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John Gold's Blog.

Started by John Gold, January 27, 2011, 05:15:03 PM

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John Gold

  19 (starter number)

01} 10    15    28
02} 30    34    20
03} 02    28    09
04} 17    02    15
05} 28    24    11
06} 12    01    21
07} 35    01*  23     (the * signals a repeat)
08} 03    01*  05
09} 00    02*  34     (the 00 represents 0, I am just trying to keep things tidy)
10} 20    24*  20*
11} 22    04    02
12} 25    16    03
13} 01    16*  13
14} 02*  20    01
15} 12*  27    10
16} 15    06    03*
17} 18    27*  03*
18} 21    13    03*
19} 32    33    11*
20} 01*  22    06
21} 02*  20*  01*
22} 21*  36    19
23} 02*  01*  18
24} 08    10    06*
25} 24    04*  16
26} 16    01*  29
27} 18*  08    02*
28} 33    30    15*
29} 13    27*  17
30} 12*  21    36
31} 02*  10*  27
32} 05    13*  03*
33} 35*  15*  30
34} 35*  00    00
35} 27    14    29*
36} 10*  07    20*
37} 05*  01*  32

So after the first 37 spins, there are 24 original numbers and 13 sleepers in the first column.

There are 22 original numbers and 15 sleepers in the second column.

There are 25 original numbers and 12 sleepers in the third column.

John Gold

So now what I am going to do is add in the next number and take the very first one away.

I only operate with the 37 spins.

02} 30    34    20
03} 02    28    09
04} 17    02    15
05} 28    24    11
06} 12    01    21
07} 35    01*  23     (the * signals a repeat)
08} 03    01*  05
09} 00    02*  34     (the 00 represents 0, I am just trying to keep things tidy)
10} 20    24*  20*
11} 22    04    02
12} 25    16    03
13} 01    16*  13
14} 02*  20    01
15} 12*  27    10
16} 15    06    03*
17} 18    27*  03*
18} 21    13    03*
19} 32    33    11*
20} 01*  22    06
21} 02*  20*  01*
22} 21*  36    19
23} 02*  01*  18
24} 08    10    06*
25} 24    04*  16
26} 16    01*  29
27} 18*  08    02*
28} 33    30    15*
29} 13    27*  17
30} 12*  21    36
31} 02*  10*  27
32} 05    13*  03*
33} 35*  15*  30
34} 35*  00    00
35} 27    14    29*
36} 10*  07    20*
37} 05*  01*  32
38} 28*  13*  23*

So now after 37 spins, there are 23 original numbers and 14 sleepers in the first column.

There are 21 original numbers and 16 sleepers in the second column.

There are 24 original numbers and 13 sleepers in the third column.

So the sleepers in each column have all jumped up by 1.

John Gold

Again I will add the next number and take the first one away.

03} 02    28    09
04} 17    02    15
05} 28    24    11
06} 12    01    21
07} 35    01*  23     (the * signals a repeat)
08} 03    01*  05
09} 00    02*  34     (the 00 represents 0, I am just trying to keep things tidy)
10} 20    24*  20*
11} 22    04    02
12} 25    16    03
13} 01    16*  13
14} 02*  20    01
15} 12*  27    10
16} 15    06    03*
17} 18    27*  03*
18} 21    13    03*
19} 32    33    11*
20} 01*  22    06
21} 02*  20*  01*
22} 21*  36    19
23} 02*  01*  18
24} 08    10    06*
25} 24    04*  16
26} 16    01*  29
27} 18*  08    02*
28} 33    30    15*
29} 13    27*  17
30} 12*  21    36
31} 02*  10*  27
32} 05    13*  03*
33} 35*  15*  30
34} 35*  00    00
35} 27    14    29*
36} 10*  07    20*
37} 05*  01*  32
38} 28*  13*  23*
39} 00*  05    09*

So now after 37 spins, there are only 22 original numbers and 15 sleepers in the first column. (notice the original numbers have decreased by 2 and the sleepers have increased by 2 in this column)

There are 21 original numbers and 16 sleepers in the second column.

There are 23 original numbers and 14 sleepers in the third column. (notice the original numbers have decreased by 2 and the sleepers have increased by 2 in this column)

Davemd

Im with you so far John.

John Gold

Again I will add the next number and take the first one away.

04} 17    02    15
05} 28    24    11
06} 12    01    21
07} 35    01*  23     (the * signals a repeat)
08} 03    01*  05
09} 00    02*  34     (the 00 represents 0, I am just trying to keep things tidy)
10} 20    24*  20*
11} 22    04    02
12} 25    16    03
13} 01    16*  13
14} 02*  20    01
15} 12*  27    10
16} 15    06    03*
17} 18    27*  03*
18} 21    13    03*
19} 32    33    11*
20} 01*  22    06
21} 02*  20*  01*
22} 21*  36    19
23} 02*  01*  18
24} 08    10    06*
25} 24    04*  16
26} 16    01*  29
27} 18*  08    02*
28} 33    30    15*
29} 13    27*  17
30} 12*  21    36
31} 02*  10*  27
32} 05    13*  03*
33} 35*  15*  30
34} 35*  00    00
35} 27    14    29*
36} 10*  07    20*
37} 05*  01*  32
38} 28*  13*  23*
39} 00*  05    09*
40} 18*  29    18*

There are now 21 original numbers and 16 sleepers in the first column. (now the original numbers have decreased by 3 and the sleepers have increased by 3 in this column)

There are 21 original numbers and 16 sleepers in the second column.

There are 22 original numbers and 15 sleepers in the third column. (now the original numbers have decreased by 3 and the sleepers have increased by 3 in this column)

so as you can see, the 'rule of the third' is decreasing all the time over the 3 columns.

There are another 5 spins to go before I will get into a detailed explanation about the 3 columns and how to bet with them.

I will complete the rest of this tomorrow night.

cheers.

John Gold

sorry about the delay. I had a nasty trojan attack on sat**day night after checking out a few different roulette sites.
(stay away from russian roulette forums  ;D) I have lost a fair bit of work that I had on my pc. Luckily I have everything written down, so it will take a few days for me to get things back in order again.

I did have a few things on one of my usb memory sticks which I can show you in the meantime. This one is for even chance betting.

I will show you a snapshot and then explain things a little. Some of you may like it.

[attach=#]

John Gold

This even chance method works on a similar principle to my 'sleeping streets' method which uses the groups ( 1-4 )

It also works in pairs as you can see by the snapshot.

The groups are as follows.

RED/RED = GROUP 1.  RED/BLACK = GROUP 2. BLACK/BLACK = GROUP 3. BLACK/RED = GROUP 4.

EVEN/EVEN = GROUP 1. EVEN/ODD = GROUP 2. ODD/ODD = GROUP 3. ODD/EVEN = GROUP 4.

LOW/LOW = GROUP 1. LOW/HIGH = GROUP 2. HIGH/HIGH = GROUP 3. HIGH/LOW = GROUP 4.

So I will use the second column in the snapshot which concentrates on the ODD and EVENS to give you an idea of what's going on.

The first three groups out are the 3, 4 and 2. This leaves the 1 as the furthest back group. (In fact it has not appeared yet but I still count it as the furthest back group)

So the 1 is the furthest back group and it consists of EVEN/EVEN.

If the 1 group continues to be absent, I will see either a group 2, 3 or 4.

These groups contain the following.

EVEN/ODD.
ODD/ODD.
ODD/EVEN.

So looking at them three choices, you can see that an ODD has to appear in either the first or second result of the pair.

The next two pairs produced ODD/EVEN (group 4) and ODD/EVEN (group 4). Following the odd, you would have had two wins on the first result of each pair.

The next group that came out was group 1. This was the furthest back group. So now the furthest back group is group 3.

If the 3 group continues to be absent, I will see either a group 1, 2 or 4.

These groups contain the following.

EVEN/EVEN.
EVEN/ODD.
ODD/EVEN.

So looking at them three choices, you can see that EVEN has to appear in either ther first or second result of the pair.

The next 5 pairs produced EVEN/EVEN (group 1), EVEN/EVEN (group 1), EVEN/ODD (group 2).
EVEN/EVEN (group 1), EVEN/ODD (group 2). The first 5 results in each pair werre EVEN.

So plenty of opportunities for winning bets. Getting the wins in the first result of each pair can work out great because you may decide to go for the win in the first result of the pair and not bother betting for the second result.
If you lose the first result, you can try and recoup the loss on the second result.

There are so many possibilities that you can try regarding MM with this. The bottom line is to follow the strongest trend.

It may be that the furthest back group keeps appearing on every pair for one of the even chances and is the strongest trend. If this is the case, you simply bet for that to happen. If the 3 is the furthest back group, you would bet ODD/ODD if you fancied it to appear. I have seen the furthest back group appear 7 times on the trot once for one of the even chances. Other times I have seen the furthest back group not appear for 27 pairs.

This is another method which requires you to be looking for what is happening on a continual basis. It is not fixed.
This is how you can regularly win in my opinion. Anything fixed is bound to come across its nemesis at some point in time. When that happens, say goodbye to your bankroll if you are not careful. Of course you can still have losing sessions with this method as well. However you are definately more in control and you are the one making the choices and not relying on some fixed method which has no flexibility to adapt to what is currently happening at the table.

John Gold


[attach=#]

Here is a situation where the furthest back group keeps repeating in the LOW and HIGH column.

The 3, 4 and 1 group appear. This leaves the 2 as the furthest back group. The 2 group then appears.

Then the 3 is the furthest back group. The 3 group then appears.

Then the 4 group is the furthest back group. The 4 group then appears.

You can bet for these furthest back groups to appear when they hitting consecutively like this. You could just go for the first hit or catch the second one as well.

By playing all the three even chances using this method, I normally find that something is streaking either way. (furthest back group not hitting or furthest back group hitting) Then it is just a case of how you want to attack it. I have had some good fun using positive progressions with this. I normally like to get up a few units and see that my luck is in before I try anything fancy.

John Gold

When I want to do some speed testing, I just download some numbers from random.org which is no different to bet voyager's RNG really.  I can then test it against different MM plans.

Here was a quick sample I just downloaded.

4
2
4
2
3 (1)
3
3
4
3
2
4
4
4
4
1 (3) The group 1 slept for 9 pairs.
2
1
4
1
2
2
1
1
4
4
3 (2)  The group 3 slept for 10 pairs.
3
2 (1)  The group 2 slept for 1 pair.
1 (4)  The group 1 slept for 0 pairs.
1
1
3
3
3
4 (2)  The group 4 slept for 5 pairs.
2 (1)  The group 2 slept for 0 pairs.
3
3
2
2
4
1 (3)  The group 1 slept for 5 pairs.
2
2
2
3 (4)  The group 3 slept for 3 pairs.
2
2
1
2
4 (3)  The group 4 slept for 4 pairs.

As you can see in this sample, the furthest back groups are hitting in a spread out fashion for the majority of the time. This tends to happen for the most part and then you get clusters where they hit quickly. You can take advantage of both of these trends.

John Gold

Here is another quick example.

2
3
2
4 (1)
3
2
4
3
1 (2)  The group 1 slept for 4 pairs.
2 (4)  The group 2 slept for 0 pairs.
4 (3)  The group 4 slept for 0 pairs.
1
2
1
2
2
3 (4)  The group 3 slept for 5 pairs.
2
2
3
3
2
3
1
1
2
1
4 (3)  The group 4 slept for 10 pairs.
4
1
2
2
1
1
3 (4)  The group 3 slept for 6 pairs.

One way to attack the furthest back groups hitting pretty close together would be to use a parlay bet.
So you would start with one unit and you would then let that bet ride should it win. This will return you 4 units for your 1 unit stake if you complete the parlay.

John Gold

One idea that I can't get out of my head for this is the 'star progression'. (I am sure if I go and rest in a dark room for 20 minutes, the urge will pass  :D )

All my testing for these groups over several years have shown them to never go past 27 groups without the furthest back hitting. So I wondered what if I wait for the furthest back to be absent for 8 groups and then use the star progression. Of course it is classic gamblers fallacy but I have tested this a lot and I reckon I would be miles in front.

The star progression is an up as you lose parlay progression. You put down one unit and on a win you let the bet ride. So you are looking to gain three units for your one unit stake. You go up to the next level on a loss. You go back to the beginning or quit once you hit a winning parlay.

I don't know how it would fare with these groups. If you lost on the very first bet, you would miss out on the next spin just to complete the group. (The original star method does not work with groups and was devised for blackjack)

I managed to get a 19 step star progression for 489 units. (you get change from 500 if it goes pear shaped  :whistle:)

Here are the steps down the devils staircase  :diablo: (I thought I would throw that line in for our satanic followers)

1) bet 1. win 4. +3/-1.
2) bet 1. win 4. +2/-2.
3) bet 1. win 4. +1/-3.
4) bet 2. win 8. +3/-5.
5) bet 2. win 8. +1/-7.
6) bet 3. win 12. +2/-10.
7) bet 4. win 16. +2/-14.
8} bet 5. win 20. +1/-19.
9) bet 7. win 28. +2/-26.
10) bet 9. win 36. +1/-35.
11) bet 12. win 48. +1/-47.
12) bet 16. win 64. +1/-63.
13) bet 22. win 88. +3/-85.
14) bet 29. win 116. +2/-114.
15) bet 39. win 156. +3/-153.
16) bet 52. win 208. +3/-205.
17) bet 69. win 276. +2/-274.
18) bet 92. win 368. +2/-366.
19) bet 123. win 492. +3/-489.

The average win is 2 units and I would suggest playing it on all even chances to provide more betting opportunities.

I will call this variation 'the lazy man's way to riches' You don't have to do any thinking with this one! Just wait
for the trigger and have some fun.

p.s. don't shoot the messenger.  :give_rose:

John Gold

The waiting time alone would make 'the lazy mans way to riches' pretty unplayable unless you tracked all three e/c opportunities.

4
1
2 (3)
4
3 (1) group 3 slept 1.
4
2
3
4
1 (2) group 1 slept 4.
1
3
4
3
4
3
1
2 (4) group 2 slept 7.
2
3
2
2
1
1
2
2
2
1
4 (3) group 4 slept 10.

It took 30 spins just to win one bet in this example. So you are only going to get maybe 10 or so bets in 300 spins to win an average of 20 units. You would definately need to play all three even chances to maximize the potential.  Also because of the table limits, you could not start with big sized chips or you would not be able to fit in the full progression.

It would be the grinder of all grinders for sure.  ;D

John Gold

The urge got the better of me today and I decided to go play 'the lazy mans way to riches' in one of my local casinos.

I did chicken out a bit and play for low stakes on the autowheel. The wheel spins every 45 seconds. I just wanted to experiment with the idea. So I concentrated on the LOW and HIGH.

I waited for the furthest back to qualify and then waited for it to sleep a further 3 pairs before betting using the 19 step star progression.

Here is what that would like. The bet comes up on the first group in this instance.

[attach=#]



It was a slow grind over a few hours but I managed to win enough to cover the expenses and buy a few drinks with enough left over to buy dinner tonight. Sure beats losing any day of the week.

I run a test last night of over 15000 spins and it did not break. It might be one of them that steadily climbs to the point where you get a few bankrolls ahead before a losing string hits. The problem will be if the losing string hits early. It was great fun however. Even a method anorak needs a bit of excitement now and again.  ;)


John Gold

I will point out that the original STAR progression was put through Dr Wilson's acid test and it passed all three times.

My version is a crude one, lol. The original was designed more or less for blackjack and has a  5 step pre-qualifying component to it as well.

It's worth checking out for all you progression junkies out there. Maybe you can fiddle about with it a bit to suit your own methods.

cheers

John Gold

here you go guys!   :thumbsup:

Don't take this as the definitive word on MM. Take what you need from it and move on.

p.s. There is no copyright on this. So it should be fine.



John Gold

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