I want calculate the number of series in X spins...

[synax.one]

Hi,

how can i calculate or give me formula to solve number of series in about 250,000 spins. Red and Black series.
So much thanks. Synax.one, Bye. I hope you will answer

[LuckoftheIrish]

Hi,

how can I calculate or give me formula to solve number of series in about 250,000 spins. Red and Black series.
So much thanks. Synax.one, Bye. I hope you will answer

Assuming no zero, this should be the approximate distribution:

Runs of 1          62500
Runs of 2          31250
Runs of 3          15625
Runs of 4           7813
Runs of 5           3907
Runs of 6           1954
Runs of 7           977
Runs of 8           489
Runs of 9           245
Runs of 10   123
Runs of 11   62
Runs of 12   31
Runs of 13   16
Runs of 14   8
Runs of 15   4
Runs of 16   2
Runs of 17   1


I just ran 250 000 RNG numbers with no zero and got this:

Runs of 1          62497
Runs of 2          30876
Runs of 3          15656
Runs of 4           7843
Runs of 5           3921
Runs of 6           1890
Runs of 7           1011
Runs of 8            555
Runs of 9            265
Runs of 10   118
Runs of 11   56
Runs of 12   37
Runs of 13   17
Runs of 14   4
Runs of 15   2
Runs of 16   0
Runs of 17   1

Keep in mind, in a true 50/50 game you always have a 50% chance to be ahead, even after a billion spins!

[guido1]

Hi,

how can I calculate or give me formula to solve number of series in about 250,000 spins.  Red and Black series.
So much thanks.  Synax. one, Bye.  I hope you will answer

Check out this webpage.

nolinks. pulcinientertainment. com/info/Streak-Calculator-enter. html#ev-runs

Even has an Excel worksheet for download

[synax.one]

thank you for distribution i know what i have to do with this. SYNAX. Easy to code.

[schoenpoetser]

A  random row of 10  will fall on average once in 1024 spins .With 250 000 spins you can expect 250 000/1024=244 times.
I think there is a mistake in the computing of luckof the irish.The results are 2x to low.

A random row of 4 spins occurs once in 16 spins .250000/16= 15625. L.O.I gives 7813

[LuckoftheIrish]

A  random row of 10  will fall on average once in 1024 spins .With 250 000 spins you can expect 250 000/1024=244 times.
I think there is a mistake in the computing of luckof the irish.The results are 2x to low.

A random row of 4 spins occurs once in 16 spins .250000/16= 15625. L.O.I gives 7813

I wrote to Imspirit, and he wrote back:

"Your numbers are right.  He is also right.

The confusion exists in the phrases "number of events" and "probability of repeats."

You were counting the number of events in a sample, while he was referring to the probability of repeats-in-a-row.

In 250,000 spins, 1/2 will be opposites and 1/2 will be repeats.

So, in 250,000 spins there are 125,000 events.

1/2 are 1s: 62,500
1/4 are 2s: 31,250
1/8 are 3s: 15,625
... etc ...

But at the same time, it is true that the probability is 1/2 that you will get a 1s (62,500/125,000), and 1/2*1/2=1/4 of getting a 2s (31,250/125,000), and (1/2)^10=1/1024 of getting a 10s (122/125,000), etc."

[LuckoftheIrish]

Going back to my older post:

I just ran 250 000 RNG numbers with no zero and got this:

Runs of 1          62497
Runs of 2          30876
Runs of 3          15656
Runs of 4           7843
Runs of 5           3921
Runs of 6           1890
Runs of 7           1011
Runs of 8            555
Runs of 9            265
Runs of 10   .......118
Runs of 11   ........56
Runs of 12   ........37
Runs of 13   ........17
Runs of 14   .........4
Runs of 15   .........2
Runs of 16   .........0
Runs of 17   .........1

If you multiply the run length by how many times it occurred and add it all together ((1*62497)+(2*30876)+(3*15656)etc) you will get 250 000 exactly.

[LuckoftheIrish]

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