion is, you must be carefull when you design complicated systems.Look allways what every number shall payout.
A system with the less number of units per spin is the best.
Try to compute the edge after all numbers are fallen in 37 spins.The answer should not be a surprise.
Does solving this puzzle teach us anything worthwhile or is it just for grins?
I can't imagine playing roulette in a way that requires a bet on every chance on a dozen.
I haven't heard anything about Red/Black, Even/Odd, High/Low. Those are chances in the 3rd dozen. :girl_wacko:
From this puzzle you can learn a lot.
1) complicated systems have no advantage on a simply one.
2) the loss is higher playing a big number units per spin.
3) one unit on an EC is the best system
4) with a simply system it is easier to play a strategy.
5) with a simply system you can compute the risk.
6) with a simply betting schedule you have more time to make decisions and place your bets.
Have you try-ed to compute the edge of 37 numbers? That is very instructive.
The total betting of 37 spins is 37* 43=1591 units.
Total pay out 1548 units.Lost 43 units. EV or house edge 43/15,48= 2,7. No surprise!!!