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Poor attempt number two

Started by col1879, January 14, 2011, 12:31:12 PM

0 Members and 1 Guest are viewing this topic.

col1879

Since there is not much success with number one, would get as much success with a red/black bet, here is number two lol

Apparently, when 10 spins occur, 70 per cent of the time you get at least one repeater and 30 per cent of the time they are all unique.  Now you cannot cover all nine numbers over nine spins to see if the tenth spin produces a repeater or a unique without being in a negative.  eg you have to place 45 bets for a 36 return.

However, if you generate 5 spins and all the numbers are unique, then you choose just three of the numbers and bet on them the next five spins, you would only have placed 15 units in search of a 31 to 21 profit return.  Although it is not a 70 to 30 split because you are not covering all nine numbers, do you not have better odds of success than if you were to choose one number at random out of 0 to 36?

I cannot quite get my head around it or work out what the actual percentages are, but I know luck is still a factor.  As it always is with gambling.  I will keep doing manual testing in fun play but if someone can help clear up the statistics for me and tell me the true percentages then that would be great.  And if anyone tries the 'poor attempt number two' system at a casino then you try it at your own risk.  I am not liable for any losses lol

darrynf

the higher your first spins are the higher your percentage will be in getting a repeat.

so in afect if you lower your first spins then you are lowering your percentage for a repeating number to happen.

if you spin 10 spins and you have 9 numbers to bet on then you can easily a make progression to go far as 10 steps, more often then not you will get a repeat but for when you dont  then you have to make the choice to keep your progression going if the table max alows it.

after the first spin the numbers will often change as you have to keep tracking the numbers, you cant keep the original numbers as new ones come in, for each new number that hits will now be apart of that 10 spin cycle .
and to keep it even you have to take out numbers that can possibly new numbers for the 10 spins. this method works extramly well, i think most people dont change the numbers and thats where they lose.

darrynf

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