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How to find a consistent bet the Enrique way.

Started by enrique malou, December 03, 2008, 07:27:24 PM

0 Members and 3 Guests are viewing this topic.

djroulette

ok i have worked out how to find out what numbers and letters to put down after each spin i am just unsure as to what numbers to erase.

Here is an example

13 - 2A
36 - 3C 2B 1A
23 - 2B 2C 1A

From this i noticed dozen 1 was missing from first section and collum A from the second. so i was left with the following numbers 14,15,17,18,20,21,23,24,26,27,29,30,32,33,35,36

now i know this must be wrong but i just cannot figure out what numbers i remove and dont remove.

i will post the next number that came and their groups and if somebody could explain it for me that would be great

25 - 3A 1B 3C

many thanks

dj

TwoCatSam

dj

Don't hold me to this, but I think you have to have something missing from each column.  Otherwise, you have too many numbers.

Sam

JLP

Quote from: djroulette on December 17, 2008, 02:29:33 PM
ok I have worked out how to find out what numbers and letters to put down after each spin I am just unsure as to what numbers to erase.

Here is an example

13 - 2A
36 - 3C 2B 1A
23 - 2B 2C 1A

From this I noticed dozen 1 was missing from first section and collum A from the second. so I was left with the following numbers 14,15,17,18,20,21,23,24,26,27,29,30,32,33,35,36

now I know this must be wrong but I just cannot figure out what numbers I remove and dont remove.

I will post the next number that came and their groups and if somebody could explain it for me that would be great

25 - 3A 1B 3C

many thanks

dj

Hi dj,

13 - 2A
36 - 3C 2B 1A
23 - 2B 2C 1A
With this you have too many numbers - the 3rd column cannot be used, so wait for a new spin number.

13 - 2A
36 - 3C 2B 1A
23 - 2B 2C 1A
25 - 3A 1B 3C
From the 1st column the 1st D is missing (remove those numbers).
From the 2nd. column the 3rd. dozen is missing and A column is missing (remove those numbers).
From the 3rd. column the 2nd. D  and B column is missing (remove those numbers).

Hope this helps.

Cheers,
JLP.-

TwoCatSam

So if we narrow it down........

1.  All three columns must be used.
2.  A 1 (dozen) and a B (column) can both be missing from a column.
3.  The columns and dozens from the wheels are enrique's invention, not as they lay on the table.
4.  You have a bet as soon as at least one item is missing from a column.
5.  You better be a quick mother goose!

Sam

TwoCatSam

Anyone home?

I've been studying this for the past few hours.  I've come to the conclusion no human could do these calculations in time to get down a bet.  Except for the "real" columns and dozens as they lay on the felt, each dozen/column of enrique's is different.  The "A" column depends on which number was last hit and so does the "3" dozen.  By the time you figured it all out, you'd be six spins behind.

I must be missing something.

Sam

TwoCatSam

Anyone left alive?

This is what I understand you would have to do using enrique's example

17
28

You use the wheels to determine the "Red" and "clear" columns and dozens by name only not number.  Then, with the red wheel set on 17, you look for the numbers of the enrique dozen by looking at the "3rd Dozen" in the middle of the little wheel and looking outward.  It starts at 12 and goes to 25.  That gets you your "enrique third dozen". 

To get your "enrique A column, you use the clear wheel with the arrow on 17.  Now the A sections on the outer edge of the inner wheel will give you the "enrique A" numbers.

Sam




Tucktuckster


TwoCatSam

enrique calls the following a section:

1A
2A
3C
2B

In the future I will refrain from calling it a "column" and begin calling it a "section".

Since enrique is not posting on this thread, I assume he wants us to do some brain work ourselves.

Sam

TwoCatSam

[table=,]
Number,Real Dozen,Real Column,Enrique Red Dozen,Enrique Red Column,Enrique Clear Dozen, Enrique Clear Column
17,2,B,1,C,3,C
28,3,A,2,C,1,B
[/table]

It seems to me the elimination process could go into the millions of permutations.  I don't see how it's possible.

I must be missing something.

Sam

TwoCatSam

Another rule I found:

1.  All three columns must be used.
2.  A 1 (dozen) and a B (column) can both be missing from a column.
3.  The columns and dozens from the wheels are enrique's invention, not as they lay on the table.
4.  You have a bet as soon as at least one item is missing from a column.
5.  You cannot have two misses from the same column or dozen.  You can have 1,2 but not 2,2,2.

onezandzeroes

Quote from: TwoCatSam on December 17, 2008, 06:25:41 PM
Anyone home?

I've been studying this for the past few hours.  I've come to the conclusion no human could do these calculations in time to get down a bet.  Except for the "real" columns and dozens as they lay on the felt, each dozen/column of enrique's is different.  The "A" column depends on which number was last hit and so does the "3" dozen.  By the time you figured it all out, you'd be six spins behind.

I must be missing something.

Sam

Isn't that what Enrique is working on, doing all the calculations in advance so you can just flip through a pocket book for each one, ex: 14 to 30, 8 to 19 etc. ?

This is definitely a mind-boggler but if we keep on working on it, new neuro pathways will be formed in the forest of our brains ;)

Even if we can consistently narrow down the field of possibilities to some degree it will be a big winner.

TwoCatSam

onez

I suppose it is.  I don't see how any human in one lifetime could do it.  I can only see it being programmed into a computer.

Sam

TwoCatSam

Here's the way I calculate it.

In each group there are fifteen different eliminations.

1
2
3

A
B
C

1A
1B
1C

2A
2B
2C

3A
3B
3C

Now take 15x15x15 and the equals a whopping....3,375.  That is how many different ways you would eliminate numbers.  Does anyone agree/disagree?

Would some math person look at this?

Sam



Jakkalsdraai

Quote from: TwoCatSam on December 18, 2008, 01:51:04 AM
  Does anyone agree/disagree?

Would some math person look at this?

Sam




hahahahahaha, hey Sam, Herb seems to be on holiday, but I'm sure Ryan will disagree! .....you know the darkside and all.....and Darth Vader..

TwoCatSam

Jakk

I am not good at figuring permutations.  But if I'm right, one would have to flip through over 3000 charts to find the right one.

Sam

TwoCatSam

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