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LAST WON COLS DOZENS tweak check newest update.

Started by bikemotorman, December 27, 2009, 09:58:49 PM

0 Members and 6 Guests are viewing this topic.

bikemotorman

BETATESTER,


ARE YOU PLAYING THE WAY I AM SAYING LAST WON TWO COLUMNS THEN LAST WON TWO DOZENS.

LAST DOZENS THEN LAST COLUMNS IS NOT THE SAME AT ALL.

PLEASE TEST IN THE ORDER THAT IS BELOW. :no:

PLAY YOUR TEST THIS WAY BELOW, YOU MUST START WITH THE COLUMNS.

I AM ALSO USING A SAFER PROGRESSION SEE.  5=10=15=25=40=65=105=170

THE ABOVE IS IN DOLLAR AMOUNTS ON YOUR PAIR OF COLS OR DOZS YOU ARE PLAYING.

I SOMETIMES COVER ZERO WHEN THE BETS GET HIGHER.


HERE YOU GO PLAY THIS WAY ONLY.


LAST WON COLUMNS
LAST WON DOZENS
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DONE

STUART :) :) :) :) :) :) :) :)

fqbien

I've give a try to this this afternoon.

Using 10c bets, went from 7,5€ to 35€, playing something like 1hour.

Not bad, but i was playing on last dozen hit, then last column hit (so just 1 each time).

So, i have not the system .. can you give an example with numbers and what to bet ?

bikemotorman

OK IF YOU ARE PLAYING LAST SPUN OR WON COLUMNS, OR LAST SPUN OR WON DOZENS LOOK BELOW.


THE LAST SPUN NUMBERS

1
3

THE LAST SPUN COLUMNS ABOVE WOULD BE COL ONE AND COL THREE YOU PLAY BOTH.

THE LAST SPUN NUMBERS

7
36

THE LAST SPUN DOZENS ABOVE WOULD BE DOZEN ONE AND DOZEN THREE YOU PLAY BOTH.

IT IS THAT SIMPLE YOU ARE ALWAYS PLAYING THE LAST TWO COLUMNS THEN THE LAST TWO DOZENS.

LAST WON COLUMNS
LAST WON DOZENS
LAST WON COLUMNS
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ARE WE CLEAR ON THE ABOVE.

THANK YOU

STUART :) :) :) :) :)

fqbien

Ok, think i got that.

But if you bet 5 on each two columns/dozens, your progression may be wrong.

5 x 2 = 10 , expected winnings are 15.
10 x 2 = 20, + 10 previous bet = 30 , expected winnings are 30.
15 x 2 = 30, +30 previous bet = 60, expected winnings are 45 ...

What i've not understand ?

bikemotorman

You put five dollars on each on each of your pair of cols or dozs but if you want to ad the 2 together that's ok.
The nearest casino has a five dollar minimum per doz or col.
If you bet five dollars on each of your pair you net 5 dollars if you win its that easy.

Are you in the states or Europe.

Stuart

fqbien

Ok, but if you loose, what the next bet ?

It must recover losses no ?

I'm in europe, from France.

fqbien


fqbien

With the other method (last column, then last dozen, etc.. and only one) i've win to spin 10 max.

It never loose, and never go to 11th spin while betting.

Progression used (in chips) : 1-2-3-5-8-13-21-34-55-89

So 10 spins max. Someone can test that or it's for sure a looser on the long run ?

hermes

French, if it wins more than lose it is still winner. Don't be scared, test more.
It is good system if you can wait for 3 virtual losses and than apply progression.
hermes

VICLIMKS

Bike..........how much n when  only do you start covering 0......pls.advise...thz :give_rose:

betatester

Hi @bike. Hi forum.
Well. You confused me too, with the progression.
What do you do when at the end of "n" steps you have one win and you don't recover the loses ???
Accept the lost units ? adjust the progression ? divide the amount by two expecting 2 consecutive hits...
If so what happens if you lost one of those 2 trials...: Accept the lost and come back to one...
Anyway... this wouldn't give you any edge.

And yes... I have an error in my program.
odd spins played first the dozens.
(some times you haven't 2 clear dozens or columns in the 3third spin.
But if you have then is in a odd spin first.

I've also committed one mistake when publishing the table results.
So in the search of consolidated results I can correct the next:

One full Weisbaden month (real spins by human dealers)
14636 spins

If I start with 2 last DOZENS in spin 3 and in all the odd spin I have exactly this:

1   2225 <<< I publish here another figure)
2   767
3   253
4   91
5   26
6   9
7   4 *
8   1 *
9   1 *
10   0
11   0
12   0
13   0
14   0
15   0
16   0
17   0
18   0
19   0
20   0
   3377 (results)

If we start playing the 3thrd spin (first odd, and all the odds) the TWO LAST COLUMNS, for your surprise, we obtain this:

1   2158
2   755
3   291
4   96
5   42
6   9
7   3 *
8   3 *
9   2 *
10   0
11   0
12   0
13   0
14   0
15   0
16   0
17   0
18   0
19   0
20   0
   3359 results

8 groups 6>, instead of "only" 6 with 2 doz - 2 col. !!!

Well as we obtain the double quantity of (+1) signs than (-2) if we choose to play the series we obtain this:
(2 doz > 2 col)

1   1180
2   778
3   508
4   301 <<<
5   225
6   149
7   105
8   45
9   39
10   13
11   11
12   10
13   5
14   3
15   2
16   1
17   0
18   1
19   0
20   0

Imagine that you want to play the series after 4 (+) signs:
We shall obtained this:

4   301   -2   -602 (we lose -2, [the 5th])
5   225   -1   -225 (we lose -2, [the 6th]; we win 1[the 5th])
6   149   0   0 (we lose -2, [the 7th];we win 2 [the 5th]+[the 6th])
7   105   1   105 (we lose -2, [the 8th] we win 3 [the 5th]+[the 6th]+[the 7th])
8   45   2   90 (.....)
9   39   3   117
10   13   4   52
11   11   5   55
12   10   6   60
13   5   7   35
14   3   8   24
15   2   9   18
16   1   10   10
17   0   11   0
18   1   12   12
19   0   13   0
20   0   14   0

For a total of : -249 units.
Try starting in any step.  :(

Thanks for your patience.

Betatester.

PS: One last advice for all those that says that the systems runs playing one last dozen, one last column:

1   1068
2   707
3   464
4   296
5   232
6   148
7   101
8   65
9   48 <<< here you touches at the 10th step
10   31
11   17
12   13
13   11
14   4
15   3
16   3
17   2
18   2
19   0
20   1
21   0
22   0
23   1
24   0
25   0
26   0
27   0
28   0
29   0
30   0

   3217 results

88 runs > than 10 steps...!!! (in the same number of spins)

fqbien

Wow, really lost in the  system ..

What means all your numbers ?

Ex: 1   2225 <<< I publish here another figure)
      2   767
      3   253
      4   91
      ...

Thanks for taking the time to answer.

bikemotorman

Sorry for the delay it seems my method is no better then any other method of playing 24 numbers.
I am sorry I thought it was better then other then other methods of play.
I am sorry I was wrong.
I apologize to the forum.

Stuart Brandt

Jish

Quote from: bikemotorman on February 05, 2010, 06:48:14 AM
Sorry for the delay it seems my method is no better then any other method of playing 24 numbers.
I am sorry I thought it was better then other then other methods of play.
I am sorry I was wrong.
I apologize to the forum.

Stuart Brandt
Depends if you are using RNG or real spins in your testing, Ive found out that RNG has ALOT longer streaks than any real wheel, i finally foud the difference;)

fqbien

Alaways in winnings ..

Now 50€, starting with 7€.

Betting all spins, last column, then last dozen.

Just a few spins, then i stop and play later.

Thinks it will fail, but i will stay in profit, because progression max cost me 23,10€.

I'm playing on RNG wheel.

fqbien

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