John Gold's Blog.

[John Gold]

So the missing streets are now 2 5 and 6. For the next bet, looking at the marking template+betting chart, go to where the 3-1 through to the 3-12 are. Look for all the combinations that have a 2 5 and 6 in them.

You should find the following.

3-2.
3-4.
3-5.
3-6.
3-8.
3-9.

So there are 6 streets to bet. 2,4,5,6,8,9.

The next number out is 13 and belongs to street 5. (that was another win of 6 units taking the profit up to + 17)

[attach=#]

Your paper after completing all the markings and ready for the next bet will look like the following.


2
--
9
1
7
2 8/10/12.
5  8/10/12.
2  8/10/12.
1 (11) 4/8/12.
8 (7,8,9) 3/4/12.
12 (12) 2/3/5.
3 (3) 2/5/6.
5 (2,4,5) 1/6/10. *Here you have got rid of the earlier 4 street in the bracketed numbers because you can't have repeats. If there is a repeat, always get rid of the furthest one back. Also the TWO missing streets 2 and 5 appeared. So this still would have left you with 11 streets in the bracketed numbers. You need to get rid of the furthest TWO back which are the 1 and the 10. This leaves you with your new 3 longest sleeping streets which are 1 6 and 10.

[John Gold]

So the missing streets are now 1 6 and 10. For the next bet, looking at the marking template+betting chart, go to where the 5-1 through to the 5-12 are. Look for all the combinations that have a 1 6 and 10 in them.

You should find the following.

5-1.
5-2.
5-3.
5-4.
5-6.
5-8.
5-10.
5-11.

So there are 8 streets to bet here. 1,2,3,4,6,8,10,11.

The next number out is 29 belonging to street 10. (that was a win of 4 units taking the total to +21)

[attach=#]

Your paper after completing all the markings and ready for the next bet should look like the following.



2
--
9
1
7
2 8/10/12.
5  8/10/12.
2  8/10/12.
1  4/8/12.
8 (7) 3/4/12.
12 (12) 2/3/5.
3 (3) 2/5/6.
5 (2,4,5) 1/6/10.
10 (8,9,10) 1/6/11. *So you would have got rid of the repeat 8 and 9. The missing street 10 appeared, so you would have also got rid of the furthest back street which was the 11. This now leaves you with the three longest sleeper streets 1 6 and 11.

[John Gold]

So the missing streets are now the 1 6 and 11. For the next bet, looking at the marking template+betting chart, go to where the 10-1 through to the 10-12 are. Look for all the combinations that have a 1 6 and 11 in them.

You should find the following.

10-1.
10-3.
10-4.
10-6.
10-7.
10-9.
10-11.

So there are 7 streets to bet here. 1,3,4,6,7,9,11.

The next number out is 21 belonging to street 7. (that was a win of 5 units taking the total to + 26)

[attach=#]

Your paper after completing the markings and ready for the next bet should look like the following.


2
--
9
1
7
2 8/10/12.
5  8/10/12.
2  8/10/12.
1  4/8/12.
8  3/4/12.
12  2/3/5.
3 (3) 2/5/6.
5 (2,4,5) 1/6/10.
10 (8,10) 1/6/11.
7 (6,7,9) 1/11/12. *So here you would first of all have got rid of the furthest back 7 and 9 so as not to have any repeats. The missing street 6 appeared. So you would have also got rid of the furthest back street which was the 12 leaving you with the three longest sleeper streets of 1 11 and 12.

I think anybody following should be getting the hang of it by now. That concluded the 8 spin winning streak.

Feel free to ask any questions on anything you are not sure about regarding the tracking. It is pretty straightforward once you get the hang of it. All you really need to remember is that you can't have any repeats in the numbers in brackets. You always take away the furthest back repeat/s.

On a loss, you will still have the same 3 sleeper streets missing.

On a win, you will need to remove the furthest back street/s depending on how many sleeping streets appeared.
If one appeared, you take away the furthest back street. If two appeared, you take away the furthest back two streets. If three appeared, you take away the furthest back three streets.

To work out your bets, use the marking template+betting chart. You always work from the last street that appeared to work out the bet. For example: If the three sleeping streets are 1 9 and 10 and the last number out was 17 which belongs to street 6. Go to the 6-1 through to the 6-12 and look for all the combinations that have a 1 9 and 10 in them. You will be betting between 6-8 streets when you have a bet. Very seldom there will be 5 to bet.

I think it works well because of my unique '3 column approach' The sleepers have to continue sleeping throughout all three columns for the bet to keep losing. This tends not to happen because by the time I arrive at the three sleeping streets, they have already slept for a good few spins. Please don't just take my word for it. Do your own testing and you will find out for yourself.

[John Gold]

In my next few posts, I am going to go into a very detailed analysis of how to take maximum advantage using the method I have described above. It can make all the difference between treading water and winning a high proportion of your sessions.

I am 100% convinced that TIMING is the real secret to winning at roulette. To take advantage of timing requires only two things in my book. PATIENCE + DISCIPLINE. In fact, without them, you can't really win long term whatever  method you are playing.

Having a good method along with the patience and discipline to recognize when to bet and when to back off can put you more or less on a level playing field with the casino. The casino know this only too well.

If you have played roulette for a while, you will notice the subtle moves the croupiers pull to break a players gameplan. You have to be in control of your game at ALL times. Anything less than that is not good enough for anybody who has ambitions to keep one step ahead.

[John Gold]

Hello again.

As I said in my last post, I really think timing is the key element for staying on top in the game of roulette.

I would like to share a few concepts, explain them and then look at practical ways to use them for the method that I have talked about over the last few days.

First of all I would like to show you 4 different pairs of results. (The W counts as a win and the L counts as a loss)



1) WW.
2) WL.
3) LL.
4) LW.
If you take any pair of results, it has to land in one of the above 4 groups. There is no other alternative. So any one of the above 4 groups has a 1/4 chance of appearing = 25%. (of course this applies if you are betting the even chances)
Now think about this, on a roulette layout, there are three dozens and we all know from experience that one of these dozens can go missing for a long time now and again. In fact sometimes up to 20 spins. A dozen represents a 33.33% chance. Now considering my 4 groups above have a 25% chance of appearing, is it therefore not logical to assume that one of these 25% chances could go missing for an equally long absence or even greater absence than one of the dozens. I can conclude by using probability alone that this is more than likely to happen on occasion and one of these 25% chances could go missing for 20+ appearances.


Here are a range of numbers between 1-4 that I downloaded from random.org.



3   2   4   4   1   3   1   1
2   1   2   4   2   1   3   3
1   4   3   4   4   4   3   4
3   3   4   4   4   1   3   3
4   1   1   4   4   2   4   4
4   1   4   3   2   2   4   4

I will now convert them into the following.

1. WW.
2. WL.
3. LL.
4. LW.


LL, WL, LW, LW, WW, LL, WW, WW.
WL, WW, WL, LW, WL, WW, LL, LL.
WW, LW, LL, LW, LW, LW, LL, LW.
LL, LL, LW, LW, LW, WW, LL, LL.
LW, WW, WW, LW, LW, WL, LW, LW.
LW, WW, LW, LL, WL, WL, LW, LW.

So looking at these, I want to see if I can find some long absences for any one of the 4 different groups.
1) LL=3.
2) WL=2.
3) LW=4. (1 MISSING)
4) LW=4. (1 MISSING)
5) WW=1. (3 MISSING)
6) LL=3. (2 MISSING)
7) WW=1. (2 MISSING)
8} WW=1. (2 MISSING)
9) WL=2. (4 MISSING)
10) WW=1. (4 MISSING)
11) WL=2. (4 MISSING)
12) LW=4. (3 MISSING)
13) WL=2. (3 MISSING)
14) WW=1. (3 MISSING)
15) LL=3. (4 MISSING)
16) LL=3. (4 MISSING)
17) WW=1. (4 MISSING)
18} LW=4. (2 MISSING)
19) LL=3. (2 MISSING)
20) LW=4. (2 MISSING)
21) LW=4. (2 MISSING)
22) LW=4. (2 MISSING)
23) LL=3. (2 MISSING)
24) LW=4. (2 MISSING)
25) LL=3. (2 MISSING)
26) LL=3. (2 MISSING)
27) LW=4. (2 MISSING)
28} LW=4. (2 MISSING)
29) LW=4. (2 MISSING)
30) WW=1. (2 MISSING)
31) LL=3. (2 MISSING)
32) LL=3. (2 MISSING)
33) LW=4. (2 MISSING)
34) WW=1. (2 MISSING)
35) WW=1. (2 MISSING)
36) LW=4. (2 MISSING)
37) LW=4. (2 MISSING)
38} WL=2. (3 MISSING)
39) LW=4. (3 MISSING)
40) LW=4. (3 MISSING)
41) LW=4. (3 MISSING)
42) WW=1. (3 MISSING)
43) LW=4. (3 MISSING)
44) LL=3. (2 MISSING)
45) WL=2. (1 MISSING)
46) WL=2. (1 MISSING)
47) LW=4. (1 MISSING)
48} LW=4. (1 MISSING)

[John Gold]

If you go down to number 18 in the groups I posted in the previous post, you will come to a LW. Now the furthest back group from here is a 2 which consists of WL. That 2 group dissapears without a sniff for a further 20 appearances. What does this mean and how can it help us? If the 2 is absent (WL) this means you can only get one of the following, WW, LL, LW. So looking at that, you are more than likely to catch a L at the beginning of the next pair and catch a W at the end of the next pair. So let's check and see what happens on these next 20 pairs without an appearance of the 2.
The L comes up at the beginning of a pair16 times out of 20.   It is also worth noting that out of them 16, 11 of those were in a continuous streak. This kind of information can save you a LOT of losses. This is where timing is so important in the game of roulette.

The method I have shared is betting between 6 and 8 streets and therefore you will not get as many losses as playing solely the even chances. On saying that, the losses do sometimes have a tendency to group together and you need to be aware of it. I like to record my results in pairs excactly like I have described above.

1) WW.
2) WL.
3) LL.
4) LW.

If you are getting a combination of pairs 2 3 and 4 appearing and the 1 is the furthest back. You are certainly going to be experiencing your fair share of losses. It is also likely that either the first or second result in each pair is turning into a bit of a nightmare scenario. I would suggest that depending on your comfort zone, you stop betting either after the first or second loss in this situation and wait for a win to appear or alternatively, you could keep a running score and if the win percentage drops below 50%, wait till it rises again. In other words, treat each result in the pair of results independent from the other. They will have their own characteristics and it pays to monitor them with close scrutiny.

On the brighter side, you may be getting a combination of pairs 1 2 and 4 appearing and the 3 is the furthest back.
This happens often because of the extra coverage at times where you are covering either 7 or 8 streets. When this happens, you get some great long win streaks. You don't really have to do anything here except keep placing them bets. 

[John Gold]

So I will finish with another quick example.

10
–
3 (3,5,11)  *remember on your piece of paper to write 1-12 at the top. Cross out the 3 5 and 11.

9 (3,6,9) * cross out the furthest back 3 street and take away the 6+9 on your 1-12 list.

11 (2,8,11) * cross out the furthest back 11 street and take away the 2+8 on your 1-12 list.

6 (6,7) * cross out the furthest back 6 street and take away the 7 on your 1-12 list.

12 (3,6,12) * cross out the furthest back 3 and 6 street and take away the 12 on your 1-12 list.

This should now leave you in a position to start betting if you wish.

Your actual piece of paper will look like the following.

10
–
3 (5)

9 (9)

11 (2,8,11)

6 (7)

12 (3,6,12)  1/4/10 are the missing 3 streets.

Using the marking template+betting chart and going to the 12-1 through to the 12-12, look for all the combinations with a 1 4 or 10 in them.

12-1.
12-2.
12-4.
12-7.
12-10.

So I need to back streets 1,2,4,7,10.

Number 11 appeared belonging to street 4. (a winner of 7 units)

10
–
3 (5)

9 (9)

11 (2,8,11)

6 (7)

12 (3,6,12)  1/4/10

4 (4,5) * So I take away the furthest back 5 street because I can't have any repeats and because one of the three sleeping streets appeared, I also take away the furthest back street which is the 9.

This now leaves the three sleeping streets as the 1 9 and 10.


How I prefer to play it is to chart for a few spins even after the first betting opportunity just to get an idea of what's happening. I monitor the results in pairs like I said earlier and look for the strong winning trends and hop on board. Obviously I avoid anything that is not showing positive results and wait for it to change. It always does change. There is always a period where them sleeping streets hit a winning run. There are many times when you can hit a nice profit of 20-30 units in less than an hour. Sometimes I have to be a bit more patient.

Well, I wish anybody luck who decides to give this a go.

cheers.

[John Gold]

I will show another example which will give you a clearer idea regarding the 'pairs' theory I described above.

2
–
4 (2,4)
2 (2,8,10)  I will just leave in all the markings in this example.
4 (2,4)
7 (3,5,7)
8 (1,8,10)
5 (5,9,11) 2/6/12. WIN.
6 (1,2,6) 3/4/12. WIN.
12 (3,6,12) 4/7/8. WIN.
10 (4,10) 5/7/8. WIN.
6 (5,6,8}7/9/11. LOSS.
4 (4,8,10) 7/9/11. WIN.
1 (1,6,9) 2/7/11. LOSS.
10 (5,9,10) 2/7/11. WIN.
11 (1,10,11) 2/3/7. LOSS.
12 (1,10,12) 2/3/7. WIN.
3 (3) 2/4/7.

So breaking the WINS and LOSSES into pairs as I suggested leaves the following.

W
W

W
W

L
W

L
W

L
W

So looking at that, you can see that the last result in the pair produced 5 straight wins however on the 3rd, 4th and 5th pair, the first result in the pair produced three consecutive losses. I have seen instances where the first or second result in the pair can produce strings of either 10+ wins or losses.
You need to be aware of this. It's not just a case of what you win but also what you can do your best to avoid losing.

[John Gold]

Here is another example where I have included the correct markings.

2
–
5
7
9
7  1/11/12. LOSS.
5 (10) 1/11/12.  WIN.
11  1/2/12.  WIN.
11  1/2/3.  LOSS.
11 (12) 1/2/3.  LOSS.
6 (6) 1/2/3.  WIN.
7 (7) 2/3/8.  LOSS.
11 (4,11) 2/3/8.  WIN.
1 (1,2,9) 3/5/8.

This is what I would describe as choppy. Because you will notice the following.

L
W

W
L

L
W

L
W

When the pairs are alternating between LW and WL, I wait for it to break up. It can sometimes take a while to break as well. Patience is the key here. In the example above, it did break up with the end pair repeating the previous and I would be looking for a possible 'win streak' on the last result of the forthcoming pairs.

Remember you can put the WINS and LOSSES into groups.

WW = 1.
WL = 2.
LL = 3.
LW = 4.

If the furthest back group is 1, you may be in for combinations of 2 and 4 which can be choppy.

Ideally, you really want to be playing when the furthest back group is the 3. Then you will see some nice win streaks.

[John Gold]

5
–
10
8
8
7  1/3/6.  WIN.
6  1/3/5.  LOSS.
4  1/3/5.  WIN.
7  1/9/12.  LOSS.
11  1/9/12.  LOSS.
5  1/9/12.  WIN.
5 (5) 1/2/9.  WIN.
2 (2,6) 1/810.  WIN.
11 (9,11) 3/8/10.  WIN.
12 (1,10,12) 3/7/8.  WIN.
8 (8} 3/4/7.

There is a little tip that I can share with you here guys. Things went pretty cool in this session except for one brief period where there was 2 losses in a row.

Pay particular attention to what the three sleeping streets were at the time. (1,9,12)

Now anybody that has read all the pages on the blog and is still familiar with the sixline method I wrote about before this one will remember how the (6) sixline could go missing for ages because of the '3 column approach' that I employ. Well, the same applies with this method, only this time, it is the (12) street that can go missing for absolute ages with this.

How does knowing this information help? If I am playing the three sleeping streets (1,9,12) I will be relying a lot of the time on just the 1 and 9 showing because the 12 can go missing.

It is worth looking out for. Some of you may think the losing streaks are not so tough with this and using a progression may be the order of the day. If you do that and you hit a few losses and notice the three sleeping streets have a (12) in them, stop betting and wait for the three sleeping streets not to have a (12) in the combination.

[John Gold]

Just to show what I mean. Here is the final screenshot I uploaded when explaining the rules of the system.
You can see there is only one X in the 12 column which represents street 12. It can go missing for 20+ spins quite regularly. It does not always hinder the method. There are times when you will keep on winning regardless if the (12) street is in the sleeping combination. However I would be weary of it if using any type of progression.

[attach=#]

[John Gold]

6
–
4
4
7
5
3
4  6/11/12.  LOSS.
2  6/11/12.  LOSS.
9  6/11/12.  WON.
4  3/6/12.  WON.
3  1/6/12.  LOSS.
11 (11) 1/6/12.  WON.
6 (7) 1/2/12.  LOSS.
9 (9) 1/2/12.  WON.
5  2/4/12.  LOSS.
8 (1,3,8}2/4/12.  WON.
2 (2,5,6) 4/10/12.

Here is an interesting example from a session I played online this morning.

The missing 12 street came up in the first batch of three sleeping streets. It stayed in the three sleeping streets for 12 spins.

The WIN and LOSS pattern were as follows.

L
L

W
W

L
W

L
W

L
W

So looking at the 4 groups again.

1 = WW.

2 = WL.

3 = LL.

4 = LW.

The first three groups are LL (3) WW (1) LW (4) That means the furthest back group would be the WL (2).
So if the 2 group continues to sleep, you are going to get groups 1, 3 or 4 appearing. These are represented by WW, LL, LW. So it it is fair to assume that you will more than likely see a L as the first result in each pair and a W as the second result in each pair.

The next two groups out were as follows.

L
W

L
W

You would have caught the two WINS if you were following this.

[John Gold]

9
–
5
12
1
12
11
4  6/9/10.  WON.
2  6/7/9.  LOSS.
2  6/7/9.  LOSS.
4  6/7/9.  WON.
11  1/3/6.  LOSS.
7  1/3/6.  WON.
8  3/5/6.  LOSS.
9  3/5/6. LOSS.
4  3/5/6.  WON.
1 (9) 3/5/12.  WON.
12 (12) 2/3/5.  LOSS.
7 (7) 2/3/5.  LOSS.
8 (8} 2,3,5.  LOSS.
6 (1,6,10) 2,3,5.  WON.
11 (5,11) 2/3/4.

Here is another example worth looking at.

The groups are as follows.

W
L (GROUP 2)

L
W (GROUP 4)

L
W (GROUP 4)

L
L (GROUP 3) So now the group 1 (WW) is the furthest back. In this case, I would stop playing. Looking at previous results indicates this could be one of those times when you are about to witness a disaster, lol.

W
W (GROUP 1) So the group 1 appeared and now leaves the 2 as the furthest back group. So if the 2 group continues to be absent, it is more than likely that a LOSS will be present in the first result of the next pair and a WIN will be present in the second result of the next pair.

L
L So I lost this bet here if I decided to play.

L
W I would have won here if I decided to play. Interestingly, the expected LOSS appeared both times on the first result of the pairs.

Now you may think that all that tracking and marking and putting things in pairs is a waste of time and brain power, All I can say is that it works for me. I do it because I don't play with a huge bankroll and therefore need to try and protect myself from losing runs that can wipe me out. Doing it this way allows me to flat bet and win a very high percentage of my sessions. The casino can't take what you don't give them a chance to take. It also means that if you hit a bad patch, the winnings are not going back after a few bad sessions..

If you have the time and patience to wait for group 3 (LL) to be the furthest back group, you are then more than likely to get a WIN in the first result of the pair and a WIN in the second result of the pair. I had a 'win streak' this morning of 11 consecutive wins. That will bankroll the next few sessions. Think of the hare and the tortoise. It is not a race.

[John Gold]

6
–
5
12
6
9
6

1  4/8/10.  LOSS.
12  4/8/10.  WON.  (GROUP 4)

4  3/8/10.  LOSS.
4  3/8/10.  WON.  (GROUP 4)

8  6/9/10.  LOSS.
1  6/9/10.  WON.  (GROUP 4)

7  2/9/10.  LOSS.
6  2/9/10.  LOSS.  (GROUP 3)

6  2/9/10.  WON.
10  2/8/9.  LOSS.  (GROUP 2)  THE MISSING GROUP IS 1 WHICH IS THE SIGNAL FOR NO PLAY BECAUSE IF THE 1 GROUP CONTINUES TO BE MISSING, IT IS MORE THAN LIKELY THAT YOU WILL GET A (L) IN THE FIRST RESULT OF EACH PAIR AND ALSO MORE THAN LIKELY THAT YOU WILL GET AN (L) IN THE SECOND RESULT OF EACH PAIR.

3 (5) 2/8/9.  LOSS.
6 (3,6) 2/8/9.  LOSS. (GROUP 3)  IT SOMETIMES AMAZES ME HOW ACCURATE THE PREDICTIONS CAN BE!

10 (4,7) 2/8/9.  LOSS.
11 (11) 2/8/9.  LOSS.  (GROUP 3) SO THE LAST 4 PAIRS HAVE RESULTED IN GROUPS 3, 2, 3 AND 3 APPEARING. 7 LOSSES OUT OF 8. ANYONE PLAYING STRAIGHT THROUGH WOULD HAVE SUFFERED A BIT HERE.
THIS IS WHERE PEOPLE WHO RUN MILLION SPIN SIMULATORS FOR TESTING CAN'T SEE THE WOOD FOR THE TREES IN MY OPINION. I HAVE SEEN CHARTS WHERE THE DOWNTURNS CAN BE SHOCKING. THE TRUTH IS YOU DON'T HAVE TO PLAY THEM ALL THE WAY TO THE END.
THESE RESULTS ALSO SHOW THAT YOU USE PROGRESSIONS AT YOUR OWN RISK.
CERTAINLY IF YOU PLAY A NEGATIVE PROGRESSION ON EVERY SPIN AFTER A LOSS.
YOU CAN BE VERY SELECTIVE WITH PROGRESSIONS AND THEY MAY FARE SLIGHTLY BETTER PROVIDING YOU HAVE A SENSIBLE STOP LOSS IN PLACE.

12 (1,10,12) 2/8/9.

This was a session I played early this evening. I never made a bet in anger.

[John Gold]

11
–
6
7
11
10

3  8/9/12.  WON.
3  6/8/9.  LOSS.  (GROUP 2)

2  6/8/9.  WON.
7  1/6/8.  WON. (GROUP 1)

8  3/4/6.  WON.
1  4/6/12.  WON.  (GROUP 1)

6  2/4/12.  LOSS.
3  2/4/12.  WON.  (GROUP 4)  The missing group is 3 which is as good as it can possibly get.

4  7/11/12.  LOSS.
1  7/11/12.  WON.  (GROUP 4)

12  5/7/8.  LOSS.
11 (11) 5/7/8.  WON.  (GROUP 4)

6  5/8/10.  LOSS.
3 (9) 5/8/10.  WON.  (GROUP 4)

10 (7,10) 4/5/8.  WON.
4 (1,6) 5/8/12.  WON.  (GROUP 1)

8 (3,4,8} 2/5/12.

This is an example of things going ok. The 3 was the missing group. So it was more than likely to see a (W) in the first result of each pair and a (W) in the second result of each pair.

You will notice however that when the group 3 qualified as the furthest back, group 4 appeared and the first result in that pair was a loss. Bearing this in mind, I was hesitant to back for a (W) in the  first result of subsequent pairs. At the very least, I was going to monitor the situation. Backing the (W) in the second result of subsequent pairs was a foregone conclusion bearing in mind the last result of the previous 3 pairs all resulted in a (W).
As you can see, it was a wise choice not to back the (W) in the first result of the pairs over the next three sets. The (W) in the second result of the pairs produced 4 consecutive wins and took its tally to 7 consecutive W's. This made a little profit and I quit the session after having a rough day on the betting exchanges. All is well that ends well.

[John Gold]

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