A Gem

[Conway Clemency]

Previously, known as, "Norman Bates" Conway Clemency will carry the torch from now on, and throughout modern history as we know it... 

"A GEM"

"A Gem" is the same type of a compensation strategy that you all may, or may not remember from threads written in the past.  For those whom may remember these strategies the concept is the same.  For those who have not had a chance to understand the concept of a compensation strategy, I will try to explain its inner workings for you now at this time.
Basically, if you add up the number of chips that effect each one of the columns, or dozens, (Counting both the inside , and outside bets that effect each location.) you would then add up the number of chips that effect each column or dozen individually, you should come up with the same amount of chips wagered in each one.  Description as follows...
Count all of the chips in that column or dozen including the outside bets that affect the column, or dozen, (Which in this case will add up to 36 units of 4.)  Here's how you do it.   "Count the 24 chips bet on numbers 4, and 6, and the 12 chips bet on number 8, and 11.  Include the 24 chips bet on the first dozen, the 1st column, and the 3rd column." All of these bets affect the 1st dozen.   
Do the same with each column or dozen you will find that there are 36 units of 4 affecting each one of them.  So, now when you first add up the total number of chips that affect the first half of the layout, (Especially numbers 4, 6, 8, 11, 17, 18, 19, 20, and 21) and then include the outside bets that affect the first half of the layout, (Those bets being the 24 chips bet on the 1st dozen, column 1, and column 3.) it will amount to a total of 48 units of 4.  Notice both of these figures, (36 chips, and 48 chips.) are both divisible by 4 which is important!
Then, the 36 units for the columns and dozens, and the 48 units of 4 that affect the first half of the layout gives you the answer as to how much to bet on the 0's.  48 are to be divided by three making 16 additional chips to be placed on top of the 12 chips already on numbers 17, and 20.  So,  16 chips at a time on top of the twelve chips already wagered on numbers 17, and 20 for a total of 28 chips on numbers 17, and 20, and 16 chips wagered on the 0 for European Roulette.  For American roulette the numbers will remain the same, 16 chips on each of the 0's, and 28 chips on both numbers 17, and 20.  I can't remember how I came up with this figure, but it seems to work.
What's different now as compared to before?  This strategy that is listed here is easy to assemble, and place your bets on the layout, and because there are generally a comparable number of chips bet on the outside locations, (As opposed to the inside bets.)  it allows the inside bets to take some hits causing it to be a little more resilient than some of the previous strategies of this type.   Also, in each case of American, and European Roulette even though you've wagered 24 chips on numbers 4, 6, 31,  and 33 as compared to 28 chips bet on numbers 17, and 20 the payoff for all of these numbers will be precisely the same when that number  lands even though the amount of chips wagered on each number is different.  This strategy was not conceived using Roulette Xtreme software.  Try Bicycle Casino software. 
Here's a breakdown of how you should bet with each spin:

12 chips on numbers 8, and 29.
16 chips on the 0's in all cases...
24 chips on the first dozen, 3rd dozen, 1st column, the 3rd column, numbers 4, 6, 31, 33, 11/14 split, 16/19 split, 18/21 split, and 23/26 split.
28 chips on numbers 17, and 20.
400 chips for each spin. 384 for European Roulette...

Fantasy land here we come.

[Mr J]

I dont know what to say......thanks(?)

Ken

[Mr J]

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