John Gold's Blog.

[John Gold]

ok Dennis, so I put the numbers that you gave me into the chart and it comes out like this....



So the 4, 7 and 12 streets are all missing at this point.

I am not quite sure what you are asking about! (are you talking about the full street method or the variation?)

[attachthumb=#]

p.s. I corrected my mistake.

[dennisbelle]

The full street method.

[dennisbelle]

The 19 should be a 9.

[John Gold]

Here is the MARKING TEMPLATE + BETTING CHART.

MARKING TEMPLATE+BETTING CHART.

1-1 = 1,12.
1-2 = 1,2.
1-3 = 2,3,4.
1-4 = 3,4,6.
1-5 = 4,5,8.
1-6 = 5,6,10.
1-7 = 6,7,11.
1-8 = 7,8,9.
1-9 = 7,8,9.
1-10 = 5,9,10.
1-11 = 3,10,11.
1-12 = 1,11,12.

2-1 = 1,10,11.
2-2 = 2,12.
2-3 = 1,2,3.
2-4 = 2,4.
2-5 = 3,5,6.
2-6 = 4,6,8.
2-7 = 5,7,9.
2-8 = 6,7,8.
2-9 = 5,7,9.
2-10 = 3,8,10.
2-11 = 1,9,11.
2-12 = 10,11,12.

3-1 = 1,8,10.
3-2 = 2,10,11.
3-3 = 3,12.
3-4 = 1,2,4.
3-5 = 2,4,5.
3-6 = 3,6.
3-7 = 4,7.
3-8 = 5,8.
3-9 = 3,6,9.
3-10 = 1,7,10.
3-11 = 8,11.
3-12 = 9,12.

4-1 = 1,6,9.
4-2 = 2,8,10.
4-3 = 3,10,11.
4-4 = 4,12.
4-5 = 1,2,5.
4-6 = 2,4,6.
4-7 = 3,5,7.
4-8 = 3,4,8.
4-9 = 1,5,9.
4-10 = 6,10,11.
4-11 = 7,9,11.
4-12 = 7,8,12.

5-1 = 1,4,8.
5-2 = 2,6,9.
5-3 = 3,8,10.
5-4 = 4,10,11.
5-5 = 5,12.
5-6 = 1,2,6.
5-7 = 2,3,7.
5-8 = 1,3,8.
5-9 = 4,9,11.
5-10 = 5,9,10.
5-11 = 6,7,11.
5-12 = 5,7,12.

6-1 = 1,2,7.
6-2 = 2,4,8.
6-3 = 3,6,9.
6-4 = 4,8,10.
6-5 = 5,10,11.
6-6 = 6,12.
6-7 = 1,7.
6-8 = 2,8,11.
6-9 = 3,9.
6-10 = 4,7,10.
6-11 = 5,11.
6-12 = 3,6,12.

7-1 = 1,6.
7-2 = 2,3,7.
7-3 = 3,5,8.
7-4 = 4,7,9.
7-5 = 5,9,10.
7-6 = 6,11.
7-7 = 7,12.
7-8 = 1,8,10.
7-9 = 2,8,9.
7-10 = 3,6,10.
7-11 = 4,11.
7-12 = 2,5,12.

8-1 = 1,3,5.
8-2 = 2,5,6.
8-3 = 3,7.
8-4 = 4,8,9.
8-5 = 5,9,11.
8-6 = 1,6,10.
8-7 = 2,7,11.
8-8 = 8,12.
8-9 = 1,9,10.
8-10 = 2,8,10.
8-11 = 3,6,11.
8-12 = 4,12.

9-1 = 1,4,5.
9-2 = 2,5,7.
9-3 = 3,6,9.
9-4 = 4,7,11.
9-5 = 1,5,8.
9-6 = 3,6,9.
9-7 = 4,7,10.
9-8 = 2,8,11.
9-9 = 9,12.
9-10 = 1,10.
9-11 = 2,8,11.
9-12 = 3,6,12.

10-1 = 1,3,7.
10-2 = 2,4,9.
10-3 = 3,5,11.
10-4 = 1,4,6.
10-5 = 3,5,7.
10-6 = 5,6,8.
10-7 = 6,7,9.
10-8 = 4,8,10.
10-9 = 2,9,11.
10-10 = 10,12.
10-11 = 1,10,11.
10-12 = 2,8,12.

11-1 = 1,2,9.
11-2 = 2,3,11.
11-3 = 1,3,4.
11-4 = 3,4,5.
11-5 = 5,6.
11-6 = 6,7.
11-7 = 7,8.
11-8 = 6,8,9.
11-9 = 4,9,10.
11-10 = 2,10,11.
11-11 = 11,12.
11-12 = 1,10,12.

12-1 = 1,11.
12-2 = 1,2.
12-3 = 3.
12-4 = 4,5.
12-5 = 5,7.
12-6 = 6,9.
12-7 = 7,10.
12-8 = 8.
12-9 = 6,9.
12-10 = 4,10.
12-11 = 2,11.
12-12 = 12.

So you could just play for the 4, 7 and 12 to remain missing if you wanted to. That would be betting streets 1, 3,5,10,11. (only 5 streets to bet) This would be a bit of a risky bet in my opinion. Playing for 2 missing streets is a much safer option.

How did I arrive at the bet on the 1,3,5,10,11 streets?

The current missing streets are 4, 7 and 12. The current number out is 6 belonging to street 2.

Go to the 2-1 through to the 2-12 and look for all combinations WITHOUT a 4, 7 and 12 in them.

You should come out with the 1,3,5,10,11 streets. This would then be your bet if you were looking for the 4, 7 and 12 streets to still be absent on the next spin.

[John Gold]

For the full street version.

13 = 5.
--
9 = 3. (10)
22 = 8. (5,8)
32 = 11. (3,6,11)
2 = 1. (9) 4/7/12. LOSS.
6 = 2. (1,2) 4/7/12.

Ok, this would be the markings so far for the full street method. We got to the stage where the 4/7/12 were the 3 missing streets. (I personally would not have bet anything here because I use the groups WW = 1. WL = 2. LL = 3. LW = 4  to give me some idea of what is actually happening) I wait for the first missing group before deciding what to do.

Dennis, you can never have just 8 numbers in the brackets. There should always be 9 and then there will be 3 missing streets.

[John Gold]

Here is an explanation Dennis,

13 = 5.
--

Then you would go.

13 = 5.
9 = 3. (3,8,10)

Then you would go.

13 = 5.
9 = 3. (3,8,10)
22 = 8. (5,8)  So now you would erase the earlier 8 leaving you with the following.....

13 = 5.
9 = 3. (3,10)
22 = 8. (5,8)

Now you would go.

13 = 5.
9 = 3. (3,10)
22 = 8. (5,8)
32 = 11. (3,6,11) So now you would erase the earlier 3 leaving you with the following....

13 = 5.
9 = 3. (10)
22 = 8. (5,8)
32 = 11. (3,6,11)

Now you would go.

13 = 5.
9 = 3. (10)
22 = 8. (5,8)
32 = 11. (3,6,11)
2 = 1. (1,2,9)  4/7/12. So these are your three missing streets. (the 4, 7 and 12)

Now you would go.

13 = 5.
9 = 3. (10)
22 = 8. (5,8)
32 = 11. (3,6,11)
2 = 1. (1,2,9)  4/7/12.
6 = 2. (1,2) 4/7/12.  So the 4/7/12 are still the three missing streets and you need to erase the previous 1 and 2 street in the brackets leaving you with the following....

13 = 5.
9 = 3. (10)
22 = 8. (5,8)
32 = 11. (3,6,11)
2 = 1. (9)  4/7/12. LOSS.
6 = 2. (1,2) 4/7/12.

I hope that clears things up. 

[dennisbelle]

John,
   Yes that clears thing up, I see my error now!  Thanks for the explanation.

[John Gold]

Looking at different variations is interesting.

The full street method leaves 9 streets in the bracketed section and then has 3 sleeping streets.

Taking it down to 2 sleeping streets and leaving 10 streets in the bracketed section is another option.

[attachthumb=#]


[attachthumb=#]


Marking the way I do means the current sleeping streets have already slept for quite a while throughout all three columns. Playing for just one of the 2 to appear is a cheaper way of doing it than looking for 3. Using the '4 group' methodology may be a way to catch some streaks for minimal outlay. Just a very quick test saw 5 out of 6 winning bets. Obviously the '3' group (LOSS/LOSS) would be the killer. It may pay its way if it was only attacked when the  '3' group was the missing group. The chip outlay here seems to be an average of 5 chips looking for one of 2 sleepers to appear compared to an average of 7 chips  looking for one of the 3 sleepers to appear. It is always another option.

An interesting option would be a 2 player team running 2 seperate games looking for the best opportunities. Kind of like a 'Parrondo's Paradox' situation. 

[John Gold]

So just to take the last 2 pics to their conclusion...

2 = 1.
--
10 = 4.
7 = 3.
16 = 6.
12 = 4.
31 = 11.
5 = 2.
12 = 4.
26 = 9.  6/12. WON.
27 = 9.  6/8. WON.  (GROUP 1)
35 = 12.  8/10. WON.
22 = 8.  7/10. LOSS. (GROUP 2)
2 = 1.  7/10. WON.
28 = 10.  7/11. WON. (GROUP 1)
7 = 3.  2/7. LOSS.
34 = 12.  2/7. LOSS. (GROUP 3)  (MISSING GROUP 4)
17 = 6. (9) 2/7. WON.
4 = 2.  1/7. LOSS. (GROUP 2)
10 = 4.  1/7. LOSS.
30 = 10.  1/7. LOSS. (GROUP 3)
24 = 8.  1/7. LOSS.
32 = 11. (6,11) 1/7. LOSS. (GROUP 3)
12 = 4. (4,5) 1/7. LOSS.
6 = 2. (8,10) 1/7. WON. (GROUP 4)  (MISSING GROUP 1)
9 = 3. (1,2,3) 7/12.

[attachthumb=#]

You can see the 7 street has went completely AWOL. The 1/7 (and 12) streets went missing for ages.

The first 6 bets produced 5 out of 6 wins betting for the one of the missing 2 streets to appear.

The next 11 bets produced 2 out of 11 wins. This is why I like to use the '4 group methodology' It can certainly point a player in the right direction.

cheers.

[John Gold]

Just ended my session today at betvoyager for a + 14 unit profit.

I will put up an explanation for it all later.

session 1. + 8 units.
session 2. + 29 units. (+ 37)
session 3. +14 units. ( +51)

28 = 10.
--
1 = 1.
3 = 1.
27 = 9.
15 = 5.
13 = 5.
26 = 9.  2/6/10. LOSS.
2 = 1.  2/6/10. WON. (GROUP 4)
9 = 3.  6/7/10. WON.
26 = 9.  7/8/10. WON. (GROUP 1)
19 = 7.  8/11/12. WON.
19 = 7.  1/8/11. WON. (GROUP 1)  
16 = 6.  1/5/8. LOSS.
17 = 6.  1/5/8. WON. (GROUP 4)
15 = 5.  1/2/8. LOSS.
25 = 9.  1/2/8. LOSS. (GROUP 3)  (MISSING GROUP 2)
36 = 12.  1/2/8. LOSS. (BET 3,4,5,6,7,9,10,12) +4. (+4)
9 = 3.  1/2/8. LOSS. (GROUP 3) (NO BET)
8 = 3.  1/2/8. WON. (BET 3,6,7,9,12) -5. (-1)
12 = 4.  5/7/8. LOSS. (GROUP 2)  (MISSING GROUP 1) (NO BET)
30 = 10.  5/7/8. WON. (NO BET)
19 = 7.  3/5/8. LOSS. (GROUP 2) (BET 1,4,6,7,11) +7. (+6)
19 = 7. (12) 3/5/8. WON. (NO BET)
26 = 9. (9) 1/3/5. LOSS. (GROUP 2) (BET 4,7,8,9,11) +7. (+13)
32 = 11. (8} 1/3/5. WON. (NO BET)
6 = 2. (3,11) 1/4/5. WON. (GROUP 1)  (MISSING GROUP 4) (BET 2,8,10,12) -4. (+9)
11 = 4. (4) 1/5/10. WON. (BET 1,2,3,5,7,9,10) +5. (+14)
13 = 5. (1,2,5) 6/7/10.

[John Gold]

So on to the explanation of the game I played today...

The 1 and 4 groups were hitting early and I was wondering if they were going to go on a long run before the first missing group appeared. This happens at times and it's frustrating but I always think patience pays off in the long run!

So eventually the 2 group became the first missing group.

group 2 = WIN/LOSS  (The opposite = LOSS/WIN)

So with no group 2, I am looking to bet either a LOSS in the first result of the pair or a WIN in the second result of the pair (or both for that matter)

I like to look at the previous few results to see what's streaking. If I am looking for a LOSS in the first result of a pair and can see that the WIN has come up 2 consecutive times previously, I don't think it's a great time to be playing for the LOSS.

The LOSS had come up previously on the first result of the last pair and seeing as that's what I wanted, I had a bet.
So a good start and winning 4 units. No bet on the next spin because I was looking for a WIN and the previous result in the last pair for the second decision was a LOSS. I don't like playing against what's coming up.

So I am looking for a LOSS on the first result of the next pair and unfortunately it's a win. Lost 5 units taking me to -1.

I am still not playing for the WIN in the second result of the pair because I see the LOSS is building up a head of steam now.

The good news is there is a new missing group which happens to be the 1 group.
The 1 group = WIN/WIN. It's opposite is LOSS/LOSS. So if the 1 group stays missing, I can make a few units on some of the LOSS bets. These require less outlay as well.

You can see that I hit 2/3 playing for the LOSS on the second result of subsequent pairs before the missing 1 group finally appears.

The new missing group is the 4 group.

The 4 group = LOSS/WIN. It's opposite is WIN/LOSS. Now looking at the previous four pairs indicates there was a WIN in the first result of the pair 4 times. This is as strong an indicator as you are going to get I suppose. So it's a WIN bet on the first result of the pair and up she pops. I decide to quit here with my 14 pieces of silver and call up the local takeaway for a curry. 

I can never remember playing a game with this where at some point or another a good trend does not come along and make a few units profit. It's important not to second guess yourself and just look out for the strongest bet and play it. Like I always say, It only costs one bet to find out and who knows how long that run could carry on for. There are losses but that is a loss of one bet. Don't chase losing streaks looking for corrections. Look for the next strongest bet to appear. 

[John Gold]

These pictures are just to give you a rough idea of 2 games being played side by side.

Game 1 is playing with the three missing streets.

Game 2 is playing with the two missing streets.

[attachthumb=#]


[attachthumb=#]


The groups in game 1 come out as 4, 3, 1, 2, 1. Two missing groups appear in that time making the game a bit choppy.

The groups in game 2 come out as 3, 4, 1, 4, 1. Only one missing group appears in this game and the stable 1 and 4 give some winning betting opportunities. The WIN appears 4 times out of 5 on the last result of the pair.

You would need a partner for playing this way in a B+M casino. It is a not a bad idea. I play several methods requiring a partner which tracks several games at the same time and looks for the prime betting opportunities.

[John Gold]

I keep checking on ebay for old gambling books just to add to my collection.

I managed to get hold of a book by Roy Ward Dickson this morning called 'How to win at roulette and blackjack'

I have searched for it for years and it pops up now and then but is always too expensive.  I was surprised when I saw it available for only £6 including the postage. I am pretty certain his 'hot number' theory has being tested to death and does not hold up in the long run but his blackjack strategy should be a good read.

Not to leave the girlfriend out......

[attachthumb=#]

I hope she likes it. 

[insidebet]

Jonh,
I don't know if i'm thicker than the rest but I reaaly don't understand a few things.

I tried to read and comprehend post #28.  You give a selection of 9 different #s if I remember well.  You give the corresponding data for each number.  Fine. Then you say something like :''you see that 1 is present in every bracket''.  Well we see this AFTER the numbers are spun.  You then say ''we will bet on all 1s''.  You give all the bets from the third spin on.  On the third spin, we don't know that 1 is going to be in the bracket for the next little while.  We know this in HINDSIGHT, not before.

What is the trigger for the first bet?

Also, you said in one of your first post that anytime you are in positive territory, the game is finished and you start a new one.  In the example you give in post #28, you keep betting even if you are winning from the start.

Thanks.

Insider

[insidebet]

Oh yes!  Is what reply #16 accurate?  If it is, it simplifies things quite a bit...

Insider

[insidebet]

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