repeating nrs, question

[foreverBOB]

I was just wondering what the longest run of non repeating nrs would be, based on an average.
We all know that it is unlikely that all 38 nrs will appear without repeating.
I thought I read somewhere that the average would be around 22 nrs, so in these 22 nr run, there would be a repeat.
Based on this idea, we could use a progression plan like this :
So we place bets on the last nr that shows. If that nr doesnt hit, we repeat last bet + add the nr nr and so on.
For example: first nr is 5, bet 5, next nr is 22, bet 5 and 22, next nr is 3, bet 5,22 and 3, ......

1 bet 1unit
2 bet 1unit
3 bet 1unit
4 bet 1unit
5 bet 1unit
6 bet 1unit
7 bet 1 unit
8 bet 2 units
9 bet 2 units
10 bet 3 units
11 bet 4 units
12 bet 6 units
13 bet 10 units
14 bet 16 units

Now if we assume that within 22 spins a nr will repeat, would it be ok to use a progression plan untill the 22th spin?
Just wondering....

[synax.one]

if you can decrease bets, it can be useful, i played this sometimes. . . .

numbers count: 1: bankroll: -1 bet1: 1
numbers count: 2: bankroll: -3 bet1: 1
numbers count: 3: bankroll: -6 bet1: 1
numbers count: 4: bankroll: -10 bet1: 1
numbers count: 5: bankroll: -15 bet1: 1
numbers count: 6: bankroll: -21 bet1: 1
numbers count: 7: bankroll: -28 bet1: 1
numbers count: 8: bankroll: -36 bet1: 1
numbers count: 9: bankroll: -54 bet1: 2
numbers count: 10: bankroll: -74 bet1: 2
numbers count: 11: bankroll: -107 bet1: 3
numbers count: 12: bankroll: -167 bet1: 5
numbers count: 13: bankroll: -258 bet1: 7
numbers count: 14: bankroll: -426 bet1: 12
numbers count: 15: bankroll: -726 bet1: 20
numbers count: 16: bankroll: -1286 bet1: 35
numbers count: 17: bankroll: -2391 bet1: 65
numbers count: 18: bankroll: -4659 bet1: 126
numbers count: 19: bankroll: -9580 bet1: 259
numbers count: 20: bankroll: -20860 bet1: 564
numbers count: 21: bankroll: -48244 bet1: 1304
numbers count: 22: bankroll: -119018 bet1: 3217
numbers count: 23: bankroll: -314564 bet1: 8502
numbers count: 24: bankroll: -895316 bet1: 24198
numbers count: 25: bankroll: -2760566 bet1: 74610
numbers count: 26: bankroll: -9285552 bet1: 250961
numbers count: 27: bankroll: -34356564 bet1: 928556
numbers count: 28: bankroll: -141243652 bet1: 3817396
numbers count: 29: bankroll: -653251905 bet1: 17655457
numbers count: 30: bankroll: 842064361 bet1: 93321701

[bella]

4ever bob
what is the max numbers you can track/bet   on and still stay in profit     and how much do you bet on each ?

good idea if you can work the bugs out

[birdhands]

Simon has been working on a repeating system like this, only for flat-betting.  I've found the first repeat is usually around spins 10 or 11; 22 is a pretty long time to wait.  I would say to wait for 10 numbers without a repeat and then start your progression.

Sam

[foreverBOB]

Indeed Bella, Birdhands, that was actualy my question. I play it unitll 14, and most of the times I have a win, but if you lose on the 14th you are down with -563 units.
Knowing the winnings arent big either, I am not sure if this idea can be worked out.
I am sure someone already thought about this....


best regards,
Bob

[schoenpoetser]

The best start with wagering is after a fictive lost and run after a hit!

[foreverBOB]

What if instead of using a dangerous progression we would rather wait for more wins to occure.
For example, betting 1 unit:
On the 8th spin, it would give you a breakeven situation.
A first win after the 8th spin, would recover but not all.
So continue placing bets, lets say untill 13 or 14 nrs max and try to win 3 times within that 14 nr strip.
If no win, restart game but doubling up.

Untill now, it looks profitable.

I use 1-2-5-10 progression. And very rare I go up to 10 unit bets.
Never lost that fourth progression step yet.

Im playing on rng at the moment, I know rng repeat nrs more oftenly than live, so Im eager to test it live asap.




Best regards to all,

Bob

[schoenpoetser]

20 Times no repeat is the same as 20 Red or Black.  A row of 20 events happens on average 2^20=1048576 spins.
On account the zero it is less.Now you can wait on 10 no repeats and bet Martingale 10 times.You have to wait on a row of 10 no repeats .That happens  once in 1024 spins on average.That can last a very long time.If you understand my SSB principle then you can play this game contious without waiting!!!!

[col1879]

With any strategy/system you always have to factor in the worst case scenario. The problem with betting from the very first spin is that you will get instances where the first 30+ numbers are all unique and you will be waaaaaaay down in losses.

The problem with waiting for X amount of spins is that you have to start off betting on all numbers already spun eg 10, so you do not start off betting 1 chip but ten chips, and even then you can go 20+ bets without a win.

Always imagine the worst case scenario happening because it will happen eventually!

[schoenpoetser]

I don`understand every thing. I agree you have to wait some spins to start a session.I always advice to
wait for a fictive lost before starting to wager. This is been in force for every strategy.The waiting period is betting with 0 units.The benefit of my SSB principle is that the zero unit period is eliminated.After every hit you can start betting without waiting.
My conclusion is you don`t understand SSB or you did not study SSB!!

[foreverBOB]

Schoenpoetser, do you have a link to your ssb method? Because Im not sure I am following here.

Best regards and thanks to reply on this topic.


Bob

[schoenpoetser]

The ShoeShinBoy (SSB) principle is as follows.
1 You do not wager on a single spin but on a  random row
2 The length of the row depends on the risk. In my excelprogram 10 spins for a EC.
3 Make a betting schedule.I did it for Martingale progression
4 Zero is a no-hit but the zero works in the benefit of the player.( European wheel with the En Prison rule)
5 After a hit you wager on a new random row.

The excelprogram finishes allways with a hit.

You can download the program with a English translation

[foreverBOB]

Schoenpoetser,

Thanks you for your reply.
However I am not sure if we are talking about the same priciple.
The system I am working on is based upon inside bets on nrs.
So for example:
if 4 hits, bet 4
if then 7 hits, bet 4 and 7
if then 22 hits, then bet 4,7,22
and so on.

It is very rare that all 38 nrs (I play on American wheel only) will appear in 38 consequtive spins.
This is the mainidea. Off course, If we would have and endless BR and there would be no table limits, then it will win always unless all 38 nrs appear in 38 consequtive spins.

Considering this, I am working on the idea to bet repeating nrs without using a progression after the 8th nr. Max betting 14 nrs.

Your ssb method is based upon outside betting using a dangerous martingale progression. You actualy copy the last 10 outcomes and play them. It looks a bit like the antiphase but then without reversing.

How many spins did you test this idea on, Schoenpoetser? I saw you statistics, and it looks working out well. In my opinion, if it passes 15000 spins with a good ptofit margin, then it is working.

Please report back,




best regards,
Bob

[schoenpoetser]

My SSB model for ECs is on the first place a study model.The risk of a bust is on average 1024 spins and it happens with a row of 20 ECs .The risk is very small.It is not necessary to proof it with a 150k sample.With every touch F 9 you become a new sample of 150 spins.In a very short time you can get the results of 15k or more.Try it!!
I use the principle in  my strategy. 

[foreverBOB]

Ok Schoenpoetser,

thanks for your input, but we are clear then that the ssb method has nothing to do with this topic, right?

Will try you ssb method and report back to you.


Best regards,
Bob

[foreverBOB]

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